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Example Questions
Example Question #1 : How To Use The Direct Variation Formula
An instrument reads two values, and
daily. The values directly vary with respect to each other. If on Monday the value of
was
and
was
, which of the following could be the values for
and
on Wednesday?
An instrument reads two values, and
daily. The values directly vary with respect to each other. If on Monday the value of
was
and
was
, which of the following could be the values for
and
on Wednesday?
Direct variation means that any pairing of the related values will always have the same ratio, thus we know that for any other values and
, those values will be equal according to the following equation:
Thus, for our information, we know:
This means that the new values of and
, when divided must be equal to
. Therefore, the only possible answer is
Example Question #2 : Direct And Inverse Variation
In an experimental setting, the pressure and the temperature of gas in a container are directly proportional. In the first experiment, the pressure of the gas was and the temperature of the gas was
, where
is a constant value not equal to
. If a second experiment found a temperature of
, which of the following represents the pressure of the gas?
It cannot be determined.
For direct variation of related variables, we know that the following equation holds:
For our data, this would be:
To start simplifying and solving this, first factor the top of the left fraction:
Cancel the s:
Next, multiply by :
Since does not equal
, cancel the
s:
Simplify:
Example Question #1 : How To Use The Direct Variation Formula
In a given solution, the proportion of water to apple juice is directly proportional. If the first batch of the solution contained gallons of apple juice and
gallons of water, how many gallons of apple juice will be needed for a solution containing
gallons of apple juice?
This problem is easily solved by setting up a ratio. For directly proportional amounts, we know:
For our data, this would be:
This is first simplified as being:
Next, multiply by on both sides to solve for
:
Finally:
Example Question #2 : How To Use The Direct Variation Formula
The length, in inches, of a box is . Which of the following gives the length,
inches, in terms of the width,
inches, of the box?
Since the question asks for the length in terms of width, I like to start by setting the problem up as , then add the conditions off the problem. I start at the first condition with
than the width and go ahead and add a
after
, then it say
less than TWICE the width, so I add my
in front of the
. This gives you
, essentially you're working the problem piece by piece.
Example Question #1 : How To Use The Inverse Variation Formula
varies inversely with
. When
,
. What does
equal when
?
1. Use the given values of and
to solve for
:
2. Solve for when
in the above equation:
Example Question #1 : How To Use The Inverse Variation Formula
If , what is the value of
?
To solve this algebraic equation, subtract from both sides, and then subtract
from both sides.
We end up with the equation , for which the solution is:
Example Question #1 : How To Use The Inverse Variation Formula
In a given set of experiments, the values of two variables are always inversely proportional. If in the first experiment the first variable was and the second was
, what could you expect the second variable to be if the first is
in a later experiment?
Recall that inverse variation means that when one variable increases, the other decreases. This gives you the following equation:
Now, for our data, we know:
You merely have to solve for :
Divide by :
Example Question #14 : Variables
Throughout a party, the number of joyful non-philosophers in a room is always inversely proportional to the number of philosophers in the room. The room begins with people,
of whom are philosophers. Later in the day, there are
philosophers in the room. How many joyful non-philosophers are at the party at the later time?
Recall that inverse variation means that when one variable increases, the other decreases. This gives you the following equation:
For our data, this means:
You merely need to solve for :
Example Question #1 : Polynomials
What type of equation is the following?
(y + 2)(y + 4)(y + 1) = z
quadratic
quartic
constant
linear
cubic
cubic
The degree of a polynomial is the highest exponent of the terms.
Degree 0 – constant
Degree 1 – linear
Degree 2 – quadratic
Degree 3 – cubic
Degree 4 – quartic
Multiply out the equation:
(y + 2)(y + 4)(y + 1) = z
(y2 + 2y + 4y + 8)(y + 1) = z
y3 + 2y2 + 4y2 + 8y + y2 + 2y + 4y + 8 = z
The highest exponent is y3;therefore the equation is a degree 3 cubic.
Example Question #1 : Polynomials
Find the degree of the polynomial:
The degree of a polynomial is determined by the term with the highest degree. In this case that is , which has a degree of
.
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