\(\displaystyle 6M\) is \(\displaystyle 28 \frac{4}{7} \%\) of \(\displaystyle 4N\), so

\(\displaystyle 6M = \frac{28\frac{4}{7}}{100} \cdot 4N = \frac{28\frac{4}{7} \cdot 7 \cdot 4}{100 \cdot 7} \cdot N = \frac{800}{700 } N = \frac{8}{7}N\)

\(\displaystyle \frac{8}{7}N = 6M\)

\(\displaystyle \frac{7}{8} \cdot \frac{8}{7}N =\frac{7}{8} \cdot 6M\)

\(\displaystyle N =\frac{21}{4} M = 5.25 M\), or 525% of \(\displaystyle M\).

The number of students who did not vote is:

\(\displaystyle 48-14-12-16=6\)

The percent of students who did not vote is therefore:

\(\displaystyle \frac{6}{48}=\frac{1}{8}=0.125\)

\(\displaystyle 12.5\%\) of the students did not vote.

First, we need to find the fraction of the class that are girls.

\(\displaystyle \frac{5}{5}-\frac{3}{5}=\frac{2}{5}\)

Next, find the number of students that are female. If we know that there are 300 students total, we can write the following ratio for girls:

\(\displaystyle \frac{x}{300}\)

Create a proportion.

\(\displaystyle \frac{x}{300}=\frac{2}{5}\)

Cross multiply and solve for the number of girls, \(\displaystyle x\).

\(\displaystyle \frac{x}{300}\times\frac{2}{5}\)

\(\displaystyle 5\cdot x=2\cdot300\)

\(\displaystyle 5x=600\)

Divide both sides of the equation by 5.

\(\displaystyle \frac{5x}{5}=\frac{600}{5}\)

\(\displaystyle x=120\)

There are 120 girls in the class.

Divide 14 by 100. Simplifying this fraction will give the reduced fractional form of \(\displaystyle 14\%\):

\(\displaystyle \frac{14}{100}= \frac{7}{50}\)

For percentages, remember that the key language is found in the words "is" and "of". "Of" is translated as multiplication, and "is" is translated as equality. Here, we merely need to set up the equation:

\(\displaystyle 0.3 * 0.7 *1=0.21\)

Notice carefully, we use \(\displaystyle 1\) to represent the \(\displaystyle 100\%\) of the class. It really is a filler. \(\displaystyle 0.21\) is the same as \(\displaystyle \frac{21}{100}\). This is the answer.

For percentages, remember that the key language is found in the words "is" and "of". "Of" is translated as multiplication, and "is" is translated as equality. Here, we merely need to set up the equation:

\(\displaystyle 0.5 * 0.3 *1=0.15\)

Notice carefully, we use \(\displaystyle 1\) to represent the \(\displaystyle 100\%\) of the group of peanuts processed anywhere. It really is a filler. \(\displaystyle 0.15\) is the same as \(\displaystyle \frac{15}{100}\). Reduce this by canceling out the common \(\displaystyle 5\): \(\displaystyle \frac{3}{20}\).

To answer this question, we must find the percentage of the amount of seats filled up within the stadium. To find a percentage, there are two steps.

First, you divide the part of the total number by the total number itself (in this case the amount of seats filled divided by the total number of seats). So, for this data:

\(\displaystyle \frac{part}{whole} = \frac{6,732}{13,758} = 0.489\)

The second step is to multiply your answer by 100 so that it will now be represented as a percentage. So for this data:

\(\displaystyle \frac{6,732}{13,758} = 0.489 \cdot 100 = 48.9 %\)

The question asked us to round our answer to the nearest whole percent. To do this, we round a number up one place if the last digit is a 5, 6, 7, 8, or 9, and we round it down if the last digit is a 1, 2, 3, or 4. Therefore:

\(\displaystyle 48.9% \rightarrow 49%\)\(\displaystyle 48.9 \rightarrow 49\)

So our answer for the amount of seats filled within the stadium is \(\displaystyle 49\%\).