ACT Math : How to factor a polynomial

Study concepts, example questions & explanations for ACT Math

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Example Questions

Example Question #11 : How To Factor A Polynomial

Which expression is equivalent to the following polynomial: 

\(\displaystyle x^2-81\)

Possible Answers:

\(\displaystyle (x+80)(x+1)\)

\(\displaystyle x(x-81)\)

\(\displaystyle (x-90)(x+9)\)

\(\displaystyle (x-9)(x+9)\)

\(\displaystyle (x-9)^2\)

Correct answer:

\(\displaystyle (x-9)(x+9)\)

Explanation:

This question calls for us to factor the polynomial into two binomials. Since the first term is \(\displaystyle x^2\) and the last term is a number without a variable, we know that how answer will be of the form \(\displaystyle (x+ a)(x+ b)\) where a and b are positive or negative numbers.

To find a and b we look at the second and third term. Since the second term \(\displaystyle nx\) is not present, we know \(\displaystyle a+b=0\). (The x comes from a and b multiplying by x and then adding with each other).

The \(\displaystyle -81\) term tells us that \(\displaystyle a*b=-81\). Using these two pieces of information we can look at possible values. The third term tells us that  -81 & 1, 81 & -1, and -9 & 9 are the possible pairs. Now we can look and see which one adds up to make 0.

This gives us the pair -9 & 9 and we plug that into the equation as a and b to get our final answer.

\(\displaystyle (x-9)(x+9)\)

Example Question #81 : Polynomials

Factor the following polynomial:

\(\displaystyle x^2 -14x + 33\)

Possible Answers:

\(\displaystyle (x-11)(x+3)\)

\(\displaystyle (x-33)(x+1)\)

\(\displaystyle (x-7)(x+2)\)

\(\displaystyle (x-11)(x-3)\)

\(\displaystyle (x+11)(x-3)\)

Correct answer:

\(\displaystyle (x-11)(x-3)\)

Explanation:

To factor a polynomial of the form \(\displaystyle ax^2 + bx + c\) begin by factoring both \(\displaystyle a\) and \(\displaystyle c\).

Since \(\displaystyle a=1\) we are done.

When you factor \(\displaystyle c\) your two factors need to add together to get \(\displaystyle b\).

Since: 

\(\displaystyle -11*-3 = 33\) and \(\displaystyle -11 +-3=-14\) the two factors we want are \(\displaystyle -11\) and \(\displaystyle -3\).

Simply plug them into the parentheses and you have:

\(\displaystyle (x-11)(x-3)\)

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