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Algebra 1 : How to find f(x)

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Example Questions

Example Question #51 : Algebraic Functions

Given a function $f(x)=2x^{2}-x+8$ $\displaystyle f(x)=2x^{2}-x+8$, what is f(3) $\displaystyle f(3)$?

Possible Answers:

$\displaystyle 23$

$\displaystyle 24$

$\displaystyle 21$

$\displaystyle 20$

$\displaystyle 22$

Correct answer:

$\displaystyle 23$

Explanation:

Given a function $f(x)=2x^{2}-x+8$ $\displaystyle f(x)=2x^{2}-x+8$, we can plug in x=3 $\displaystyle x=3$ to get

$\\f(3)=2(3)^{2}-(3)+8\\=18-3+8\\=15+8\\=23$ $\displaystyle \\f(3)=2(3)^{2}-(3)+8\\=18-3+8\\=15+8\\=23$.

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Example Question #51 : Algebraic Functions

Given a function $f(x)=5x^{2}+5x+9$ $\displaystyle f(x)=5x^{2}+5x+9$, what is f(7) $\displaystyle f(7)$?

Possible Answers:

292 $\displaystyle 292$

293 $\displaystyle 293$

289 $\displaystyle 289$

291 $\displaystyle 291$

290 $\displaystyle 290$

Correct answer:

289 $\displaystyle 289$

Explanation:

Given a function $f(x)=5x^{2}+5x+9$ $\displaystyle f(x)=5x^{2}+5x+9$, we can plug in x=7 $\displaystyle x=7$ to get

$\\f(7)=5(7)^{2}+5(7)+9\\=5(49)+35+9\\=245+44\\=289$ $\displaystyle \\f(7)=5(7)^{2}+5(7)+9\\=5(49)+35+9\\=245+44\\=289$.

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Example Question #101 : Functions And Lines

Given a function $f(x)=\frac{1}{2}x^{2}-11x+8$ $\displaystyle f(x)=\frac{1}{2}x^{2}-11x+8$, what is f(-2) $\displaystyle f(-2)$?

Possible Answers:

$\displaystyle 30$

$\displaystyle 29$

$\displaystyle 32$

$\displaystyle 31$

$\displaystyle 28$

Correct answer:

$\displaystyle 32$

Explanation:

Given a function $f(x)=\frac{1}{2}x^{2}-11x+8$ $\displaystyle f(x)=\frac{1}{2}x^{2}-11x+8$, we can plug in x=-2 $\displaystyle x=-2$ to get

$\\f(-2)=\frac{1}{2}(-2)^{2}-11(-2)+8\\=2+22+8\\=2+30\\=32$ $\displaystyle \\f(-2)=\frac{1}{2}(-2)^{2}-11(-2)+8\\=2+22+8\\=2+30\\=32$.

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Example Question #51 : How To Find F(X)

Given a function $f(x)=x^{2}-\frac{1}{2}x+\frac{3}{4}$ $\displaystyle f(x)=x^{2}-\frac{1}{2}x+\frac{3}{4}$, what is f(2) $\displaystyle f(2)$?

Possible Answers:

$\frac{17}{4}$ $\displaystyle \frac{17}{4}$

$\frac{21}{4}$ $\displaystyle \frac{21}{4}$

$\frac{15}{4}$ $\displaystyle \frac{15}{4}$

$\frac{13}{4}$ $\displaystyle \frac{13}{4}$

$\frac{19}{4}$ $\displaystyle \frac{19}{4}$

Correct answer:

$\frac{15}{4}$ $\displaystyle \frac{15}{4}$

Explanation:

Given a function

$f(x)=x^{2}-\frac{1}{2}x+\frac{3}{4}$ $\displaystyle f(x)=x^{2}-\frac{1}{2}x+\frac{3}{4}$,

we can plug in x=2 $\displaystyle x=2$ to get

$\\f(2)=(2)^{2}-\frac{1}{2}(2)+\frac{3}{4}\\ \\=4-1+\frac{3}{4}\\ \\=3+\frac{3}{4}\\ \\=\frac{12}{4}+\frac{3}{4}\\ \\=\frac{15}{4}$ $\displaystyle \\f(2)=(2)^{2}-\frac{1}{2}(2)+\frac{3}{4}\\ \\=4-1+\frac{3}{4}\\ \\=3+\frac{3}{4}\\ \\=\frac{12}{4}+\frac{3}{4}\\ \\=\frac{15}{4}$

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Example Question #52 : Algebraic Functions

Given a function $f(x)=x^{3}+2x^{2}+5x$ $\displaystyle f(x)=x^{3}+2x^{2}+5x$, what is f(3) $\displaystyle f(3)$?

Possible Answers:

$\displaystyle 60$

$\displaystyle 68$

$\displaystyle 62$

$\displaystyle 70$

$\displaystyle 64$

Correct answer:

$\displaystyle 60$

Explanation:

Given a function

$f(x)=x^{3}+2x^{2}+5x$ $\displaystyle f(x)=x^{3}+2x^{2}+5x$,

we can plug in x=3 $\displaystyle x=3$ to get

$\\ f(3)=(3)^{3}+2(3)^{2}+5(3)\\ \\=27+18+15\\ \\=27+33\\ \\=60$ $\displaystyle \\ f(3)=(3)^{3}+2(3)^{2}+5(3)\\ \\=27+18+15\\ \\=27+33\\ \\=60$.

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Example Question #51 : How To Find F(X)

Given a function $f(x)=-7x^{2}-6x^{2}+15$ $\displaystyle f(x)=-7x^{2}-6x^{2}+15$, what is f(1) $\displaystyle f(1)$?

Possible Answers:

$\displaystyle 1$

$\displaystyle 3$

$\displaystyle 4$

$\displaystyle 2$

$\displaystyle 5$

Correct answer:

$\displaystyle 2$

Explanation:

Given a function

$f(x)=-7x^{2}-6x^{2}+15$ $\displaystyle f(x)=-7x^{2}-6x^{2}+15$,

we can plug in x=1 $\displaystyle x=1$ to get

$\\ f(1)=-7(1)^{2}-6(1)^{2}+15\\ \\=-7-6+15\\ \\=-13+15\\ \\=2$ $\displaystyle \\ f(1)=-7(1)^{2}-6(1)^{2}+15\\ \\=-7-6+15\\ \\=-13+15\\ \\=2$.

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Example Question #52 : How To Find F(X)

Given a function $f(x)=x^{3}-9x+3$ $\displaystyle f(x)=x^{3}-9x+3$, what is f(3) $\displaystyle f(3)$?

Possible Answers:

$\displaystyle -3$

$\displaystyle 9$

$\displaystyle 3$

$\displaystyle -9$

$\displaystyle 27$

Correct answer:

$\displaystyle 3$

Explanation:

Given a function $f(x)=x^{3}-9x+3$ $\displaystyle f(x)=x^{3}-9x+3$, we can plug in x=3 $\displaystyle x=3$ to get

$\\ f(3)=(3)^{3}-9(3)+3 \\=27-27+3\\=3$ $\displaystyle \\ f(3)=(3)^{3}-9(3)+3 \\=27-27+3\\=3$.

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Example Question #58 : How To Find F(X)

Given a function $f(x)=2x^{2}+5x-9$ $\displaystyle f(x)=2x^{2}+5x-9$, what is f(2) $\displaystyle f(2)$?

Possible Answers:

$\displaystyle -7$

$\displaystyle 9$

$\displaystyle 7$

$\displaystyle 2$

$\displaystyle -9$

Correct answer:

$\displaystyle 9$

Explanation:

Given a function $f(x)=2x^{2}+5x-9$ $\displaystyle f(x)=2x^{2}+5x-9$, we can plug in x=2 $\displaystyle x=2$ to get

$\\f(2)=2(2)^{2}+5(2)-9\\=8+10-9\\=18-9\\=9$ $\displaystyle \\f(2)=2(2)^{2}+5(2)-9\\=8+10-9\\=18-9\\=9$.

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Example Question #51 : How To Find F(X)

Given a function $f(x)=\frac{1}{2}x^{2}-\frac{1}{6}x-4$ $\displaystyle f(x)=\frac{1}{2}x^{2}-\frac{1}{6}x-4$, what is f(4) $\displaystyle f(4)$?

Possible Answers:

$\frac{10}{3}$ $\displaystyle \frac{10}{3}$

$\frac{11}{3}$ $\displaystyle \frac{11}{3}$

$\frac{13}{3}$ $\displaystyle \frac{13}{3}$

$\displaystyle 3$

$\displaystyle 4$

Correct answer:

$\frac{10}{3}$ $\displaystyle \frac{10}{3}$

Explanation:

Given a function $f(x)=\frac{1}{2}x^{2}-\frac{1}{6}x-4$ $\displaystyle f(x)=\frac{1}{2}x^{2}-\frac{1}{6}x-4$, we can plug in x=4 $\displaystyle x=4$ to get

$\\f(4)=\frac{1}{2}(4)^{2}-\frac{1}{6}(4)-4\\ \\=8-\frac{2}{3}-4\\ \\=4-\frac{2}{3}\\ \\=\frac{10}{3}$ $\displaystyle \\f(4)=\frac{1}{2}(4)^{2}-\frac{1}{6}(4)-4\\ \\=8-\frac{2}{3}-4\\ \\=4-\frac{2}{3}\\ \\=\frac{10}{3}$.

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Example Question #60 : How To Find F(X)

For the function $f(x)=2x^{2}-6x+7$ $\displaystyle f(x)=2x^{2}-6x+7$, find f(-1) $\displaystyle f(-1)$

Possible Answers:

$\displaystyle f(-1)=12$

f(-1)=3 $\displaystyle f(-1)=3$

f(-1)=9 $\displaystyle f(-1)=9$

$\displaystyle f(-1)=15$

$\displaystyle f(-1)=-1$

Correct answer:

$\displaystyle f(-1)=15$

Explanation:

To find f(-1) $\displaystyle f(-1)$, we must plug x=-1 $\displaystyle x=-1$ into the provided function:

$f(x)=2x^{2}-6x+7$ $\displaystyle f(x)=2x^{2}-6x+7$

$f(-1)=2(-1)^{2}-6(-1)+7$ $\displaystyle f(-1)=2(-1)^{2}-6(-1)+7$

$\displaystyle f(-1)=2(1)-6(-1)+7$

$\displaystyle f(-1)=2+6+7$

$\displaystyle f(-1)=15$

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Algebra 1 : How to find f(x)

Study concepts, example questions & explanations for Algebra 1

All Algebra 1 Resources

Example Questions

Example Question #51 : Algebraic Functions

Example Question #51 : Algebraic Functions

Example Question #101 : Functions And Lines

Example Question #51 : How To Find F(X)

Example Question #52 : Algebraic Functions

Example Question #51 : How To Find F(X)

Example Question #52 : How To Find F(X)

Example Question #58 : How To Find F(X)

Example Question #51 : How To Find F(X)

Example Question #60 : How To Find F(X)

All Algebra 1 Resources

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