Since we know  \(\displaystyle 1\) kilogram is equal to \(\displaystyle 2.2\) pounds, we can write the following:

\(\displaystyle 95\text{ kilograms}\times\frac{2.2\text{ pounds}}{1\text{ kilogram}}=209\text{ pounds}\)

Since we know there are \(\displaystyle 1609\) meters in a mile and recall that there are \(\displaystyle 3600\) seconds in a hour, we can write the following:

\(\displaystyle \frac{10\text{ miles}}{1\text{ hour}}\times\frac{1609\text{ meters}}{1\text{ mile}}\times\frac{1\text{ hour}}{3600\text{ seconds}}=4.5 \text{ meters per second}\)

Because we are told that there are \(\displaystyle 2.54\) centimeters in \(\displaystyle 1\) inch, we can write the following:

\(\displaystyle 193\text{ centimers}\times\frac{1\text{ inch}}{2.54\text{ centimeters}}=75.98\text{ inches}\)

Recall that there are \(\displaystyle 60\) seconds in a minute, \(\displaystyle 60\) minutes in an hour, and \(\displaystyle 24\) hours in a day.

\(\displaystyle 691,200\text{ seconds}\times\frac{1\text{ minute}}{60\text{ seconds}}\times\frac{1\text{ hour}}{60\text{ minutes}}\times\frac{1\text{ day}}{24 \text{ hours}}=8 \text{ days}\)

Because we are told that there are \(\displaystyle 3.28\) feet in a meter, we can write the following:

\(\displaystyle 124\text{ feet}\times\frac{1\text{ meter}}{3.28\text{ feet}}=37.8\text{ meters}\)

Since we know that there are \(\displaystyle 0.45\) pounds in \(\displaystyle 1\) kilogram, we can write the following:

\(\displaystyle 157\text{ pounds}\times\frac{0.45 \text{ kilograms}}{1\text{ pound} }=70.7\text{ kilograms}\)

To find the number of meters required, simply multiply the number of Vines (14) by the converstion factor of Vines to Panes (4).

Then multiply the result by the conversion factor of Panes to Stems (8).

The last step is to multiply this answer by the conversion factor of Stems to meters (.05). 

\(\displaystyle 14(4)(8)(0.05)=56(8)(0.05)=56(0.4)=22.4\)

To solve this conversion we have to remember that there are 3 feet per 1 yard.

In order to have yards left as our unit, we need to make sure that the other units cancel out by one being in the numerator and one being in the denominator.

Therefore, set up the following conversion and solve:

\(\displaystyle \frac{15ft}{1}*\frac{1yd}{3ft}=\frac{15yds}{3}=5yds\)

To solve this conversion we have to remember that there are 4 quarts per 1 gallon.

In order to have gallons left as our unit, we need to make sure that the other units cancel out by one being in the numerator and one being in the denominator.

Therefore, set up the following conversion and solve:

\(\displaystyle \frac{16qts}{1}*\frac{1gal}{4qts}=\frac{16gal}{4}=4gal\)

To solve this conversion we have to remember that there are 12 inches per 1 foot.

In order to have feet left as our unit, we need to make sure that the other units cancel out by one being in the numerator and one being in the denominator.

Therefore, set up the following conversion and solve:

\(\displaystyle \frac{36in}{1}*\frac{1ft}{12in}=\frac{36ft}{12}=3ft\)