All Algebra 1 Resources
Example Questions
Example Question #211 : Linear Equations
Solve for .
In order to solve for , we need to isolate the variable on the left side of the equation. We will do this by performing the same operations to both sides of the equation.
Multiply both sides of the equation by . When multiplying with one negative and one positive number, our answer is negative.
Solve.
Example Question #211 : Linear Equations
Solve for .
In order to solve for , we need to isolate the variable on the left side of the equation. We will do this by performing the same operations to both sides of the equation.
Multiply both sides by . When multiplying two negative numbers, our answer is positive.
Solve.
Example Question #212 : Algebra 1
Solve for :
.
In order to solve for in the above equation, we must isolate it on one side of the equation. We can do this by applying an operation to
that is the inverse (opposite) of what's currently being applied to
.
Given , we see that
is being multiplied by
, so we need to divide both sides of the equation by
to isolate it:
Example Question #211 : Linear Equations
Solve for :
.
In order to solve for in the above equation, we must isolate it on one side of the equation. We can do this by applying an operation to
that is the inverse (opposite) of what's currently being applied to
.
Given , we see that
is being divided by
, so we need to multiply both sides of the equation by
to isolate it:
Example Question #212 : Linear Equations
Solve for :
.
In order to solve for in the above equation, we must isolate it on one side of the equation. We can do this by applying an operation to
that is the inverse (opposite) of what's currently being applied to
.
Given , we see that
is being added to
, so we need to subtract both sides of the equation by
to isolate
:
Example Question #216 : Algebra 1
Solve for :
.
In order to solve for in the above equation, we must isolate it on one side of the equation. We can do this by applying an operation to
that is the inverse (opposite) of what's currently being applied to
.
Given , we see that
is being subtracted from
, so we need to add
to both sides of the equation to isolate
:
Example Question #217 : Algebra 1
Solve for :
.
In order to solve for in the above equation, we must isolate it on one side of the equation. We can do this by applying an operation to
that is the inverse (opposite) of what's currently being applied to
.
Given , we see that
is being divided by
, so we need to multiply both sides of the equation by
to isolate
:
Example Question #218 : Algebra 1
Solve for :
.
In order to solve for in the above equation, we must isolate it on one side of the equation. We can do this by applying an operation to
that is the inverse (opposite) of what's currently being applied to
.
Given , we see that
is being multiplied by
, so we need to divide both sides of the equation by
to isolate
:
Example Question #219 : Algebra 1
Solve for .
In order to solve for , we need to isolate it on the left side of the equation. We will do this by performing the same operations on both sides of the given equation:
Subtract from both sides of the equation.
Solve.
Example Question #220 : Algebra 1
Solve for .
In order to solve for , we need to isolate it on the left side of the equation. We will do this by performing the same operations on both sides of the given equation:
Add to both sides of the equation.
Solve.
All Algebra 1 Resources
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