Algebra II : Algebra II

Study concepts, example questions & explanations for Algebra II

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Example Questions

Example Question #430 : Basic Single Variable Algebra

Set up the equation:  Two less than twenty times a number is four.

Possible Answers:

\(\displaystyle 22x=4\)

\(\displaystyle 18x=4\)

\(\displaystyle 2-20x=4\)

\(\displaystyle 20(x-2)=4\)

\(\displaystyle 20x-2=4\)

Correct answer:

\(\displaystyle 20x-2=4\)

Explanation:

Split up the sentence into parts.

Twenty times a number:  \(\displaystyle 20x\) 

Two less than twenty times a number:  \(\displaystyle 20x-2\)

Is four:  \(\displaystyle =4\)

Combine the terms.

The answer is:  \(\displaystyle 20x-2=4\)

Example Question #431 : Basic Single Variable Algebra

Set up the following equation:   The sum of a number and twice the square of a number is eleven.

Possible Answers:

\(\displaystyle (3x)^2=11\)

\(\displaystyle x+(2x)^2=11\)

\(\displaystyle x+2x^2=11\)

\(\displaystyle (x+2x^2)^2=11\)

\(\displaystyle 3x^2=11\)

Correct answer:

\(\displaystyle x+2x^2=11\)

Explanation:

Break up the sentence into parts.

Twice the square of a number:  \(\displaystyle 2x^2\)

The sum of a number and twice the square of a number:  \(\displaystyle x+2x^2\)

Is eleven:  \(\displaystyle =11\)

Combine the parts to form the equation.

The answer is:  \(\displaystyle x+2x^2=11\)

Example Question #81 : Setting Up Equations

Set up the following equation:  Ten less than three times the square root of a number is five.

Possible Answers:

\(\displaystyle 3\sqrt{10-x}=5\)

\(\displaystyle \textup{The answer is not given.}\)

\(\displaystyle 3\sqrt{x}-10=5\)

\(\displaystyle 3\sqrt{x-10}=5\)

\(\displaystyle 10-3\sqrt{x}=5\)

Correct answer:

\(\displaystyle 3\sqrt{x}-10=5\)

Explanation:

Split up the sentence into parts.

The square root of a number: \(\displaystyle \sqrt{x}\)

Three times the square root of a number:  \(\displaystyle 3\sqrt{x}\)

Ten more less than three times the square root of a number:  \(\displaystyle 3\sqrt{x}-10\)

Is five:  \(\displaystyle =5\)

Combine the parts to form an equation.

The answer is:  \(\displaystyle 3\sqrt{x}-10=5\)

Example Question #81 : Equations

Set up the equation:  Five more than six times a number cubed is eight.

Possible Answers:

\(\displaystyle 6x^3+5=8\)

\(\displaystyle 6(x^3+5)=8\)

\(\displaystyle (6x+5)^3=8\)

\(\displaystyle (6x)^3+5=8\)

\(\displaystyle 6(x+5)^3=8\)

Correct answer:

\(\displaystyle 6x^3+5=8\)

Explanation:

Split up the sentence into parts.

Six times a number cubed:  \(\displaystyle 6x^3\)

 Five more than six times a number cubed:  \(\displaystyle 6x^3+5\)

Is eight:  \(\displaystyle =8\)

The answer is:  \(\displaystyle 6x^3+5=8\)

Example Question #82 : Equations

Set up the following equation:  Eight times a number less than seven is equal to fifty six.

Possible Answers:

\(\displaystyle 7x-8=56\)

\(\displaystyle 8(x-7)= 56\)

\(\displaystyle 7(x-8)=56\)

\(\displaystyle 8x-7= 56\)

\(\displaystyle 7-8x = 56\)

Correct answer:

\(\displaystyle 7-8x = 56\)

Explanation:

Split up the sentence into parts.

Eight times a number:  \(\displaystyle 8x\)

Eight times a number less than seven:  \(\displaystyle 7-8x\)

Is fifty six:  \(\displaystyle =56\)

Combine the parts to form the equation.

The answer is:  \(\displaystyle 7-8x = 56\)

Example Question #81 : Equations

Set up the equation:  The product of the square of a number and four times another number is six.

Possible Answers:

\(\displaystyle (4x)^2y=6\)

\(\displaystyle 4x^2y=6\)

\(\displaystyle 4x^2+y=6\)

\(\displaystyle 4x^3=6\)

\(\displaystyle 4(x+y)^2=6\)

Correct answer:

\(\displaystyle 4x^2y=6\)

Explanation:

Break up the question into parts.

The square of a number:  \(\displaystyle x^2\)

Four times another number:  \(\displaystyle 4y\)

Is six:  \(\displaystyle =6\)

The product means to multiply the numbers together.

The answer is:  \(\displaystyle 4x^2y=6\)

Example Question #431 : Basic Single Variable Algebra

Set up the equation:  Eight less than the cube root of a number squared is four.

Possible Answers:

\(\displaystyle 8-\sqrt[3]{x^2}=4\)

\(\displaystyle \sqrt[3]{8-x^2}=4\)

\(\displaystyle \sqrt[3]{(x-8)^2}=4\)

\(\displaystyle \sqrt[3]{x^2-8}=4\)

\(\displaystyle \sqrt[3]{x^2}-8=4\)

Correct answer:

\(\displaystyle \sqrt[3]{x^2}-8=4\)

Explanation:

Break up the sentence into parts.

A number squared:  \(\displaystyle x^2\)

The cube root of a number squared:  \(\displaystyle \sqrt[3]{x^2}\)

Eight less than the cube root of a number squared:  \(\displaystyle \sqrt[3]{x^2}-8\)

Is four:  \(\displaystyle =4\)

Set the two terms equal to form the equation.

The answer is:  \(\displaystyle \sqrt[3]{x^2}-8=4\)

Example Question #431 : Basic Single Variable Algebra

Set up the equation:  Eight less than four times a number is twenty.

Possible Answers:

\(\displaystyle 4(8-x)=20\)

\(\displaystyle 8-4x=20\)

\(\displaystyle 4x-8=20\)

\(\displaystyle 4(x-8)=20\)

\(\displaystyle 4x=20\)

Correct answer:

\(\displaystyle 4x-8=20\)

Explanation:

Split the sentence into parts.

Four times a number: \(\displaystyle 4x\)

Eight less than four times a number:  \(\displaystyle 4x-8\)

Is twenty:  \(\displaystyle =20\)

Set the terms equal.

The answer is:  \(\displaystyle 4x-8=20\)

Example Question #432 : Basic Single Variable Algebra

Set up the equation:  Nine more than three times the cube of a number is four.

Possible Answers:

\(\displaystyle 27x^3+9=4\)

\(\displaystyle 3x^3+9=4\)

\(\displaystyle 3(x+9)^3=4\)

\(\displaystyle 3(x+9)^2=4\)

\(\displaystyle (3x+9)^3=4\)

Correct answer:

\(\displaystyle 3x^3+9=4\)

Explanation:

Split the sentence into parts.

The cube of a number:  \(\displaystyle x^3\)

Three times the cube of a number:  \(\displaystyle 3x^3\)

Nine more than three times the cube of a number:  \(\displaystyle 3x^3+9\)

Is four:  \(\displaystyle =4\)

Combine the parts to form the equation.

The answer is:  \(\displaystyle 3x^3+9=4\)

Example Question #433 : Basic Single Variable Algebra

Set up the equation:  Five less than a fifth of a number is three.

Possible Answers:

\(\displaystyle \frac{1}{5}x-5=3\)

\(\displaystyle -5-\frac{1}{5}x=3\)

\(\displaystyle 4.5x=3\)

\(\displaystyle 5-\frac{1}{5}x=3\)

\(\displaystyle \frac{1}{5}(x-5)=3\)

Correct answer:

\(\displaystyle \frac{1}{5}x-5=3\)

Explanation:

Write each part of the sentence in separate terms.

A fifth of a number:  \(\displaystyle \frac{1}{5}x\)

Five less than a fifth of a number:   \(\displaystyle \frac{1}{5}x-5\)

Is three:  \(\displaystyle =3\)

Combine the parts to form an equation.

The answer is:  \(\displaystyle \frac{1}{5}x-5=3\)

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