Call Now to Set Up Tutoring:

(888) 888-0446

Algebra II : Algebra II

Study concepts, example questions & explanations for Algebra II

Create An Account

All Algebra II Resources

10 Diagnostic Tests 630 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #251 : Functions And Graphs

What is $f^{-1}(5)$ if x-f(x)=5 ?

Possible Answers:

$\frac{1}{5}$

Correct answer:

Explanation:

The notation $f^{-1}(5)$ designates the inverse function at x=5 .

Replace the f(x) term with .

x-y=5

Interchange the and values.

y-x=5

Solve for . Add on both sides.

y-x+x=5+x

The inverse function is: y=x+5

Substitute x=5 into the inverse function.

y=x+5 = 5+5 =10

The answer is:

Report an Error

Example Question #781 : Algebra Ii

Find the inverse of: y=-6x+7

Possible Answers:

$y=-\frac{1}{6}x+\frac{7}{6}$

$y=-\frac{1}{6}x+7$

$y=-\frac{1}{6}x-7$

$y=-\frac{7}{6}x+\frac{1}{6}$

$y=-\frac{1}{6}x-\frac{7}{6}$

Correct answer:

$y=-\frac{1}{6}x+\frac{7}{6}$

Explanation:

Interchange the x and y variables.

x=-6y+7

Solve for y. Subtract seven on both sides.

x-7=-6y+7-7

x-7=-6y

Divide by negative six on both sides.

$\frac{x-7}{-6}=\frac{-6y}{-6}$

The answer is: $y=-\frac{1}{6}x+\frac{7}{6}$

Report an Error

Example Question #61 : Inverse Functions

Determine the inverse of: y=9x+27

Possible Answers:

$y=\frac{1}{9}x-\frac{1}{9}$

$y=\frac{1}{9}x-\frac{1}{3}$

$y=-\frac{1}{9}x-\frac{1}{3}$

$y=-\frac{1}{9}x-\frac{1}{9}$

$y=\frac{1}{9}x-3$

Correct answer:

$y=\frac{1}{9}x-3$

Explanation:

Switch the x and y variables.

x=9y+27

Solve for y. Subtract 27 on both sides.

x-27=9y+27-27

x-27=9y

Divide both sides by 9.

$\frac{x-27}{9}=\frac{9y}{9}$

The answer is: $y=\frac{1}{9}x-3$

Report an Error

Example Question #61 : Inverse Functions

Determine the inverse function given the equation: y= -4x-6

Possible Answers:

$y=-\frac{1}{4}x-\frac{1}{3}$

$y=-\frac{1}{4}x+\frac{3}{2}$

$y=-\frac{1}{4}x-\frac{3}{2}$

$y=-\frac{1}{4}x-3$

$y=-\frac{1}{4}x+\frac{1}{3}$

Correct answer:

$y=-\frac{1}{4}x-\frac{3}{2}$

Explanation:

Interchange the x and y variables.

x= -4y-6

Solve for y. Add six on both sides.

x+6= -4y-6+6

x+6= -4y

Divide both sides by negative four.

$\frac{x+6}{-4}= \frac{-4y}{-4}$

The answer is: $y=-\frac{1}{4}x-\frac{3}{2}$

Report an Error

Example Question #61 : Inverse Functions

Determine the inverse: y= 3(3-9x)

Possible Answers:

$y=-\frac{1}{27}x+\frac{1}{3}$

$y=-\frac{1}{27}x+\frac{1}{27}$

$y=-\frac{1}{3}x+\frac{1}{9}$

$y=-\frac{1}{3}x+\frac{1}{27}$

$y=-9x+\frac{1}{27}$

Correct answer:

$y=-\frac{1}{27}x+\frac{1}{3}$

Explanation:

Interchange the x and y-variables.

x= 3(3-9y)

Solve for y. Distribute the three through both terms of the binomial.

x=9-27y

Subtract 9 on both sides.

x-9=9-27y-9

The equation becomes: x-9=-27y

Divide by negative 27 on both sides.

$\frac{x-9}{-27}=\frac{-27y}{-27}$

Simplify both sides.

The answer is: $y=-\frac{1}{27}x+\frac{1}{3}$

Report an Error

Example Question #261 : Introduction To Functions

Determine the inverse of: y=-4x-32

Possible Answers:

$y=-\frac{1}{4}x-32$

$y=-\frac{1}{4}x-\frac{1}{8}$

$y=-\frac{1}{4}x+\frac{1}{8}$

$y=-\frac{1}{4}x+\frac{1}{4}$

$y=-\frac{1}{4}x-8$

Correct answer:

$y=-\frac{1}{4}x-8$

Explanation:

Interchange the x and y-variables.

x=-4y-32

Solve for y. Add 32 on both sides.

x+32=-4y-32+32

The equation becomes:

x+32=-4y

Divide by negative four on both sides.

$\frac{x+32}{-4}=\frac{-4y}{-4}$

Simplify both sides.

The answer is: $y=-\frac{1}{4}x-8$

Report an Error

Example Question #65 : Inverse Functions

Determine the inverse: y=2-(2x-3)

Possible Answers:

$y=-\frac{1}{2}x+\frac{3}{2}$

$y=-\frac{3}{2}x+\frac{1}{2}$

$y=-\frac{1}{2}x+\frac{5}{2}$

$y=-\frac{3}{2}x+\frac{3}{2}$

$y=-\frac{5}{2}x+\frac{5}{2}$

Correct answer:

$y=-\frac{1}{2}x+\frac{5}{2}$

Explanation:

Interchange the x and y variables.

x=2-(2y-3)

Solve for y.

Subtract two from both sides.

x-2=2-(2y-3)-2

x-2=-(2y-3)

Divide by negative one on both sides.

$\frac{x-2}{-1}=\frac{-(2y-3)}{-1}$

-x+2 =2y-3

Add three on both sides.

-x+2+3 =2y-3+3

-x+5 =2y

Divide by two on both sides.

$\frac{-x+5 }{2}=\frac{2y}{2}$

The answer is: $y=-\frac{1}{2}x+\frac{5}{2}$

Report an Error

Example Question #61 : Inverse Functions

Determine the inverse of the function: y=-3(6x+3)

Possible Answers:

$y=-\frac{1}{18}x -\frac{1}{2}$

$y=-\frac{1}{9}x -\frac{1}{18}$

$y=-\frac{1}{18}x -\frac{1}{18}$

$y=-\frac{1}{9}x -\frac{1}{2}$

$y=-\frac{1}{9}x -\frac{1}{4}$

Correct answer:

$y=-\frac{1}{18}x -\frac{1}{2}$

Explanation:

Interchange the x and y variables.

x=-3(6y+3)

Solve for y. Distribute the negative three across both terms in the binomial.

x=-3(6y)+(-3)(3)

Simplify the equation.

x=-18y-9

Add 9 on both sides.

x+9=-18y-9+9

x+9=-18y

Divide by negative 18 on both sides.

$\frac{x+9}{-18}=\frac{-18y}{-18}$

The answer is: $y=-\frac{1}{18}x -\frac{1}{2}$

Report an Error

Example Question #61 : Inverse Functions

Determine the inverse of the equation: y=-6x+3

Possible Answers:

$y=-\frac{1}{6}x+\frac{1}{4}$

$y=-\frac{1}{6}x+\frac{1}{2}$

$y=-\frac{1}{6}x+\frac{1}{6}$

$y=-\frac{1}{3}x+\frac{1}{2}$

$y=-\frac{1}{6}x+\frac{1}{3}$

Correct answer:

$y=-\frac{1}{6}x+\frac{1}{2}$

Explanation:

Interchange the x and y-variables.

x=-6y+3

Solve for y.

Subtract three from both sides.

x-3=-6y+3-3

x-3=-6y

Divide by negative 6 on both sides.

$\frac{x-3}{-6}=\frac{-6y}{-6}$

The answer is: $y=-\frac{1}{6}x+\frac{1}{2}$

Report an Error

Example Question #61 : Inverse Functions

Determine the inverse for: y=-6x-10

Possible Answers:

$y=-\frac{1}{3}x-\frac{5}{6}$

$y=-\frac{1}{2}x-\frac{5}{2}$

$y=-\frac{1}{6}x-\frac{10}{3}$

$y=-\frac{1}{3}x-\frac{5}{3}$

$y=-\frac{1}{6}x-\frac{5}{3}$

Correct answer:

$y=-\frac{1}{6}x-\frac{5}{3}$

Explanation:

Swap the x and y variables.

x=-6y-10

Solve for y. Add 10 on both sides.

x+10=-6y-10+10

x+10=-6y

Divide by negative six on both sides.

$\frac{x+10}{-6}=\frac{-6y}{-6}$

The answer is: $y=-\frac{1}{6}x-\frac{5}{3}$

Report an Error

View Algebra 2 Tutors

Michelle
Certified Tutor

University of Nevada-Las Vegas, Bachelor of Science, Mathematics.

View Algebra 2 Tutors

Corey
Certified Tutor

North Carolina State University at Raleigh, Bachelor in Arts, Organizational Leadership.

View Algebra 2 Tutors

Mayowa
Certified Tutor

Logan University, Bachelor of Science, Biology, General.

All Algebra II Resources

10 Diagnostic Tests 630 Practice Tests Question of the Day Flashcards Learn by Concept

Popular Subjects

MCAT Tutors in Dallas Fort Worth, Statistics Tutors in Houston, SAT Tutors in Boston, French Tutors in Atlanta, SSAT Tutors in Miami, SAT Tutors in Washington DC, Spanish Tutors in Washington DC, Math Tutors in Houston, SSAT Tutors in San Diego, Math Tutors in New York City

Popular Courses & Classes

Spanish Courses & Classes in Phoenix, Spanish Courses & Classes in Dallas Fort Worth, ISEE Courses & Classes in Los Angeles, GMAT Courses & Classes in San Francisco-Bay Area, SAT Courses & Classes in Seattle, SSAT Courses & Classes in Atlanta, GRE Courses & Classes in Boston, SAT Courses & Classes in Miami, ISEE Courses & Classes in Washington DC, SSAT Courses & Classes in Chicago

Popular Test Prep

SAT Test Prep in Houston, LSAT Test Prep in Denver, ISEE Test Prep in Miami, SSAT Test Prep in Philadelphia, GMAT Test Prep in Miami, SSAT Test Prep in San Diego, LSAT Test Prep in Miami, SSAT Test Prep in Los Angeles, GRE Test Prep in Boston, GMAT Test Prep in San Francisco-Bay Area

DMCA Complaint

If you believe that content available by means of the Website (as defined in our Terms of Service) infringes one or more of your copyrights, please notify us by providing a written notice (“Infringement Notice”) containing the information described below to the designated agent listed below. If Varsity Tutors takes action in response to an Infringement Notice, it will make a good faith attempt to contact the party that made such content available by means of the most recent email address, if any, provided by such party to Varsity Tutors.

Your Infringement Notice may be forwarded to the party that made the content available or to third parties such as ChillingEffects.org.

Please be advised that you will be liable for damages (including costs and attorneys’ fees) if you materially misrepresent that a product or activity is infringing your copyrights. Thus, if you are not sure content located on or linked-to by the Website infringes your copyright, you should consider first contacting an attorney.

Please follow these steps to file a notice:

You must include the following:

A physical or electronic signature of the copyright owner or a person authorized to act on their behalf; An identification of the copyright claimed to have been infringed; A description of the nature and exact location of the content that you claim to infringe your copyright, in \ sufficient detail to permit Varsity Tutors to find and positively identify that content; for example we require a link to the specific question (not just the name of the question) that contains the content and a description of which specific portion of the question – an image, a link, the text, etc – your complaint refers to; Your name, address, telephone number and email address; and A statement by you: (a) that you believe in good faith that the use of the content that you claim to infringe your copyright is not authorized by law, or by the copyright owner or such owner’s agent; (b) that all of the information contained in your Infringement Notice is accurate, and (c) under penalty of perjury, that you are either the copyright owner or a person authorized to act on their behalf.

Send your complaint to our designated agent at:

Charles Cohn Varsity Tutors LLC
101 S. Hanley Rd, Suite 300
St. Louis, MO 63105

Or fill out the form below:

Do not fill in this field

Contact Information

* Full legal name

Company name

* Phone number

* Email address

Address

* Address1

Address2

* City

* State

* Zipcode

* Country

Complaint Details

* URL of copyrighted work (where your original material is located)

* Please describe the copyrighted work so that it may be easily identified

I am the owner, or an agent authorized to act on behalf of the owner of an exclusive right that is allegedly infringed.

I have a good faith belief that the use of the material in the manner complained of is not authorized by the copyright owner, its agent, or the law.

This notification is accurate.

I acknowledge that there may be adverse legal consequences for making false or bad faith allegations of copyright infringement by using this process.

* Signature (your digital signature is legally binding)

HIGH SCHOOL

GRADUATE SCHOOL

K-8

Search 50+ Tests

math tutoring

science tutoring

foreign languages

elementary tutoring

other

Search 350+ Subjects

Algebra II : Algebra II

Study concepts, example questions & explanations for Algebra II

All Algebra II Resources

Example Questions

Example Question #251 : Functions And Graphs

Example Question #781 : Algebra Ii

Example Question #61 : Inverse Functions

Example Question #61 : Inverse Functions

Example Question #61 : Inverse Functions

Example Question #261 : Introduction To Functions

Example Question #65 : Inverse Functions

Example Question #61 : Inverse Functions

Example Question #61 : Inverse Functions

Example Question #61 : Inverse Functions

All Algebra II Resources

Report an issue with this question

DMCA Complaint

Contact Information

Address

Complaint Details

Email address:
Your name:
Feedback: