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Algebra II : Algebra II

Study concepts, example questions & explanations for Algebra II

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Example Questions

Example Question #251 : Functions And Graphs

What is $f^{-1}(5)$ if x-f(x)=5 ?

Possible Answers:

$\frac{1}{5}$

Correct answer:

Explanation:

The notation $f^{-1}(5)$ designates the inverse function at x=5 .

Replace the f(x) term with .

x-y=5

Interchange the and values.

y-x=5

Solve for . Add on both sides.

y-x+x=5+x

The inverse function is: y=x+5

Substitute x=5 into the inverse function.

y=x+5 = 5+5 =10

The answer is:

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Example Question #781 : Algebra Ii

Find the inverse of: y=-6x+7

Possible Answers:

$y=-\frac{1}{6}x+\frac{7}{6}$

$y=-\frac{1}{6}x+7$

$y=-\frac{1}{6}x-7$

$y=-\frac{7}{6}x+\frac{1}{6}$

$y=-\frac{1}{6}x-\frac{7}{6}$

Correct answer:

$y=-\frac{1}{6}x+\frac{7}{6}$

Explanation:

Interchange the x and y variables.

x=-6y+7

Solve for y. Subtract seven on both sides.

x-7=-6y+7-7

x-7=-6y

Divide by negative six on both sides.

$\frac{x-7}{-6}=\frac{-6y}{-6}$

The answer is: $y=-\frac{1}{6}x+\frac{7}{6}$

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Example Question #61 : Inverse Functions

Determine the inverse of: y=9x+27

Possible Answers:

$y=\frac{1}{9}x-\frac{1}{9}$

$y=\frac{1}{9}x-\frac{1}{3}$

$y=-\frac{1}{9}x-\frac{1}{3}$

$y=-\frac{1}{9}x-\frac{1}{9}$

$y=\frac{1}{9}x-3$

Correct answer:

$y=\frac{1}{9}x-3$

Explanation:

Switch the x and y variables.

x=9y+27

Solve for y. Subtract 27 on both sides.

x-27=9y+27-27

x-27=9y

Divide both sides by 9.

$\frac{x-27}{9}=\frac{9y}{9}$

The answer is: $y=\frac{1}{9}x-3$

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Example Question #61 : Inverse Functions

Determine the inverse function given the equation: y= -4x-6

Possible Answers:

$y=-\frac{1}{4}x-\frac{1}{3}$

$y=-\frac{1}{4}x+\frac{3}{2}$

$y=-\frac{1}{4}x-\frac{3}{2}$

$y=-\frac{1}{4}x-3$

$y=-\frac{1}{4}x+\frac{1}{3}$

Correct answer:

$y=-\frac{1}{4}x-\frac{3}{2}$

Explanation:

Interchange the x and y variables.

x= -4y-6

Solve for y. Add six on both sides.

x+6= -4y-6+6

x+6= -4y

Divide both sides by negative four.

$\frac{x+6}{-4}= \frac{-4y}{-4}$

The answer is: $y=-\frac{1}{4}x-\frac{3}{2}$

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Example Question #61 : Inverse Functions

Determine the inverse: y= 3(3-9x)

Possible Answers:

$y=-\frac{1}{27}x+\frac{1}{3}$

$y=-\frac{1}{27}x+\frac{1}{27}$

$y=-\frac{1}{3}x+\frac{1}{9}$

$y=-\frac{1}{3}x+\frac{1}{27}$

$y=-9x+\frac{1}{27}$

Correct answer:

$y=-\frac{1}{27}x+\frac{1}{3}$

Explanation:

Interchange the x and y-variables.

x= 3(3-9y)

Solve for y. Distribute the three through both terms of the binomial.

x=9-27y

Subtract 9 on both sides.

x-9=9-27y-9

The equation becomes: x-9=-27y

Divide by negative 27 on both sides.

$\frac{x-9}{-27}=\frac{-27y}{-27}$

Simplify both sides.

The answer is: $y=-\frac{1}{27}x+\frac{1}{3}$

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Example Question #261 : Introduction To Functions

Determine the inverse of: y=-4x-32

Possible Answers:

$y=-\frac{1}{4}x-32$

$y=-\frac{1}{4}x-\frac{1}{8}$

$y=-\frac{1}{4}x+\frac{1}{8}$

$y=-\frac{1}{4}x+\frac{1}{4}$

$y=-\frac{1}{4}x-8$

Correct answer:

$y=-\frac{1}{4}x-8$

Explanation:

Interchange the x and y-variables.

x=-4y-32

Solve for y. Add 32 on both sides.

x+32=-4y-32+32

The equation becomes:

x+32=-4y

Divide by negative four on both sides.

$\frac{x+32}{-4}=\frac{-4y}{-4}$

Simplify both sides.

The answer is: $y=-\frac{1}{4}x-8$

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Example Question #65 : Inverse Functions

Determine the inverse: y=2-(2x-3)

Possible Answers:

$y=-\frac{1}{2}x+\frac{3}{2}$

$y=-\frac{3}{2}x+\frac{1}{2}$

$y=-\frac{1}{2}x+\frac{5}{2}$

$y=-\frac{3}{2}x+\frac{3}{2}$

$y=-\frac{5}{2}x+\frac{5}{2}$

Correct answer:

$y=-\frac{1}{2}x+\frac{5}{2}$

Explanation:

Interchange the x and y variables.

x=2-(2y-3)

Solve for y.

Subtract two from both sides.

x-2=2-(2y-3)-2

x-2=-(2y-3)

Divide by negative one on both sides.

$\frac{x-2}{-1}=\frac{-(2y-3)}{-1}$

-x+2 =2y-3

Add three on both sides.

-x+2+3 =2y-3+3

-x+5 =2y

Divide by two on both sides.

$\frac{-x+5 }{2}=\frac{2y}{2}$

The answer is: $y=-\frac{1}{2}x+\frac{5}{2}$

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Example Question #61 : Inverse Functions

Determine the inverse of the function: y=-3(6x+3)

Possible Answers:

$y=-\frac{1}{18}x -\frac{1}{2}$

$y=-\frac{1}{9}x -\frac{1}{18}$

$y=-\frac{1}{18}x -\frac{1}{18}$

$y=-\frac{1}{9}x -\frac{1}{2}$

$y=-\frac{1}{9}x -\frac{1}{4}$

Correct answer:

$y=-\frac{1}{18}x -\frac{1}{2}$

Explanation:

Interchange the x and y variables.

x=-3(6y+3)

Solve for y. Distribute the negative three across both terms in the binomial.

x=-3(6y)+(-3)(3)

Simplify the equation.

x=-18y-9

Add 9 on both sides.

x+9=-18y-9+9

x+9=-18y

Divide by negative 18 on both sides.

$\frac{x+9}{-18}=\frac{-18y}{-18}$

The answer is: $y=-\frac{1}{18}x -\frac{1}{2}$

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Example Question #61 : Inverse Functions

Determine the inverse of the equation: y=-6x+3

Possible Answers:

$y=-\frac{1}{6}x+\frac{1}{4}$

$y=-\frac{1}{6}x+\frac{1}{2}$

$y=-\frac{1}{6}x+\frac{1}{6}$

$y=-\frac{1}{3}x+\frac{1}{2}$

$y=-\frac{1}{6}x+\frac{1}{3}$

Correct answer:

$y=-\frac{1}{6}x+\frac{1}{2}$

Explanation:

Interchange the x and y-variables.

x=-6y+3

Solve for y.

Subtract three from both sides.

x-3=-6y+3-3

x-3=-6y

Divide by negative 6 on both sides.

$\frac{x-3}{-6}=\frac{-6y}{-6}$

The answer is: $y=-\frac{1}{6}x+\frac{1}{2}$

Report an Error

Example Question #61 : Inverse Functions

Determine the inverse for: y=-6x-10

Possible Answers:

$y=-\frac{1}{3}x-\frac{5}{6}$

$y=-\frac{1}{2}x-\frac{5}{2}$

$y=-\frac{1}{6}x-\frac{10}{3}$

$y=-\frac{1}{3}x-\frac{5}{3}$

$y=-\frac{1}{6}x-\frac{5}{3}$

Correct answer:

$y=-\frac{1}{6}x-\frac{5}{3}$

Explanation:

Swap the x and y variables.

x=-6y-10

Solve for y. Add 10 on both sides.

x+10=-6y-10+10

x+10=-6y

Divide by negative six on both sides.

$\frac{x+10}{-6}=\frac{-6y}{-6}$

The answer is: $y=-\frac{1}{6}x-\frac{5}{3}$

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Algebra II : Algebra II

Study concepts, example questions & explanations for Algebra II

All Algebra II Resources

Example Questions

Example Question #251 : Functions And Graphs

Example Question #781 : Algebra Ii

Example Question #61 : Inverse Functions

Example Question #61 : Inverse Functions

Example Question #61 : Inverse Functions

Example Question #261 : Introduction To Functions

Example Question #65 : Inverse Functions

Example Question #61 : Inverse Functions

Example Question #61 : Inverse Functions

Example Question #61 : Inverse Functions

All Algebra II Resources

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