All Algebra II Resources
Example Questions
Example Question #341 : Basic Single Variable Algebra
Solve the inequality:
Add on both sides.
The inequality becomes:
Subtract 16 on both sides.
Divide by 10 on both sides.
Reduce both fractions.
The answer is:
Example Question #104 : Solving Inequalities
Solve:
Distribute on both sides of the inequality in order to eliminate the parentheses.
The inequality becomes:
Add on both sides.
Subtract 6 from both sides.
Divide by 17 on both sides.
The answer is:
Example Question #105 : Solving Inequalities
Solve the inequality:
Add 9 on both sides.
Divide by negative three on both sides. Dividing by a negative number will switch the sign.
The answer is:
Example Question #106 : Solving Inequalities
Solve the inequality:
Multiply both sides by the least common denominator to eliminate the fractions. The LCD is 12.
Subtract three on both sides.
Divide both sides by 8.
The answer is:
Example Question #111 : Solving Inequalities
Solve:
Distribute the four through the binomial of the right side.
Add and on both sides.
Divide by four on both sides.
The answer is:
Example Question #112 : Solving Inequalities
Solve.
No solution.
Solve.
Step 1: Subtract from both sides of the inequality.
Step 2: Subtract from both sides of the inequality to isolate the term with the variable.
Step 3: Multiply both sides of the inequality by -1 and reverse the inequality sign.
This is to make the inequality have only positive numbers, and this will help solve the inequality. Because we are multiplying by a negative number, we must reverse the inequality sign. The only times we reverse the inequality sign are when we are multiplying or dividing by a negative number. In other instances, we would leave the sign the same.
Step 4: Divide both sides of the inequality by .
Solution:
Example Question #113 : Solving Inequalities
Solve the inequality for
Inequalities can be algebraically rearranged using operations that are mostly identical to algebraic equations, although one notable exception is multiplication or division by -1. This reverses the inequality signs.
Multiply out by
Subtract from all sides,
Divide throughout by and remember to reverse the inequality signs.
It feels more natural to write the final result as:
Example Question #151 : Inequalities
Solve for m.
Remember: Use inverse operations to undo the operations in the inequality (for example use a subtraction to undo an addition) until you are left with the variable. Make sure to do the same operations to both sides of the inequality.
Important Note: When multiplying or dividing by a negative number, always flip the sign of an inequality.
Solution:
Expand all factors
Simplify
Add 23
Subtract 22m
Divide by -6 (We flip the sign of the inequality)
Simplify
Example Question #152 : Inequalities
Solve the double inequality and give the solution in interval notation.
Start by subtracting 1 and divinding by 4 on both sides of the equality
Written in interval notation:
Example Question #1 : Basic Single Variable Algebra
Tom is painting a fence feet long. He starts at the West end of the fence and paints at a rate of feet per hour. After hours, Huck joins Tom and begins painting from the East end of the fence at a rate of feet per hour. After hours of the two boys painting at the same time, Tom leaves Huck to finish the job by himself.
If Huck completes painting the entire fence after Tom leaves, how many more hours will Huck work than Tom?
Tom paints for a total of hours (2 on his own, 2 with Huck's help). Since he paints at a rate of feet per hour, use the formula
(or )
to determine the total length of the fence Tom paints.
feet
Subtracting this from the total length of the fence feet gives the length of the fence Tom will NOT paint: feet. If Huck finishes the job, he will paint that feet of the fence. Using , we can determine how long this will take Huck to do:
hours.
If Huck works hours and Tom works hours, he works more hours than Tom.