Algebra II : Basic Single-Variable Algebra

Study concepts, example questions & explanations for Algebra II

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Example Questions

Example Question #22 : How To Find The Solution To An Equation

Solve for \(\displaystyle x\):

\(\displaystyle 6x-3-4x+5=3(x-1)\)

Possible Answers:

\(\displaystyle 6\)

\(\displaystyle 7\)

\(\displaystyle 4\)

\(\displaystyle 3\)

\(\displaystyle 5\)

Correct answer:

\(\displaystyle 5\)

Explanation:

Combine like terms on the left side of the equation: \(\displaystyle 2x+2=3(x-1)\)

Use the distributive property to simplify the right side of the equation: \(\displaystyle 2x+2=3x-3\)

Next, move the \(\displaystyle x\)'s to one side and the integers to the other side: \(\displaystyle x=5\)

Example Question #24 : How To Find The Solution To An Equation

Solve for \(\displaystyle x\):

\(\displaystyle ex+f=g\)

Possible Answers:

\(\displaystyle \frac{g+f}{e}\)

\(\displaystyle \frac{e}{g+f}\)

\(\displaystyle \frac{g-f}{e}\)

None of the other answers

\(\displaystyle \frac{e}{g-f}\)

Correct answer:

\(\displaystyle \frac{g-f}{e}\)

Explanation:

To solve for \(\displaystyle x\), you must isolate it so that all of the other variables are on the other side of the equation. To do this, first subtract \(\displaystyle f\) from both sides to get \(\displaystyle ex=g-f\). Then, divide both sides by \(\displaystyle e\) to get \(\displaystyle x=\frac{g-f}{e}\).

Example Question #41 : Solving Equations

\(\displaystyle 3x+12=36\), solve for \(\displaystyle x\).

Possible Answers:

\(\displaystyle 16\)

\(\displaystyle 12\)

\(\displaystyle 2\)

\(\displaystyle 4\)

\(\displaystyle 8\)

Correct answer:

\(\displaystyle 8\)

Explanation:

First you need to subtract 12 from both sides of the equation: 

\(\displaystyle 3x+12-12=36-12.\) 

This gives us 

\(\displaystyle 3x=24.\) 

Then, divide each side by 3:

 \(\displaystyle \frac{3x}{3}=\frac{24}{3}\)  which, when simplified, gives us: 

\(\displaystyle x=8.\)

Example Question #42 : Solving Equations

Solve for \(\displaystyle x\):

\(\displaystyle \frac{x}{4} - 3x = 121\)

Possible Answers:

\(\displaystyle x = 11\)

\(\displaystyle x = -11\)

\(\displaystyle x = -44\)

\(\displaystyle x = 44\)

None of the other answers.

Correct answer:

\(\displaystyle x = -44\)

Explanation:

\(\displaystyle \frac{x}{4} - 3x = 121\)

Step 1: Multiply both sides of the equation by 4.

\(\displaystyle \rightarrow x - 12x = 484\)

Step 2: Combine the \(\displaystyle x\)'s.

\(\displaystyle \rightarrow -11x = 484\)

Step 3: Divide both sides of the equation by -11. 

\(\displaystyle \rightarrow x = -44\)

Example Question #171 : Equations

Solve for \(\displaystyle y\):

\(\displaystyle 15 + \frac{y}{2} = 20 - 5y\)

Possible Answers:

\(\displaystyle y = \frac{11}{10}\)

\(\displaystyle y = -\frac{5}{3}\)

\(\displaystyle y = \frac{10}{11}\)

None of the other answers.

\(\displaystyle y = -\frac{3}{5}\)

Correct answer:

\(\displaystyle y = \frac{10}{11}\)

Explanation:

\(\displaystyle 15 + \frac{y}{2} = 20 - 5y\)

Step 1: Multiply both sides of the equation by 2.

\(\displaystyle \rightarrow 30 + y = 40 - 10 y\)

Step 2: Add \(\displaystyle 10y\) to both sides of the equation, and subtract 30 from both sides of the equation.

\(\displaystyle \rightarrow 11y = 10\)

Step 3: Divide both sides of the equation by 11.

\(\displaystyle \rightarrow y = \frac{10}{11}\)

Example Question #172 : Equations

Solve for \(\displaystyle x\):

\(\displaystyle 20 + \frac{2x}{3} = 100\)

Possible Answers:

\(\displaystyle x = 140\)

None of the other answers.

\(\displaystyle x = 120\)

\(\displaystyle x = 180\)

\(\displaystyle x = 50\)

Correct answer:

\(\displaystyle x = 120\)

Explanation:

\(\displaystyle 20 + \frac{2x}{3} = 100\)

Step 1: Multiply both sides of the equation by 3.

\(\displaystyle \rightarrow 60 + 2x = 300\)

Step 2: Subtract 60 from both sides of the equation.

\(\displaystyle \rightarrow 2x = 240\)

Step 3: Divide both sides of the equation by 2.

\(\displaystyle \rightarrow x = 120\)

Example Question #521 : Basic Single Variable Algebra

Solve for \(\displaystyle x\):

\(\displaystyle \frac{x}{5} - 22 = -10\)

Possible Answers:

None of the other answers.

\(\displaystyle x = 60\)

\(\displaystyle x = 160\)

\(\displaystyle x = -60\)

\(\displaystyle x = 28\)

Correct answer:

\(\displaystyle x = 60\)

Explanation:

\(\displaystyle \frac{x}{5} - 22 = -10\)

Step 1: Multiply both sides of the equation by 5.

\(\displaystyle \rightarrow x - 110 = -50\)

Step 2: Add 110 to both sides of the equation.

\(\displaystyle \rightarrow x = 60\)

Example Question #43 : Solving Equations

Solve for \(\displaystyle x\):

\(\displaystyle -16 - 4x = \frac{x}{5} + 2x\)

Possible Answers:

\(\displaystyle x = - \frac{80}{31}\)

\(\displaystyle x = -\frac{31}{80}\)

\(\displaystyle x = \frac{80}{31}\)

None of the other answers.

\(\displaystyle x = -\frac{80}{23}\)

Correct answer:

\(\displaystyle x = - \frac{80}{31}\)

Explanation:

\(\displaystyle -16 - 4x = \frac{x}{5} + 2x\)

Step 1: Multiply both sides of the equation by 5.

\(\displaystyle \rightarrow -80 - 20x = x + 10x\)

Step 2: Combine the \(\displaystyle x\)'s. 

\(\displaystyle \rightarrow -80 - 20x = 11x\)

Step 3: Add \(\displaystyle 20x\) to both sides of the equation.

\(\displaystyle \rightarrow -80 = 31x\)

Step 4: Divide both sides of the equation by 31.

\(\displaystyle \rightarrow x = -\frac{80}{31}\)

Example Question #44 : Solving Equations

Solve for \(\displaystyle x\):

\(\displaystyle 48 = \frac{x}{2} + 20\)

Possible Answers:

\(\displaystyle x = 136\)

\(\displaystyle x = -56\)

\(\displaystyle x = 56\)

None of the other answers.

\(\displaystyle x = 76\)

Correct answer:

\(\displaystyle x = 56\)

Explanation:

\(\displaystyle 48 = \frac{x}{2}+ 20\)

Step 1: Multiply both sides of the equation by 2.

\(\displaystyle \rightarrow 96 = x + 40\)

Step 2: Subtract 40 from both sides of the equation.

\(\displaystyle \rightarrow x = 56\)

Example Question #41 : Solving Equations

Solve for \(\displaystyle x\):

\(\displaystyle 5 + \frac{3}{x} = 20\)

Possible Answers:

\(\displaystyle x = \frac{2}{5}\)

None of the other answers.

\(\displaystyle x = -\frac{1}{5}\)

\(\displaystyle x = \frac{1}{5}\)

\(\displaystyle x = 5\)

Correct answer:

\(\displaystyle x = \frac{1}{5}\)

Explanation:

\(\displaystyle 5 + \frac{3}{x} = 20\)

Step 1: Multiply both sides of the equation by \(\displaystyle x\).

\(\displaystyle \rightarrow 5x + 3 = 20x\)

Step 2: Subtract \(\displaystyle 5x\) from both sides of the equation.

\(\displaystyle \rightarrow 3 = 15x\)

Step 3: Divide both sides of the equation by 15.

\(\displaystyle \rightarrow x = \frac{1}{5}\)

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