Algebra II : Mathematical Relationships and Basic Graphs

Study concepts, example questions & explanations for Algebra II

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Example Questions

Example Question #12 : Elementary Operations

Simplify the following expression:

\(\displaystyle 117+(-33)-88\)

Possible Answers:

\(\displaystyle -104\)

\(\displaystyle -4\)

\(\displaystyle 4\)

\(\displaystyle 45\)

Correct answer:

\(\displaystyle -4\)

Explanation:

Simplify the following expression:

\(\displaystyle 117+(-33)-88\)

Let's break this into parts.

First, realize that adding a negative number is the same as subtracting that number:

\(\displaystyle 117-33=84\)

Next, subtract the 88:

\(\displaystyle 84-88=-4\)

Our answer must be negative, because 88 is bigger than 84. Therefore our answer is -4

Example Question #14 : Addition And Subtraction

If \(\displaystyle f(x)=3x^{2}-4x+2\) and \(\displaystyle g(x)=2x^{2}+x+3\), what is \(\displaystyle f(x)+g(x)\)?

Possible Answers:

\(\displaystyle 2x^{2}+3x-5\)

\(\displaystyle 5x^{2}-3x+5\)

\(\displaystyle x^{2}-5x-1\)

\(\displaystyle 6x^{4} -3x^{3}+2x^{2}-4x+6\)

\(\displaystyle 6x^{2}-4x+6\)

Correct answer:

\(\displaystyle 5x^{2}-3x+5\)

Explanation:

When we add the functions together, we can only add terms that have matching exponents.  First, let's add the terms that are squared:

\(\displaystyle 3x^{2}+2x^{2}=5x^{2}\)

Next, let's do the linear terms:

\(\displaystyle -4x + x = -3x\)

Finally, we add the constants:

\(\displaystyle 2 + 3 = 5\)

Then we collect all the terms back together:

\(\displaystyle f(x)+g(x)=5x^{2}-3x+5\)

Example Question #2222 : Mathematical Relationships And Basic Graphs

Add the following numbers:  \(\displaystyle 973+287+188\)

Possible Answers:

\(\displaystyle 1458\)

\(\displaystyle 1448\)

\(\displaystyle 1428\)

\(\displaystyle 1548\)

\(\displaystyle 1568\)

Correct answer:

\(\displaystyle 1448\)

Explanation:

Add the ones digits.

\(\displaystyle 3+7+8 = 18\)

The tens place is the carry over.

Add the tens digits with the carry over.

\(\displaystyle 7+8+8+(1) = 24\)

The tens place is the carry over for the next calculation.

Add the hundreds place with the carryover.

\(\displaystyle 9+2+1+(2)= 14\)

Combine this number with the ones digits of the previous calculations.

The answer is:  \(\displaystyle 1448\)

Example Question #4884 : Algebra Ii

Add the following numbers:  \(\displaystyle 3196+8541\)

Possible Answers:

\(\displaystyle 12737\)

\(\displaystyle 11647\)

\(\displaystyle 11637\)

\(\displaystyle 11737\)

\(\displaystyle 11727\)

Correct answer:

\(\displaystyle 11737\)

Explanation:

Add the ones digits.

\(\displaystyle 6+1=7\)

Add the tens digits.

\(\displaystyle 9+4=13\)

The carryover is the tens digit.

Add the hundreds digits with the carryover.

\(\displaystyle 1+5+(1)=7\)

Add the thousands digits.

\(\displaystyle 3+8=11\)

Combine this number with the ones digits of the previous calculations.

The answer is:  \(\displaystyle 11737\)

Example Question #13 : Addition And Subtraction

Add the following numbers:  \(\displaystyle 2167+385+1473\)

Possible Answers:

\(\displaystyle 2825\)

\(\displaystyle 3025\)

\(\displaystyle \textup{The answer is not given.}\)

\(\displaystyle 4025\)

\(\displaystyle 2625\)

Correct answer:

\(\displaystyle 4025\)

Explanation:

Add the ones digits.

\(\displaystyle 7+5+3 = 15\)

The carryover is the tens digit.

Add the tens digits with the carryover.

\(\displaystyle 6+8+7+(1)=22\)

The carryover is the tens digit.

Add the hundreds digits with the carryover.

\(\displaystyle 1+3+4+(2)=10\)

The carryover is the tens digit.

Add the thousands digits with the carryover.  The thousands digit to 385 is zero.

\(\displaystyle 2+0+1+(1)=4\)

Combine all the ones digits from each calculation.

The answer is:  \(\displaystyle 4025\)

Example Question #18 : Elementary Operations

Solve:  \(\displaystyle 1874+381\)

Possible Answers:

\(\displaystyle 4694\)

\(\displaystyle 2355\)

\(\displaystyle 2265\)

\(\displaystyle 2255\)

\(\displaystyle 1255\)

Correct answer:

\(\displaystyle 2255\)

Explanation:

Add the ones digits.

\(\displaystyle 4+1=5\)

Add the tens digits.

\(\displaystyle 7+8=15\)

The tens place will be the carryover.

Add the hundreds place with the carryover.

\(\displaystyle 8+3+(1)= 12\)

The tens place will be the carryover.

Add the thousands place with the carryover.  The thousands place of 381 is zero.

\(\displaystyle 1+0+(1)=2\)

Combine all the ones digits from each calculation.

The answer is:  \(\displaystyle 2255\)

Example Question #15 : Addition And Subtraction

Add the numbers:  \(\displaystyle 1986+3218+3971\)

Possible Answers:

\(\displaystyle 8285\)

\(\displaystyle 9185\)

\(\displaystyle 9175\)

\(\displaystyle \textup{The answer is not given.}\)

\(\displaystyle 8175\)

Correct answer:

\(\displaystyle 9175\)

Explanation:

Add the ones digits.

\(\displaystyle 6+8+1= 15\)

The carryover is the tens digit.

Add the tens digits with the carryover, one.

\(\displaystyle 8+1+7+(1)=17\)

The carryover is the tens digit.

Add the hundreds digits with the carryover, which is also one.

\(\displaystyle 9+2+9+(1) = 21\)

The carryover is the tens digit.

Add the thousands digits with the carryover, which is two.

\(\displaystyle 1+3+3+2= 9\)

Combine all the ones digits from the previous calculations.

The answer is:  \(\displaystyle 9175\)

Example Question #16 : Addition And Subtraction

Add the following numbers:  \(\displaystyle 1716+8946+1088\)

Possible Answers:

\(\displaystyle 11650\)

\(\displaystyle 11850\)

\(\displaystyle 11750\)

\(\displaystyle 10650\)

\(\displaystyle 10660\)

Correct answer:

\(\displaystyle 11750\)

Explanation:

Add the ones digits.

\(\displaystyle 6+6+8 = 20\)

The two in the tens place is the carryover.

Add the tens digits with the carryover.

\(\displaystyle 1+4+8+(2)=15\)

The one in the tens place is the carryover.

Add the hundreds places with the carryover.

\(\displaystyle 7+9+0+(1) =17\)

The one in the tens place is the carryover.

Add the thousands places with the carryover.

\(\displaystyle 1+8+1+(1) =11\)

Combine this number with the ones digits from the previous calculations.

The answer is:  \(\displaystyle 11750\)

Example Question #4891 : Algebra Ii

Add the following numbers:  \(\displaystyle 1965+3979+2013\)

Possible Answers:

\(\displaystyle 7867\)

\(\displaystyle \textup{The answer is not given.}\)

\(\displaystyle 7797\)

\(\displaystyle 7857\)

\(\displaystyle 7957\)

Correct answer:

\(\displaystyle 7957\)

Explanation:

Add the ones digits.

\(\displaystyle 5+9+3=17\)

The carryover is the tens place.

Add the tens digits with the carryover.

\(\displaystyle 6+7+1+(1)= 15\)

The carryover is the tens place.

Add the hundreds digits with the carryover.

\(\displaystyle 9+9+0+(1)=19\)

The carryover is the tens place.

Add the thousands digits with the carryover.

\(\displaystyle 1+3+2+(1)=7\)

The answer is:  \(\displaystyle 7957\)

Example Question #21 : Addition And Subtraction

Solve:  \(\displaystyle 117+981+318+996\)

Possible Answers:

\(\displaystyle 2412\)

\(\displaystyle 1921\)

\(\displaystyle 2411\)

\(\displaystyle 2301\)

\(\displaystyle 2392\)

Correct answer:

\(\displaystyle 2412\)

Explanation:

Add the ones digits.

\(\displaystyle 7+1+8+6 = 22\)

The two in the tens digit is the carryover.

Add the tens digits with the carryover.

\(\displaystyle 1+8+1+9+(2) = 21\)

The two in the tens digit is the carryover.

Add the hundreds digits with the carryover.

\(\displaystyle 1+9+3+9+(2) = 24\)

Combine this number with the ones digits from the previous calculations.

The answer is:  \(\displaystyle 2412\)

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