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AP Calculus BC : Derivative at a Point

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Example Questions

Example Question #11 : Derivative Defined As Limit Of Difference Quotient

Calculate the derivative of $f(x)=\frac{x^3}{3}-2x^2+x-3$ at the point x=3 .

Possible Answers:

Correct answer:

Explanation:

There are 2 steps to solving this problem.

First, take the derivative of f(x)

Then, replace the value of x with the given point and evaluate

For example, if x=a , then we are looking for the value of f'(x=a) , or the derivative of f(x) at x=a .

$f(x)=\frac{x^3}{3}-2x^2+x-3$

Calculate f'(x)

Derivative rules that will be needed here:

Derivative of a constant is 0. For example, $\frac{\mathrm{d} }{\mathrm{d} t} 5 = 0$
Taking a derivative on a term, or using the power rule, can be done by doing the following: $\frac{\mathrm{d} }{\mathrm{d} t} t^n = n * t^{n-1}$

f'(x)=x^2 - 4x + 1

Then, plug in the value of x and evaluate

f'(x=3)=3^2-4*3+1=-2

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Example Question #61 : Derivatives

If $f(x)=\ln(2x)$ , which of the following limits equals f'(e+1) ?

Possible Answers:

$\lim_{h \to 0} \frac{\ln(1+h)-\ln(h)}{h}$

$\lim_{h \to 0} \frac{\ln(e+1+h)-\ln(e+1)}{e+1}$

$\lim_{h \to \infty} \frac{\ln(e+1+h)-\ln(e+1)}{h}$

$\lim_{h \to \infty} \frac{\ln(e+1+h)-\ln(e+1)}{e+1}$

$\lim_{h \to 0} \frac{\ln(e+1+h)-\ln(e+1)}{h}$

Correct answer:

$\lim_{h \to 0} \frac{\ln(e+1+h)-\ln(e+1)}{h}$

Explanation:

The equation for the derivative at a point is given by

$f'(a)=\lim_{h \to 0}\frac{f(a+h)-f(a)}{h}$ .

By substituting a = e+1 , $f = \ln(2x)$ , we obtain

$f'(e+1)=\lim_{h \to 0} \frac{\ln(e+1+h)-\ln(e+1)}{h}.$

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AP Calculus BC : Derivative at a Point

Study concepts, example questions & explanations for AP Calculus BC

All AP Calculus BC Resources

Example Questions

Example Question #11 : Derivative Defined As Limit Of Difference Quotient

Example Question #61 : Derivatives

All AP Calculus BC Resources

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