AP Chemistry : AP Chemistry

Study concepts, example questions & explanations for AP Chemistry

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Example Questions

Example Question #91 : Reaction Types

Put the following acids in order of their DECREASING acid strength:  HOCl, HO2Cl, HO3Cl, HO4Cl.

Possible Answers:

HO4Cl, HOCl, HO2Cl, HO3Cl

HO4Cl, HO3Cl, HO2Cl, HOCl

HOCL, HO2Cl, HO3Cl, HO4Cl

HOCl, HO4Cl, HO2Cl, HO3Cl

HO2Cl, HOCl, HO3Cl, HO4Cl

Correct answer:

HOCL, HO2Cl, HO3Cl, HO4Cl

Explanation:

For an oxyacid, the acid strength increases as the number of oxygens increase.

Example Question #92 : Reaction Types

Put the following in order of INCREASING acid strength:  H2Se, KH, AsH3, HBr.

Possible Answers:

KH, AsH3, H2Se, HBr

KH, H2Se, AsH3, HBr

HBr, H2Se, AsH3, KH

AsH3, H2Se, HBr, KH

AsH3, H2Se, KH, HBr

Correct answer:

KH, AsH3, H2Se, HBr

Explanation:

Acid strength increases going across a period.

Example Question #91 : Reaction Types

If you have a solution that consist of a weak monoprotic acid (HA), with a pKA of 5.3 and a pH of 3.2, what is the predominant species present?

Possible Answers:

H3O+

Equal amounts of acid and conjugate base are present.

H2A+

HA

A­-

Correct answer:

HA

Explanation:

Since pH < pKa the undissociated acid is the predominant form.

Example Question #92 : Reaction Types

If you have a solution that consists of a monoprotic acid (HA), with a pKa of 4.1 and at a pH of 5.8, what is the predominant species present?

Possible Answers:

Equal amounts of acid and conjugate base are present.

H3O+

H2A+

HA

A­-

Correct answer:

A­-

Explanation:

Since pH > pKA, the deprotonated form of the acid is predominant.

Example Question #93 : Reaction Types

Carbonic acid as a pKa1 = 6.35 and a pKa2=10.33.  If the pH is 3.52, what is the predominant species present.

Possible Answers:

CO32-

Can not be determined.

HCO3-

H3O+

H2CO3

Correct answer:

H2CO3

Explanation:

Since pH < pKa1, the undissociated form of carbonic acid (H2CO3) is predominant.

Example Question #94 : Reaction Types

Sulphurous acid (H2SO3) has a pKa1 = 1.92 and a pKa2 = 7.18, if the pH = 5.3, what is the predominant species present?

Possible Answers:

HSO3-

H2SO3

Can not be determined

H3O+

SO32-

Correct answer:

HSO3-

Explanation:

Since pH > pKa1 but pH < pKa2 the predominant form is one with a single hydrogen dissociated.

Example Question #95 : Reaction Types

Phosphoric acid has a pKa1 = 2.15, a pKa2 = 7.20, and a pKa3 = 12.35.  If the pH = 13.0, what is the predominant species present?

Possible Answers:

HPO42-

Can not be determined

H3PO4

H2PO4-

PO43-

Correct answer:

PO43-

Explanation:

Since pH > pKa1, pKa2, and pKa3 the predominant form of the acid is the fully deprotonated form.

Example Question #1 : Cell Potential Under Non Standard Conditions

Consider an electrochemical cell that has the following overall reaction:

2 H+(aq) + Sn (s) -> Sn2+ (aq) + H2 (aq)

 

Which of the following changes would alter the measured cell potential?

Possible Answers:

Adding SnCl2 to the cathode.

Increasing the H2 pressure in the cathode.

Lowering the pH in the cathode.

All of the above.

Increase the pH in the cathode.

Correct answer:

All of the above.

Explanation:

All of these changes would change Q and thus change the measured cell potential.

Example Question #672 : Ap Chemistry

For the following cell reaction:

 

2 Al (s) + 3 Mn2+ (aq) -> 2 Al3+ (aq)  + 3 Mn (s)

predict if the cell potential Ecell will be larger, or smaller than Eocell for the following conditions: 

[Al3+] = 2.0 M; [Mn2+] = 1.0 M. 

Possible Answers:

Can not be determined

Smaller

Larger

Identical

Correct answer:

Smaller

Explanation:

Altering these conditions would increase Q, and thus result in a decrease in the measured cell potential.

Example Question #2 : Cell Potential Under Non Standard Conditions

For the following cell reaction:

2 Al (s) + 3 Mn2+ (aq) -> 2 Al3+ (aq)  + 3 Mn (s)

predict if the cell potential Ecell will be larger, or smaller than Eocell for the following conditions:  [Al3+] = 1.0 M; [Mn2+] = 5.0 M. 

Possible Answers:

Smaller

Can not be determined

Identical

Larger

Correct answer:

Larger

Explanation:

At these concentrations Q will become smaller, and thus log Q will become smaller.  This will give rise to a larger cell potential.

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