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Example Questions
Example Question #701 : Newtonian Mechanics
A block is held at rest at the top of slope inclined at
. When the block is let go it slides down the slope, experiencing friction along the way. If the acceleration of the block down the ramp is
, what is the coefficient of kinetic friction between the block and ramp?
Because the block is traveling on an inclined ramp and experiences friction, the two main forces at work here are a component of gravitational force and kinetic frictional force.
The total force acting on the block can be written as
, where
is the component of gravitational force in the direction of motion, and
is the kinetic frictional force.
We know that forces can be expressed as , and kinetic friction can be expressed as
. Hence our total force can be expressed as
. The normal force can be further expressed as
The component of gravity parallel to the ramp is given by , while the component of gravity perpendicular to the ramp is given by
.
Our total force can hence be expressed as .
Thus,
and
Example Question #33 : Force Of Friction
Jennifer has a mass of and is riding a rocket powered sled of mass
. The rocket produces a thrust of
and she accelerates at a rate of
. Determine the coefficient of friction between the sled and the snow underneath.
Solving for the coefficient of friction:
Example Question #34 : Force Of Friction
Consider the following scenario:
A sledder of mass is at the stop of a sledding hill at height
with a slope of angle
.
The hill has a height of and a slope
. If a 75-kilogram sledder is initially at rest at the top of the hill and reaches the bottom of the hill with a final velocity
, what is the average frictional force applied to the sledder? Neglect air resistance and any other frictional forces.
We can use the expression for conservation of energy to solve this problem:
The problem statement tells us that the sledder is initially at rest, so we can eliminate initial kinetic energy. Also, if we assume that the bottom of the hill has a height of 0, we can eliminate final potential energy to get:
(1)
From here we need to determine what is going to contribute to work. The only extra piece of information we have in this problem is that there is an average frictional force. Therefore that will be the only source of work. Let's began expanding each term, going from left to right:
(2)
Note that we didn't mark the height as an initial height because we assumed that the bottom of the hill has a height of 0.
Where d is the length of the hill. We can calculate this distance using the height and angle of the hill.
Rearranging for distance:
Substituting this back into our expression for work, we get:
(3)
Now our final term:
(4)
Now substituting expression 2, 3, and 4 into expression 1, we get:
The reason we are subtracting friction is because it is removing energy from the system. Another way we could have written our initial expression would be to have work on the final state and then friction would be positive.
Rearranging for the frictional force:
We have all of these values, so time to plug and chug:
Example Question #1 : Spring Force
A horizontal spring with a spring constant of is attached to a frictionless surface. A block of mass 2kg is attached to the end of the spring. A man spends 20J of energy to compress the spring. How far from equilibrium is the block?
You simply need to know the formula for the potential energy stored in a spring to solve this problem. The formula is:
where k is the spring constant, and x is the distance from equilibrium
We can rearrange this to get:
Plugging in our values, we get:
Example Question #1 : Spring Force
Consider the following system:
Both springs have a constant of and the block is motionless. If the bottom spring is compressed
past its equilibrium and the block has a mass of
, how far is the top spring stretched past its equilibrium?
Since the block is motionless, we know that our forces will cancel out:
There are three forces in play: one from each spring, as well as the force of gravity. If we assume that forces pointing up are positive, we can write:
Plugging in expressions for each spring force, we get:
Rearring for the displacement of the top spring, we get:
Example Question #2 : Spring Force
Consider the following system:
Both springs have a constant of and the block is motionless. If the top spring is stretched
past its point of equilibrium and the bottom spring is compressed
past its point of equilibrium, what is the mass of the block?
Since the block is motionless, we can assume that the forces cancel out:
If we designate any forces pointing downward as positive, we can write:
Inserting expressions for each force, we get:
Rearranging for mass, we get:
Example Question #131 : Forces
A spring attached to the ceiling has a block of mass attached to the other end. On Earth, the displacement of the spring when at equilibrium is
. What is the displacement of the spring at equilibirum when this system is on a planet that has a gravitational acceleration of
There are two ways to solve this problem: the first involves calculating the spring constant and the second does not. We'll go through both methods.
Calculating Spring Constant
We can use the expression for the force of a spring:
At equilibrium, the force of the spring equals the force of gravity:
Rearranging for the spring constant and plugging in values, we get:
Now, apply this equation when the spring is on a different planet:
Rearranging for displacement and plugging in values, we get:
Without Calculating Spring Constant
We can write the force equation for each scenario. Let the subscript 1 denote Earth, and 2 denote the other planet:
Using these equations, we can set up a proportion:
Rearranging for the displacement of scenario 2 and plugging in values:
Example Question #3 : Spring Force
A spring hanging from the ceiling of an elevator has a spring constant of and a block attached to the other end with a mass of
. If the elevator is accelerating upward at a rate of
and the spring is in equilibirum, what is the displacement of the spring?
Since the displacement of the spring is at equilibrium, we can write:
There are three forces we can account for: spring force, gravitational force, and the additional force resulting from the acceleration of the elevator. If we assume that forces pointing upward are positive, we can write:
If you are unsure whether the force resulting from the acceleration of the elevator will be positive or negative, think about the situtation from personal experience: When an elevator begins to accelerate upward, your body feels heavier. Thus, the force adds to the normal gravitational force.
Substituting expressions for each force, we get:
Rearrange to solve for displacement:
Example Question #2 : Spring Force
A horizontal spring with a constant of is attached to a wall at one end and has a block of mass
attached to the other end. If the system has
of potential energy and the block is on a frictionless surface, what is the maxmimum force applied by the spring?
The maxmimum force applied by the spring will occur when the mass is at its maximum displacement. Since we know the energy of the system, we can calculate displacement using the following expression:
Rearranging for displacement, we get:
We can use this, along with the expression for force applied by a spring:
Substitute our first expression into our second and simplify:
We have values for each variable, allowing us to solve for the force:
Note that the mass of the block is irrelevant to the problem. Mass does not effect displacement or force applied by the spring; it only affects the velocity of the block at different points.
Example Question #3 : Spring Force
A series of horizontal springs are attached end to end. The far left spring is attached to a wall. The constant of each spring is . If a tensile force of
applied to the right end of the series of springs results in a displacement of
for each spring, how many springs are in the series?
We simply need to alter the expression for the force of the springs to solve this problem. The following is the original expression:
Since each spring has the same costant, they actually act as one large spring with the same, original costant. Therefore the value of in this equation is the total displacement. Multiplying the displacement of each single spring by the number of total springs will give us this total displacement:
Here, is the number of springs, and this new displacement,
, is the displacement of each spring. Rearranging for the number of springs, we get:
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