Call Now to Set Up Tutoring:

(888) 888-0446

AP Physics 1 : Newtonian Mechanics

Study concepts, example questions & explanations for AP Physics 1

Create An Account

All AP Physics 1 Resources

7 Diagnostic Tests 170 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #1 : Circular And Rotational Motion

What is the difference in the angular velocity of the second hand of radius 1cm on a wristwatch, compared to the second hand of radius 5m on a large clock tower?

Possible Answers:

The clocktower second hand has an angular velocity that is 20 times faster than that of the wristwatch

No difference

The clocktower second hand has an angular velocity that is 500 times slower than that of the wristwatch

The clocktower second hand has an angular velocity that is 500 times faster than that of the wristwatch

The clocktower second hand has an angular velocity that is 5 times faster than that of the wristwatch

Correct answer:

No difference

Explanation:

The angular velocity should not change based on the radius of the second hand. No matter what size the second hand, it will still cover one revolution every minute or 60s. The linear velocity will be greater and the angular momentum will also be greater for the clocktower, but its angular velocity will be the same. This can be seen by looking at the equation for angular velocity:

$\omega=\frac{\theta}{t}$

Report an Error

Example Question #1 : Circular And Rotational Motion

A ferris wheel has a trip length of 3min, that is it takes three minutes for it to make one complete revolution. What is the angular velocity of the ferris wheel if it only takes passengers around one time, in $\frac{rad}{s}$ ?

Possible Answers:

2.094

18.85

0.35

0.035

Correct answer:

0.035

Explanation:

Angular velocity, in $\frac{rad}{s}$ , is given by the length traveled divided by the time taken to travel the length:

$\omega=\frac{\theta}{t}$

We are told that the amount of time taken to make one revolution is 3min. One revolution is equal to $2\pi\ rad$ , and 3 minutes is equal to 180 seconds. Divide the radian value by the seconds value to get the angular velocity.

$\omega =\frac{2\pi}{180}$

$\omega=0.035\frac{rad}{s}$

Report an Error

Example Question #3 : Circular And Rotational Motion

A wheel makes one full revolution every seconds and has a radius of . Determine its angular velocity .

Possible Answers:

$w=10\pi \frac{rads}{s}$

$w=\frac{\pi}{5} \frac{rads}{s}$

$w=\pi \frac{rads}{s}$

$w=5\pi \frac{rads}{s}$

Correct answer:

$w=\pi \frac{rads}{s}$

Explanation:

For this question, the angular velocity can be given by the equation:

$w=\frac{\theta}{t}$ , where $\theta$ is the angle made and is the time taken to make this angle.

In this problem, the wheel makes one full revolution( $\theta=2\pi$ ) in seconds.

Therefore:

$w=\frac{2\pi}{2s}=\pi \frac{rads}{s}$

Report an Error

Example Question #961 : Newtonian Mechanics

A CD rotates at a rate of $5\frac{rad}{s}$ in the positive counter clockwise direction. After pressing play, the disk is speeding up at a rate of $2\frac{rad}{s^2}$ . What is the angular velocity of the CD in $\frac{rad}{s}$ after 4 seconds?

Possible Answers:

$6.5 \frac{rad}{s}$

$10 \frac{rad}{s}$

$19.5 \frac{rad}{s}$

$13 \frac{rad}{s}$

$6 \frac{rad}{s}$

Correct answer:

$13 \frac{rad}{s}$

Explanation:

Given initial angular velocity, angular acceleration, and time we can easily solve for final angular velocity with:

$\omega=\omega _{0}+\alpha t$

$\omega=5\frac{rad}{s}+2\frac{rad}{s} (4)={13\frac{rad}{s}}$

Report an Error

Example Question #1001 : Ap Physics 1

If a ferris wheel has height of 100m, find the angular velocity in rotations per minute if the riders in the carts are going $7\frac{m}{s}$ .

Possible Answers:

$7.77\frac{rotations}{minute}$

$1.34 \frac{rotations}{minute}$

$1.94 \frac{rotations}{minute}$

$3.95 \frac{rotations}{minute}$

None of these

Correct answer:

$1.34 \frac{rotations}{minute}$

Explanation:

If the ferris wheel has height 100m then it must have radius 50m .

The circumference of the ferris wheel, or the distance of one rotation, is then:

$2\pi*r=C$

$2\pi*50m=C$

$2\pi*50m\approx 314m$

Convert the given velocity into meters per minute, or $\frac{m}{min}$ :

$7\frac{m}{s}*\frac{60 s}{1 min}=420\frac{m}{min}$

Find rotations per minute:

$420\frac{m}{min}*\frac{1 rotation}{314m}=\frac{1.34 rotations}{minute}$

Report an Error

Example Question #1 : Angular Velocity And Acceleration

A person of mass 95kg is riding a ferris wheel of radius 10m . The wheel is spinning at a constant angular velocity of 1rpm . Determine the linear velocity of the rider.

Possible Answers:

$\frac{1.05 meters}{second}$

$\frac{4.25 meters}{second}$

$\frac{3.25 meters}{second}$

$\frac{.86 meters}{second}$

$\frac{2.65 meters}{second}$

Correct answer:

$\frac{1.05 meters}{second}$

Explanation:

Convert $\frac{rotations}{minute}$ to $\frac{meters}{second}$ :

$1\frac{rotation}{minute}*\frac{1 minute}{60 seconds}*\frac{2*pi*10meters}{1 rotation}=\frac{1.05 meters}{second}$

Report an Error

Example Question #11 : Circular And Rotational Motion

Radius of the earth: $6.37*10^{6}m$

A train is traveling directly north at $110\frac{km}{hr}$ . Estimate its angular velocity with respect to the center of the earth.

Possible Answers:

$2.5*10^{-6} \frac{radians}{second}$

$6.2*10^{-6} \frac{radians}{second}$

$4.8*10^{-6} \frac{radians}{second}$

$7.8*10^{-6} \frac{radians}{second}$

$9.1*10^{-6} \frac{radians}{second}$

Correct answer:

$4.8*10^{-6} \frac{radians}{second}$

Explanation:

Convert $\frac{km}{hr}$ to $\frac{m}{s}$

$110\frac{km}{hr}*\frac{1hr}{3600 seconds}*\frac{1000m}{1km}=30.6\frac{m}{s}$

Use the following relationship and plug in known values:

$\omega=\frac{v}{r}$

$\omega=\frac{30.6}{6.37*10^6}$

$\omega=4.8*10^{-6} \frac{radians}{second}$

Report an Error

Example Question #12 : Circular And Rotational Motion

$1 \ \text{day on Pluto}=6.39 \ \text{days on Earth}$

Pluto radius: 1.186*10^6 m

Determine the linear velocity of someone standing on the surface of Pluto due to the rotation of the planet.

Possible Answers:

$13.5\frac{m}{s}$

$15.7\frac{m}{s}$

$2.5\frac{m}{s}$

$9.3\frac{m}{s}$

$4.3\frac{m}{s}$

Correct answer:

$13.5\frac{m}{s}$

Explanation:

Convert units of time into radians per second:

$\frac{2\pi~radians}{1~pluto~day}*\frac{1~pluto~day}{6.39~earth~days}*\frac{1 earth~ day}{24 hours}*\frac{1 hour}{3600 seconds}=\frac{1.138*10^{-5}radians}{sec}$

Convert to linear distance:

$\frac{1.138*10^{-5}radians}{second}*\frac{1.186*10^6meters}{1 radian}={13.5\frac{m}{s}}$

Report an Error

Example Question #1003 : Ap Physics 1

1~pluto~year=250~earth~years

Pluto distance to sun: $1.43*10^{9}km$

Determine the translational velocity of Pluto.

Possible Answers:

$1137\frac{m}{s}$

$717\frac{m}{s}$

$1009\frac{m}{s}$

$1454\frac{m}{s}$

$929\frac{m}{s}$

Correct answer:

$1137\frac{m}{s}$

Explanation:

$\frac{d}{t}=v$

$C=2\pi r$

Combine equations:

$\frac{2\pi r}{t}=v$

Convert to meters and seconds and plug in values:

$\frac{2\pi r}{t}=v$

$\frac{2*\pi* 1.43*10^{12}}{7.9*10^9}=v$

$v=1137\frac{m}{s}$

Report an Error

Example Question #12 : Circular And Rotational Motion

Consider the following system:

Spinning rod with masses at end

Two spherical masses, A and B, are attached to the end of a rigid rod with length l. The rod is attached to a fixed point, p, which is at a height, h, above the ground. The rod spins around the fixed point in a vertical circle that is traced in grey. $\angle c$ is the angle at which the L side of the rod makes with the horizontal at any given time ( $c=0^{\circ}$ in the figure and can be negative if mass A is above the horizontal).

As the rod rotates through the horizontal, the masses are traveling at a rate of $3\frac{m}{s}$ . What is $\angle c$ when mass A is at its highest point. Neglect air resistance and internal friction forces.

m_A = 12kg, m_B = 6kg, l = 8m, h = 10m

Note: $\angle c$ is the angle between mass A and the horizontal and thus has a range of $0^{\circ}\leq \angle c \leq 90^{\circ}$ .

$g = 10\frac{m}{s^2}$

Possible Answers:

$42.5^{\circ}$

$78.1^{\circ}$

$35.3^{\circ}$

$19.2^{\circ}$

$62.8^{\circ}$

Correct answer:

$42.5^{\circ}$

Explanation:

We can use the expression for conservation of energy to solve this problem:

E = U_i+K_i=U_f+K_f

Our initial state will be when the rod is horizontal, and our final state will be when mass A is at its highest point. If we assume that point p is at a height of 0 and the system is at rest and mass A is at its highest point, we can eliminate initial potential energy and final kinetic energy to get:

K_i = U_f

Expanding these terms and applying them to both masses, we get:

$\frac{1}{2}mv_i^2=mgh_f$

$\frac{1}{2}v_i^2(m_A+m_B) = m_Agh_{A_{f}}+m_Bgh_{B_{f}}$

We don't need to separate the velocity components for each mass since they are always traveling at the same speed. Since the masses are attached to a rigid rod that spins around its midpoint, we know that the heights of the two masses (with respect to point p) will be equal and opposite. In expression form:

h_A = -h_B

Substituting this into our equation, we get:

$\frac{1}{2}v_i^2(m_A+m_B) = m_Agh_{A_{f}}-m_Bgh_{A_{f}}$ $\frac{1}{2}v_i^2(m_A+m_B) = gh_{A_{f}}(m_A -m_B)$

Rearranging for final height, we get:

$h_{A_{f}}= \frac{v_i^2(m_A+m_B)}{g(m_A-m_B)}$

We have values for all of these variables, so time to plug and chug:

$h_{A_{f}} = \frac{\left ( 3\frac{m}{s}\right )^2(12kg+6kg)}{\left ( 10\frac{m}{s^2}\right )(12kg-6kg)}$

$h_{A_{f}}=2.7m$

Now we can use the sine function to determine what the angle c is at this point:

$sin(c^{\circ}) = \frac{opp}{hyp}$

Where the opposite side is the height we just calculated and the hypotenuse is half the length of the rod. Therefore, we get:

$sin(c^{\circ}) = \frac{h_{A_{f}}}{\frac{1}{2}l} = \frac{2h_{A_{f}}}{l}$

Taking the inverse sine of both sides, we get:

$c^{\circ}=sin^{-1}\left ( \frac{2h_{A_{f}}}{l} \right )$

Substituting in our values, we get:

$c^{\circ}=sin^{-1}\left ( \frac{2(2.7m)}{8m} \right )$

$c^{\circ} = 42.5^{\circ}$

Report an Error

View AP Physics 1 Tutors

Godswill
Certified Tutor

Rivers State University, Bachelor of Engineering, Mechanical Engineering. Texas Southern University, Master of Science, Compu...

View AP Physics 1 Tutors

Dossevi
Certified Tutor

cole Ste Genevive Versailles, Bachelor of Science, Mathematics. Institut National Polytechnique de Grenoble, Master of Scienc...

View AP Physics 1 Tutors

Scott
Certified Tutor

Florida State University, Bachelor of Science, Applied Mathematics. Florida State University, Bachelor of Science, Astrophysi...

All AP Physics 1 Resources

7 Diagnostic Tests 170 Practice Tests Question of the Day Flashcards Learn by Concept

Popular Subjects

French Tutors in Miami, GRE Tutors in San Francisco-Bay Area, Math Tutors in San Francisco-Bay Area, Physics Tutors in Philadelphia, Computer Science Tutors in Dallas Fort Worth, English Tutors in Houston, Math Tutors in New York City, Computer Science Tutors in New York City, Computer Science Tutors in Miami, Statistics Tutors in San Diego

Popular Courses & Classes

SSAT Courses & Classes in Denver, ACT Courses & Classes in Los Angeles, ACT Courses & Classes in Chicago, SAT Courses & Classes in Washington DC, SAT Courses & Classes in Boston, MCAT Courses & Classes in San Diego, ACT Courses & Classes in Phoenix, SAT Courses & Classes in Phoenix, SAT Courses & Classes in Philadelphia, ACT Courses & Classes in Dallas Fort Worth

Popular Test Prep

GMAT Test Prep in Washington DC, ISEE Test Prep in Boston, GRE Test Prep in Boston, SSAT Test Prep in Dallas Fort Worth, MCAT Test Prep in Philadelphia, SAT Test Prep in Seattle, GRE Test Prep in New York City, SSAT Test Prep in Chicago, GMAT Test Prep in Seattle, ACT Test Prep in Los Angeles

DMCA Complaint

If you believe that content available by means of the Website (as defined in our Terms of Service) infringes one or more of your copyrights, please notify us by providing a written notice (“Infringement Notice”) containing the information described below to the designated agent listed below. If Varsity Tutors takes action in response to an Infringement Notice, it will make a good faith attempt to contact the party that made such content available by means of the most recent email address, if any, provided by such party to Varsity Tutors.

Your Infringement Notice may be forwarded to the party that made the content available or to third parties such as ChillingEffects.org.

Please be advised that you will be liable for damages (including costs and attorneys’ fees) if you materially misrepresent that a product or activity is infringing your copyrights. Thus, if you are not sure content located on or linked-to by the Website infringes your copyright, you should consider first contacting an attorney.

Please follow these steps to file a notice:

You must include the following:

A physical or electronic signature of the copyright owner or a person authorized to act on their behalf; An identification of the copyright claimed to have been infringed; A description of the nature and exact location of the content that you claim to infringe your copyright, in \ sufficient detail to permit Varsity Tutors to find and positively identify that content; for example we require a link to the specific question (not just the name of the question) that contains the content and a description of which specific portion of the question – an image, a link, the text, etc – your complaint refers to; Your name, address, telephone number and email address; and A statement by you: (a) that you believe in good faith that the use of the content that you claim to infringe your copyright is not authorized by law, or by the copyright owner or such owner’s agent; (b) that all of the information contained in your Infringement Notice is accurate, and (c) under penalty of perjury, that you are either the copyright owner or a person authorized to act on their behalf.

Send your complaint to our designated agent at:

Charles Cohn Varsity Tutors LLC
101 S. Hanley Rd, Suite 300
St. Louis, MO 63105

Or fill out the form below:

Do not fill in this field

Contact Information

* Full legal name

Company name

* Phone number

* Email address

Address

* Address1

Address2

* City

* State

* Zipcode

* Country

Complaint Details

* URL of copyrighted work (where your original material is located)

* Please describe the copyrighted work so that it may be easily identified

I am the owner, or an agent authorized to act on behalf of the owner of an exclusive right that is allegedly infringed.

I have a good faith belief that the use of the material in the manner complained of is not authorized by the copyright owner, its agent, or the law.

This notification is accurate.

I acknowledge that there may be adverse legal consequences for making false or bad faith allegations of copyright infringement by using this process.

* Signature (your digital signature is legally binding)

HIGH SCHOOL

GRADUATE SCHOOL

K-8

Search 50+ Tests

math tutoring

science tutoring

foreign languages

elementary tutoring

other

Search 350+ Subjects

AP Physics 1 : Newtonian Mechanics

Study concepts, example questions & explanations for AP Physics 1

All AP Physics 1 Resources

Example Questions

Example Question #1 : Circular And Rotational Motion

Example Question #1 : Circular And Rotational Motion

Example Question #3 : Circular And Rotational Motion

Example Question #961 : Newtonian Mechanics

Example Question #1001 : Ap Physics 1

Example Question #1 : Angular Velocity And Acceleration

Example Question #11 : Circular And Rotational Motion

Example Question #12 : Circular And Rotational Motion

Example Question #1003 : Ap Physics 1

Example Question #12 : Circular And Rotational Motion

All AP Physics 1 Resources

Report an issue with this question

DMCA Complaint

Contact Information

Address

Complaint Details

Email address:
Your name:
Feedback: