We are open Saturday and Sunday!

Call Now to Set Up Tutoring:

(888) 888-0446

AP Physics 2 : Electrostatics

Study concepts, example questions & explanations for AP Physics 2

Create An Account

All AP Physics 2 Resources

6 Diagnostic Tests 149 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #11 : Electric Force In An Electric Field

A test charge of -9nC is placed in an electric field of $<-.008,-.008,.003>\frac{N}{C}$ . Determine the force on the charge.

Possible Answers:

$\overrightarrow{F}=<7.2*10^{-11},7.2*10^{-11}, -2.7*10^{-11}>N$

None of these

$\overrightarrow{F}=<7.2*10^{-11},4.5*10^{-11}, 4.5*10^{-11}>N$

$\overrightarrow{F}=<-7.2*10^{-11},-7.2*10^{-11}, 2.7*10^{-11}>N$

$\overrightarrow{F}=<6.9*10^{-11},7.2*10^{-11}, 3.8*10^{-11}>N$

Correct answer:

$\overrightarrow{F}=<-7.2*10^{-11},-7.2*10^{-11}, 2.7*10^{-11}>N$

Explanation:

The definition of electric force on a charge in an electric field is:

$\overrightarrow{F}=\overrightarrow{E}q$

$\overrightarrow{F}=<-.008,-.008,.003>\frac{N}{C}*(9*10^{-9}C)$

$\overrightarrow{F}=<-7.2*10^{-11},-7.2*10^{-11}, 2.7*10^{-11}>N$

Report an Error

Example Question #41 : Electrostatics

A test charge of 35nC is placed in an electric field of $<.007,.006,.019>\frac{N}{C}$ . Determine the force on the charge.

Possible Answers:

$\overrightarrow{F}=<6.77*10^{-10},2.3*10^{-10}, 8.7*10^{-10}>N$

$\overrightarrow{F}=<3.11*10^{-10},5.25*10^{-10}, 3.11*10^{-10}>N$

$\overrightarrow{F}=<2.10*10^{-10},1.38*10^{-10}, 9.87*10^{-10}>N$

None of these

$\overrightarrow{F}=<2.45*10^{-10},2.1*10^{-10}, 6.65*10^{-10}>N$

Correct answer:

$\overrightarrow{F}=<2.45*10^{-10},2.1*10^{-10}, 6.65*10^{-10}>N$

Explanation:

The definition of electric force on a charge in an electric field is:

$\overrightarrow{F}=\overrightarrow{E}q$

$\overrightarrow{F}=<.007,.006,.019>\frac{N}{C}*(35*10^{-9}C)$

$\overrightarrow{F}=<2.45*10^{-10},2.1*10^{-10}, 6.65*10^{-10}>N$

Report an Error

Example Question #14 : Electric Force In An Electric Field

Determine the force on a point charge of q=-33nC in an electric field of $<2.5,3.1>\frac{N}{C}$

Possible Answers:

$<7.77*10^{-9},1.02*10^{-7}>N$

$<8.25*10^{-9},1.02*10^{-7}>N$

$<-8.25*10^{-9},-1.02*10^{-7}>N$

None of these

$<-1.25*10^{-9},-8.02*10^{-7}>N$

Correct answer:

$<-8.25*10^{-9},-1.02*10^{-7}>N$

Explanation:

Use the following form of the electric force equation:

F_E=Eq

Plug in values:

$F_E=-33*10^{-9}*<2.5,3.1>\frac{N}{C}$

$F_E=<-8.25*10^{-9},-1.02*10^{-7}>N$

Report an Error

Example Question #11 : Electric Force In An Electric Field

An object deep in space of mass 50mg and charge 60nC accelerates at $1.1\frac{m}{s^2}$ . Determine the electric field at this location.

Possible Answers:

$8.44*10^3\frac{N}{C}$

$1.11*10^3\frac{N}{C}$

$4.49*10^3\frac{N}{C}$

$3.86*10^2\frac{N}{C}$

$9.17*10^2\frac{N}{C}$

Correct answer:

$9.17*10^2\frac{N}{C}$

Explanation:

Use the following equation for electric force:

F_E=Eq

Plug in values:

$50*10^{-6}*1.1=60*10^{-9}*E$

$E=9.16*10^3\frac{N}{C}$

Report an Error

Example Question #741 : Ap Physics 2

A $95\textup{ nC}$ charge of mass $55\ \mu\textup{g}$ accelerates with $<50,0>\ \frac{\textup{m}}{\textup{s}^2}$ . Determine the electric field.

Possible Answers:

$E=<48,0>\ \frac{\textup{N}}{\textup{C}}$

$E=<0,0>\ \frac{\textup{N}}{\textup{C}}$

$E=<28.9,0>\ \frac{\textup{N}}{\textup{C}}$

$E=<15,15>\ \frac{\textup{N}}{\textup{C}}$

$E=<12,9>\ \frac{\textup{N}}{\textup{C}}$

Correct answer:

$E=<28.9,0>\ \frac{\textup{N}}{\textup{C}}$

Explanation:

Using F_E=Eq and F=ma

Combining equations:

Eq=ma

Solving for

$\frac{m*a}{q}=E$

Converting $\mu g$ to , to and plugging in values

$\frac{55*10^{-9}*<50,0>}{95*10^{-9}}=E$

$E=<28.9,0>\frac{N}{C}$

Report an Error

Example Question #741 : Ap Physics 2

An observer is away from a negatively charged sphere. How will the electric field change as they move closer to the sphere?

Possible Answers:

It will increase in magnitude and flip directions

It will decrease in magnitude and have constant direction

It will increase in magnitude and have constant direction

It will flip directions constantly

None of these

Correct answer:

It will increase in magnitude and have constant direction

Explanation:

E field negative

As one moves closer to a negative charge, the electric field increases in the direction of the negative charge.

Report an Error

Example Question #751 : Ap Physics 2

Suppose I have a uniform electric field within a parallel plate capacitor with field strength of $E=41\frac{N}{C}$ .

Suppose the capacitor's plates are .5m in length and the space between the plates is 1.5cm .

Determine the magnitude of force experienced by an individual electron placed in this field and the direction. Assume the charge of an electron is $-1.602*10^{-19}C$

Possible Answers:

$6.6*10^{-18}N$ towards the negative plate

$6.6*10^{-18}N$ towards the positive plate

41N towards the positive plate

$6.6*10^{-19}N$ towards the positive plate

Correct answer:

$6.6*10^{-18}N$ towards the positive plate

Explanation:

Recall that the formula for the magnitude of force is given by:

F=|E*q|

Where is the electric field strength and is the charge.

Since the electric field strength is constant,

$F=(41 \frac{N}{C})*(1.602*10^{-19}C)=6.6*10^{-18}N$

To determine direction, remember that electrons will move towards the positively charged plates since electrons are negatively charged.

Report an Error

Example Question #41 : Electrostatics

An electron is moved in a perfect circle, with a negative point charge in the center. Determine the work done by the negative point charge.

Possible Answers:

Impossible to determine

Positive work done

Infinite work done

Negative work done

No work done

Correct answer:

No work done

Explanation:

There will be no work done. The point charge at the center is emitting an electric field towards itself. If the electron is moved in a circle around it, it will have moved perpendicular to the force the entire time, and thus no work has been done.

Report an Error

Example Question #1 : Electric Force Between Point Charges

Two charges are placed a certain distance apart such that the force that each charge experiences is 20 N. If the distance between the charges is doubled, what is the new force that each charge experiences?

Possible Answers:

10N

40N

There is no way to determine the new force

80N

Correct answer:

Explanation:

To solve this problem, we'll need to utilize the equation for the electric force:

$F_{e}=k\frac{Q_{1}Q_{2}}{r^{2}}$

We're told that the force each charge experiences is 20 N at a certain distance, but then that distance is doubled. Thus, the new electric force will be:

$F_{e}^{'}=k\frac{Q_{1}Q_{2}}{(2r)^{2}}=k\frac{Q_{1}Q_{2}}{4r^{2}}=\frac{F_{e}}{4}=\frac{20N}{4}=5N$

Report an Error

Example Question #2 : Electric Force Between Point Charges

What is the force experienced by a $20\mu C$ point charge away from a $30\mu C$ point charge?

Possible Answers:

1.08N

5.4N

0.108N

0.216N

The point charge experiences no force

Correct answer:

0.216N

Explanation:

The equation to find the force from two point charges is called Coulomb's Law.

$F=\frac{kq_1q_2}{r^2}$

In this equation, is force in Newtons, is the respective charge value in $\mu C$ , is radius in meters, and is the Coulomb constant, which has a value of $9 \cdot 10^9 \frac{N*m^2}{C^2}$ .

Now, we just plug in the numbers. Note: the charge values are in microcoulombs (the Greek letter $\mu$ , called "mu," stands for micro), which is equal to $10^{-6}$ .

$F&=\frac{kq_1q_2}{r^2}$

$F=\frac{(9\cdot 10^9\frac{N*m^2}{C^2}) \cdot (20\cdot 10^{-6}\mu C) \cdot (30 \cdot 10^{-6}\mu C)}{(5m)^2}$

F= 0.216

Therefore, the force experienced on either charge is 0.216N of force.

Report an Error

View Tutors

Abhya
Certified Tutor

O.P JINDAL GLOBAL LAW SCHOOL, Master's/Graduate, MASTERS IN LAW.

View Tutors

Vivek
Certified Tutor

University of Virginia-Main Campus, Bachelor of Science, Biology, General.

View Tutors

Soung
Certified Tutor

University of Chicago, Bachelor in Arts, Chemistry. Northwestern University, Doctor of Science, Molecular Pharmacology.

All AP Physics 2 Resources

6 Diagnostic Tests 149 Practice Tests Question of the Day Flashcards Learn by Concept

Popular Subjects

Algebra Tutors in San Francisco-Bay Area, LSAT Tutors in New York City, Algebra Tutors in Chicago, GRE Tutors in Denver, SAT Tutors in Miami, Statistics Tutors in San Diego, Statistics Tutors in Seattle, Statistics Tutors in New York City, ACT Tutors in San Diego, SAT Tutors in Washington DC

Popular Courses & Classes

LSAT Courses & Classes in Boston, SSAT Courses & Classes in San Diego, GRE Courses & Classes in Denver, SAT Courses & Classes in Philadelphia, SSAT Courses & Classes in Houston, SSAT Courses & Classes in Philadelphia, LSAT Courses & Classes in Phoenix, LSAT Courses & Classes in Miami, SSAT Courses & Classes in Miami, Spanish Courses & Classes in San Diego

Popular Test Prep

SSAT Test Prep in Philadelphia, GRE Test Prep in Denver, SSAT Test Prep in Houston, ACT Test Prep in New York City, LSAT Test Prep in New York City, SAT Test Prep in Miami, SSAT Test Prep in Boston, ISEE Test Prep in Denver, GMAT Test Prep in Miami, SAT Test Prep in Denver

DMCA Complaint

If you believe that content available by means of the Website (as defined in our Terms of Service) infringes one or more of your copyrights, please notify us by providing a written notice (“Infringement Notice”) containing the information described below to the designated agent listed below. If Varsity Tutors takes action in response to an Infringement Notice, it will make a good faith attempt to contact the party that made such content available by means of the most recent email address, if any, provided by such party to Varsity Tutors.

Your Infringement Notice may be forwarded to the party that made the content available or to third parties such as ChillingEffects.org.

Please be advised that you will be liable for damages (including costs and attorneys’ fees) if you materially misrepresent that a product or activity is infringing your copyrights. Thus, if you are not sure content located on or linked-to by the Website infringes your copyright, you should consider first contacting an attorney.

Please follow these steps to file a notice:

You must include the following:

A physical or electronic signature of the copyright owner or a person authorized to act on their behalf; An identification of the copyright claimed to have been infringed; A description of the nature and exact location of the content that you claim to infringe your copyright, in \ sufficient detail to permit Varsity Tutors to find and positively identify that content; for example we require a link to the specific question (not just the name of the question) that contains the content and a description of which specific portion of the question – an image, a link, the text, etc – your complaint refers to; Your name, address, telephone number and email address; and A statement by you: (a) that you believe in good faith that the use of the content that you claim to infringe your copyright is not authorized by law, or by the copyright owner or such owner’s agent; (b) that all of the information contained in your Infringement Notice is accurate, and (c) under penalty of perjury, that you are either the copyright owner or a person authorized to act on their behalf.

Send your complaint to our designated agent at:

Charles Cohn Varsity Tutors LLC
101 S. Hanley Rd, Suite 300
St. Louis, MO 63105

Or fill out the form below:

Do not fill in this field

Contact Information

* Full legal name

Company name

* Phone number

* Email address

Address

* Address1

Address2

* City

* State

* Zipcode

* Country

Complaint Details

* URL of copyrighted work (where your original material is located)

* Please describe the copyrighted work so that it may be easily identified

I am the owner, or an agent authorized to act on behalf of the owner of an exclusive right that is allegedly infringed.

I have a good faith belief that the use of the material in the manner complained of is not authorized by the copyright owner, its agent, or the law.

This notification is accurate.

I acknowledge that there may be adverse legal consequences for making false or bad faith allegations of copyright infringement by using this process.

* Signature (your digital signature is legally binding)

HIGH SCHOOL

GRADUATE SCHOOL

K-8

Search 50+ Tests

math tutoring

science tutoring

foreign languages

elementary tutoring

other

Search 350+ Subjects

AP Physics 2 : Electrostatics

Study concepts, example questions & explanations for AP Physics 2

All AP Physics 2 Resources

Example Questions

Example Question #11 : Electric Force In An Electric Field

Example Question #41 : Electrostatics

Example Question #14 : Electric Force In An Electric Field

Example Question #11 : Electric Force In An Electric Field

Example Question #741 : Ap Physics 2

Example Question #741 : Ap Physics 2

Example Question #751 : Ap Physics 2

Example Question #41 : Electrostatics

Example Question #1 : Electric Force Between Point Charges

Example Question #2 : Electric Force Between Point Charges

All AP Physics 2 Resources

Report an issue with this question

DMCA Complaint

Contact Information

Address

Complaint Details

Email address:
Your name:
Feedback: