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Basic Geometry : Squares

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9 Diagnostic Tests 164 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #201 : Squares

Find the perimeter of a square that has side lengths of 2.5 $\displaystyle 2.5$.

Possible Answers:

$\displaystyle 10$

$\displaystyle 20$

6.25 $\displaystyle 6.25$

$\displaystyle 5$

Correct answer:

$\displaystyle 10$

Explanation:

Use the following formula to find the perimeter of a square:

$\text{Perimeter}=4(\text{side length})$ $\displaystyle \text{Perimeter}=4(\text{side length})$

For the given square,

$\text{Perimeter}=4(2.5)=10$ $\displaystyle \text{Perimeter}=4(2.5)=10$

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Example Question #202 : Squares

Find the perimeter of a square that has side lengths 6.3 $\displaystyle 6.3$.

Possible Answers:

16.2 $\displaystyle 16.2$

18.2 $\displaystyle 18.2$

26.2 $\displaystyle 26.2$

25.2 $\displaystyle 25.2$

Correct answer:

25.2 $\displaystyle 25.2$

Explanation:

Use the following formula to find the perimeter of a square:

$\text{Perimeter}=4(\text{side length})$ $\displaystyle \text{Perimeter}=4(\text{side length})$

For the given square,

$\text{Perimeter}=4(6.3)=25.2$ $\displaystyle \text{Perimeter}=4(6.3)=25.2$

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Example Question #203 : Squares

Find the perimeter of a square that has side lengths of 12.6 $\displaystyle 12.6$.

Possible Answers:

52.4 $\displaystyle 52.4$

62.4 $\displaystyle 62.4$

50.4 $\displaystyle 50.4$

48.4 $\displaystyle 48.4$

Correct answer:

50.4 $\displaystyle 50.4$

Explanation:

Use the following formula to find the perimeter of a square:

$\text{Perimeter}=4(\text{side length})$ $\displaystyle \text{Perimeter}=4(\text{side length})$

For the given square,

$\text{Perimeter}=4(12.6)=50.4$ $\displaystyle \text{Perimeter}=4(12.6)=50.4$

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Example Question #204 : Squares

Find the perimeter of a square that has side lengths of 8.9 $\displaystyle 8.9$.

Possible Answers:

38.6 $\displaystyle 38.6$

32.6 $\displaystyle 32.6$

27.6 $\displaystyle 27.6$

35.6 $\displaystyle 35.6$

Correct answer:

35.6 $\displaystyle 35.6$

Explanation:

Use the following formula to find the perimeter of a square:

$\text{Perimeter}=4(\text{side length})$ $\displaystyle \text{Perimeter}=4(\text{side length})$

For the given square,

$\text{Perimeter}=4(8.9)=35.6$ $\displaystyle \text{Perimeter}=4(8.9)=35.6$

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Example Question #205 : Squares

Find the perimeter of a square that has side lengths of 102 $\displaystyle 102$.

Possible Answers:

608 $\displaystyle 608$

408 $\displaystyle 408$

308 $\displaystyle 308$

1020 $\displaystyle 1020$

Correct answer:

408 $\displaystyle 408$

Explanation:

Use the following formula to find the perimeter of a square:

$\text{Perimeter}=4(\text{side length})$ $\displaystyle \text{Perimeter}=4(\text{side length})$

For the given square,

$\text{Perimeter}=4(102)=408$ $\displaystyle \text{Perimeter}=4(102)=408$

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Example Question #206 : Squares

Find the perimeter of a square that has side lengths of 196.3 $\displaystyle 196.3$.

Possible Answers:

785.2 $\displaystyle 785.2$

695.2 $\displaystyle 695.2$

802.2 $\displaystyle 802.2$

762.2 $\displaystyle 762.2$

Correct answer:

785.2 $\displaystyle 785.2$

Explanation:

Use the following formula to find the perimeter of a square:

$\text{Perimeter}=4(\text{side length})$ $\displaystyle \text{Perimeter}=4(\text{side length})$

For the given square,

$\text{Perimeter}=4(196.3)=785.2$ $\displaystyle \text{Perimeter}=4(196.3)=785.2$

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Example Question #207 : Squares

Find the perimeter of a square with the side lengths of $\frac{3}{4}$ $\displaystyle \frac{3}{4}$.

Possible Answers:

$\displaystyle 4$

$\displaystyle 8$

$\displaystyle 3$

$\displaystyle 6$

Correct answer:

$\displaystyle 3$

Explanation:

Use the following formula to find the perimeter of a square:

$\text{Perimeter}=4(\text{side length})$ $\displaystyle \text{Perimeter}=4(\text{side length})$

For the given square,

$\text{Perimeter}=4\left(\frac{3}{4}\right)=3$ $\displaystyle \text{Perimeter}=4\left(\frac{3}{4}\right)=3$

In this particular case the fours cancel out and our final answer is three.

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Example Question #208 : Squares

Find the perimeter of a square with side lengths of $\frac{5}{6}$ $\displaystyle \frac{5}{6}$.

Possible Answers:

$\frac{20}{3}$ $\displaystyle \frac{20}{3}$

$\frac{10}{3}$ $\displaystyle \frac{10}{3}$

$\frac{1}{8}$ $\displaystyle \frac{1}{8}$

$\frac{5}{24}$ $\displaystyle \frac{5}{24}$

Correct answer:

$\frac{10}{3}$ $\displaystyle \frac{10}{3}$

Explanation:

Use the following formula to find the perimeter of a square:

$\text{Perimeter}=4(\text{side length})$ $\displaystyle \text{Perimeter}=4(\text{side length})$

For the given square,

$\text{Perimeter}=4\left(\frac{5}{6}\right)=\frac{20}{6}=\frac{2\cdot 10}{2\cdot 3}=\frac{10}{3}$ $\displaystyle \text{Perimeter}=4\left(\frac{5}{6}\right)=\frac{20}{6}=\frac{2\cdot 10}{2\cdot 3}=\frac{10}{3}$

Since there is a two in the numerator and a two in the denominator they cancel out which results in the simplified fraction.

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Example Question #21 : How To Find The Perimeter Of A Square

If the diagonal of a square is $12\sqrt2$ $\displaystyle 12\sqrt2$, what is the perimeter of the square?

Possible Answers:

$\displaystyle 24$

$\displaystyle 48$

$\displaystyle 96$

144 $\displaystyle 144$

Correct answer:

$\displaystyle 48$

Explanation:

The diagonal of a square is also a hypotenuse of a right triangle with the side lengths as legs of the triangle.

Use the Pythagorean Theorem to find the length of one side of the square.

$\text{Diagonal}=\sqrt{\text{side length}^2+\text{side length}^2}$ $\displaystyle \text{Diagonal}=\sqrt{\text{side length}^2+\text{side length}^2}$

$\text{Diagonal}=\sqrt{2(\text{side length})^2}$ $\displaystyle \text{Diagonal}=\sqrt{2(\text{side length})^2}$

$\text{Diagonal}=(\text{side length})\sqrt2$ $\displaystyle \text{Diagonal}=(\text{side length})\sqrt2$

$\text{Side length}=\frac{\text{Diagonal}}{\sqrt2}$ $\displaystyle \text{Side length}=\frac{\text{Diagonal}}{\sqrt2}$

For the square given in the question,

$\text{Side length}=\frac{12\sqrt2}{\sqrt{2}}$ $\displaystyle \text{Side length}=\frac{12\sqrt2}{\sqrt{2}}$

Simplify.

$\text{Side length}=12$ $\displaystyle \text{Side length}=12$

Now, recall how to find the perimeter of a square.

$\text{Perimeter}=4\times\text{side length}$ $\displaystyle \text{Perimeter}=4\times\text{side length}$

For the square in question,

$\text{Perimeter}=4\times 12$ $\displaystyle \text{Perimeter}=4\times 12$

Solve.

$\text{Perimeter}=48$ $\displaystyle \text{Perimeter}=48$

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Example Question #21 : How To Find The Perimeter Of A Square

If the diagonal of a square is $2\sqrt2$ $\displaystyle 2\sqrt2$, what is the perimeter of the square?

Possible Answers:

$\displaystyle 4$

$\displaystyle 16$

$8\sqrt2$ $\displaystyle 8\sqrt2$

$\displaystyle 8$

Correct answer:

$\displaystyle 8$

Explanation:

The diagonal of a square is also a hypotenuse of a right triangle with the side lengths as legs of the triangle.

Use the Pythagorean Theorem to find the length of one side of the square.

$\text{Diagonal}=\sqrt{\text{side length}^2+\text{side length}^2}$ $\displaystyle \text{Diagonal}=\sqrt{\text{side length}^2+\text{side length}^2}$

$\text{Diagonal}=\sqrt{2(\text{side length})^2}$ $\displaystyle \text{Diagonal}=\sqrt{2(\text{side length})^2}$

$\text{Diagonal}=(\text{side length})\sqrt2$ $\displaystyle \text{Diagonal}=(\text{side length})\sqrt2$

$\text{Side length}=\frac{\text{Diagonal}}{\sqrt2}$ $\displaystyle \text{Side length}=\frac{\text{Diagonal}}{\sqrt2}$

For the square given in the question,

$\text{Side length}=\frac{2\sqrt2}{\sqrt{2}}$ $\displaystyle \text{Side length}=\frac{2\sqrt2}{\sqrt{2}}$

Simplify.

$\text{Side length}=2$ $\displaystyle \text{Side length}=2$

Now, recall how to find the perimeter of a square.

$\text{Perimeter}=4\times\text{side length}$ $\displaystyle \text{Perimeter}=4\times\text{side length}$

For the square in question,

$\text{Perimeter}=4\times 2$ $\displaystyle \text{Perimeter}=4\times 2$

Solve.

$\text{Perimeter}=8$ $\displaystyle \text{Perimeter}=8$

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Basic Geometry : Squares

Study concepts, example questions & explanations for Basic Geometry

All Basic Geometry Resources

Example Questions

Example Question #201 : Squares

Example Question #202 : Squares

Example Question #203 : Squares

Example Question #204 : Squares

Example Question #205 : Squares

Example Question #206 : Squares

Example Question #207 : Squares

Example Question #208 : Squares

Example Question #21 : How To Find The Perimeter Of A Square

Example Question #21 : How To Find The Perimeter Of A Square

All Basic Geometry Resources

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