Biochemistry : Biochemistry

Study concepts, example questions & explanations for Biochemistry

varsity tutors app store varsity tutors android store

Example Questions

Example Question #191 : Carbohydrate Metabolism

The process of glycogenolysis is an example of __________.

Possible Answers:

Hydrolysis

Phosphorolysis

Phosphorylation

Lysis

Thiolysis

Correct answer:

Phosphorolysis

Explanation:

Phosphorolysis is the name given to the addition of phosphate across a bond. Remember that in glycogenolysis, glycogen phosphorylase adds a phosphate across the a-1,4-glycosidic bonds between the glucose units of glycogen. The result is that glucose leaves as glucose-1-phosphate. If hydrolysis were performed instead of phosphorolysis, free glucose would be severed from glycogen and would be able to leave the cell.

Example Question #3 : Alternative Pathways

Which of the following statements about glycogen phosphorylase (GP) is incorrect?

Possible Answers:

The dephosphorylated form of glycogen phosphorylase is less active.

Glucose is a competitive inhibitor of glycogen phosphorylase.

Glucose-6-phosphate is a negative regulator of glycogen phosphorylase.

AMP is an inhibitor of glycogen phosphorylase.

This enzyme is active during times of starvation.

Correct answer:

AMP is an inhibitor of glycogen phosphorylase.

Explanation:

AMP is an activator of GP, whereas ATP is an inhibitor of GP. GP cleaves the alpha 1-4 glycosidic bond between a terminal glucose molecule and the rest of the glycogen straight chain, yielding glucose-1-phosphate during glycogenolysis.

Example Question #991 : Biochemistry

Which of the following is not a possible fate of glucose-6-phosphate?

Possible Answers:

It can enter into the urea cycle

It can enter into the pentose phosphate pathway

It can become lactate

It can become pyruvate

It can become glucose

Correct answer:

It can enter into the urea cycle

Explanation:

When glycogen is broken down, the individual units that are removed are glucose-1-phosphate units. These are then transformed into glucose-6-phosphate molecules which are of extreme biological importance because of their ability to enter various different pathways. These pathways include glycolysis and the pentose phosphate pathway. The urea cycle, however, has to do with amino acids/proteins.

Example Question #992 : Biochemistry

What is the term for the end of the a glycogen branch from which glucose residues are removed during degradation?

Possible Answers:

Degradation end

Non-bonding end

Reducing end

Bonding end

Non-reducing end

Correct answer:

Non-reducing end

Explanation:

The non reducing end of a glycogen branch is the end from which glucose units are removed during degradation of glycogen.

Example Question #1 : Other Glycogenolysis Concepts

Which of the following is an example of a catabolic reaction?

Possible Answers:

Glycogenolysis

Gluconeogenesis

Protein synthesis

DNA polymerization

Correct answer:

Glycogenolysis

Explanation:

A catabolic reaction is defined as a reaction used to break down a large molecule into smaller subunits. Of the following options, glycogenolysis is the only option where a larger molecule (glycogen) is broken down into smaller subunits (individual glucose molecules).

Example Question #11 : Alternative Pathways

Which one of the following can store the largest total amount of Glycogen in the human body?

Possible Answers:

Skeletal muscle

Brain

Liver

Fat

Correct answer:

Skeletal muscle

Explanation:

Glycogen is the storage form of glucose, and is more readily accessible than starches or fats. It is used for short-term supply of glucose and in starvation conditions is used up in a matter of hours. It is mainly stored in the liver and skeletal muscle. Glycogenolysis in the liver results in glucose release into the bloodstream, whereas in the muscle the glucose is immediately used up. The highest demand for the glucose is in the muscle, and that is where most of it is stored.

Example Question #1 : Gluconeogenesis

Which enzyme(s) bypass the pyruvate kinase reaction of glycolysis in gluconeogenesis?

Possible Answers:

pyruvate carboxylase and phosphoenolpyruvate carboxykinase (PEPCK)

phosphoenolpyruvate carboxykinase (PEPCK) only

pyruvate carboxylase only

fructose bis-phosphatase only

phosphoglycerate mutase and pyruvate carboxylase

Correct answer:

pyruvate carboxylase and phosphoenolpyruvate carboxykinase (PEPCK)

Explanation:

In the first step of gluconeogenesis, pyruvate carboxylase (with ATP and bicarbonate) converts pyruvate to oxaloacetate. Then phosphoenolpyruvate carboxykinase (PEPCK) (with GTP) releases carbon dioxide to give phosphoenolpyruvate.

Example Question #1 : Gluconeogenesis

Which one of the following statements about PEP (phosphoenolpyruvate) synthesis is correct?

Possible Answers:

Pyruvate can be converted to PEP by pyruvate kinase.

Pyruvate is converted to PEP by the citric acid cycle.

Pyruvate can be converted to PEP by a combination of reactions that use energy from two different types of nucleotide triphosphate.

Pyruvate can be converted to PEP by a mutase.

Correct answer:

Pyruvate can be converted to PEP by a combination of reactions that use energy from two different types of nucleotide triphosphate.

Explanation:

GTP and ATP are used to drive the reactions that make pyruvate into PEP. Specifically, ATP catalyzes PEP carboxylase and GTP catalyzes PEP carboxykinase. A mutase moves phosphate groups already on a molecule, so it cannot be used to introduce one. The citric acid cycle can make pyruvate into any of the citric acid intermediates, but PEP isn't one of them. Pyruvate kinase is the enzyme that makes pyruvate into PEP, which is only favorable in the forward direction.

Example Question #992 : Biochemistry

In order for gluconeogenesis to generate one molecule of glucose, how many molecules of ATP and/or GTP are needed?

Possible Answers:

Correct answer:

Explanation:

Answering this question requires knowledge of the pathway of gluconeogenesis. In this pathway, non-carbohydrate carbon substrates such as lactate, pyruvate, and certain amino acids are used to generate glucose as the final product. Much of this pathway utilizes the same enzymes used in glycolysis, which is essentially the reverse of gluconeogenesis. However, it is critical to note that there are 3 reactions in glycolysis that are irreversible. Therefore, gluconeogenesis is not an exact reverse of glycolysis, and instead there are a few different enzymes in gluconeogenesis that bypass these irreversible reactions. One of the irreversible steps in glycolysis is the formation of pyruvate from phosphoenolpyruvate (PEP), catalyzed by the glycolytic enzyme pyruvate kinase. To bypass this irreversible reaction, gluconeogenesis makes use of two enzymes. First, the enzyme pyruvate carboxylase converts pyruvate into oxaloacetate, which requires the input of one molecule of ATP per molecule of pyruvate used. Next, the gluconeogenic enzyme PEP carboxykinase converts oxaloacetate into PEP, using one molecule of GTP per molecule of oxaloacetate used. The other step that requires an investment of energy is by a reaction that is reversible. The conversion of 3-phosphoglycerate into 1,3-bisphosphoglycerate (1,3-BPG) by the enzyme phosphoglycerate kinase utilizes one molecule of ATP per molecule of 1,3-BPG generated. This is a reversible reaction. Now, we can add up the energy requirements. Since each of these reactions need to occur twice in order to generate a single molecule of glucose, we'll need to multiply the energy investment by two in each step. Thus, we have two molecules of ATP from the reaction catalyzed by pyruvate carboxylase. We also have two molecules of GTP from the reaction catalyzed by PEP carboxykinase. And lastly, we have two molecules of ATP used from the reaction catalyzed by phosphoglycerate kinase. Adding all of these up, we have a total of four molecules of ATP and two molecules of GTP.

Example Question #13 : Alternative Pathways

Which of the following are true about oxaloacetate?

Possible Answers:

It can cross mitochondrial membranes

It is a lipid

It is an intermediary in glycolysis

It is an intermediary in the synthesis of glucose from lactate

It is an intermediary in the synthesis of glucose from glycerol

Correct answer:

It is an intermediary in the synthesis of glucose from lactate

Explanation:

Oxaloacetate contributes to fatty acid synthesis, but it’s not a lipid, because, among other reasons, it’s not hydrophobic. This is also why it cannot cross mitochondrial membranes. Glucose can be synthesized from glycerol, but this process occurs via dihydroxyacetone phosphate, and doesn’t involve oxaloacetate. Oxaloacetate is synthesized from pyruvate, which is the end product of glycolysis, so oxaloacetate cannot be an intermediary in glycolysis. However, lactate can be converted to pyruvate, which is the principle substrate for gluconeogenesis (sometimes called “reverse glycolysis”). In gluconeogenesis, oxaloacetate is an intermediary in the conversion of pyruvate to phosphoenolpyruvate, and so that makes it an intermediary, too, in the synthesis of glucose from lactate.

Learning Tools by Varsity Tutors