All Calculus 1 Resources
Example Questions
Example Question #303 : Equations
Find the particular solution at to the given differential equation:
To solve the differential equation, you first seperate the x and y variables:
.
Then, integrate on both sides:
which is equal to:
.
This integration was performed using the rules
and
.
(The constant 2 had no part in the integration and was therefore unchanged.) Note that there is only one constant of integration, C, in the entire equation. This is the general solution of the differential equation. We want the particular solution at the point , though. So, you plug in that point into the equation to solve for C:
. The natural log of one is zero, so
.
The final answer, which doesn't contain C, is .
Example Question #2391 : Calculus
What is the second derivative of ?
The original function can be written as
Taking the first derivative using chain rule and simplifying gives us
Now, to take the second derivative, we may either use the product rule or the quotient rule. The product rule is used arbitrarily. Either of these methods will also implement the chain rule on the term.
Simplying and finding a common denominator gives us
Example Question #2392 : Calculus
What is the derivative of ?
In the problem above, we can consider to be a composite function
, where
and
.
According to the Chain Rule, .
Applying this rule to our composite function:
.
Example Question #2393 : Calculus
What is the derivative of ?
None of the above
In the problem above, we can consider to be a composite function
, where
and
. .
According to the Chain Rule, .
Applying this rule to our composite function:
.
Example Question #51 : Solutions To Differential Equations
What is the derivative of ?
None of the above
In the problem above, we can consider to be a composite function
, where
and
.
According to the Chain Rule, .
Applying this rule to our composite function:
.
Example Question #61 : Solutions To Differential Equations
Find the solution to the differential equation
with initial value .
We can solve this by method of separating variables:
So we integrate to get
So now we plug in the initial value to get the specific solution:
So we solve for to get
. We plug this
into
to get
which becomes
after simplifying.
Example Question #61 : Solutions To Differential Equations
Find the general solution to the differential equation
.
We can use separation of variables to solve the differential equation
We have
So the general solution is , or
for
.
Example Question #63 : How To Find Solutions To Differential Equations
What is the solution to the differential equation
First, multiply both sides of the equation by dx to find
Second, integrate both sides of the equation
To integrate the right side, we can use u-substitution. Let u=sec(x). Then du=sec(x)tan(x)dx. Therefore we can rewrite the integral in terms of u as:
Next take the antiderivative of both sides
Substitute sec(x) for u to find the final solution in terms of x.
Example Question #72 : Differential Equations
Find the solution to the separable differential equation.
To solve this separable differential equation, we first need to rewrite it so that the left side is expressed entirely in terms of y and the right side in terms of x.
First factor the right side of the equation:
Next, divide both sides of the equation by y and multiply both sides of the equation by dx, which results in:
Integrate both sides of the equation:
Finally, exponentiate both sides of the equation to solve for y:
Finally, is a constant, so just write it as 'c'.
Example Question #65 : How To Find Solutions To Differential Equations
Find the derivative of the following function:
Computation of the derivative requires use of the Product Rule and the Chain Rule.
A good way to remember the Product Rule is by memorizing this saying: "First Times the Derivative of the Second, Plus the Second Times the Derivative of the First." Or if that doesn't help then you can just write out the formula:
For:
Where f(x) and g(x) are differentiable functions
As you can see, the "saying" from above matches the formula.
In this case:
,
Applying the Product Rule:
To compute the derivatives of and
, simply apply the chain rule:
For:
Where a is an integer and f(x) is a differentiable function.
Applying the Chain Rule:
Simplify the expression to match one of the answer choices:
All Calculus 1 Resources
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