We are open Saturday and Sunday!

Call Now to Set Up Tutoring:

(888) 888-0446

Calculus 2 : Riemann Sums

Study concepts, example questions & explanations for Calculus 2

Create An Account

All Calculus 2 Resources

9 Diagnostic Tests 308 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #80 : Introduction To Integrals

$\begin{align*}&\text{Calculate the Riemann sums integral approximation of :}\\&\int_{4}^{21.6}(16sin(4x))dx\\&\text{Using left points over }4\text{ intervals.}\end{align*}$

Possible Answers:

72.11

411.04

627.38

19.49

Correct answer:

72.11

Explanation:

$\begin{align*}&\text{A Riemann sum integral approximation over an interval [a, b]}\\&\text{with n subintervals follows the form:}\\&\int_a^b f(x)dx \approx \frac{b-a}{n}(f(x_1)+f(x_2)+...+f(x_n))\\&\text{It is essentially a sum of n rectangles, each with a base of}\\&\text{length :}\frac{b-a}{n}\text{ and variable heights :}f(x_i)\text{, which depend on the function value at }x_i\\&\text{We're asked to approximate}\int_{4}^{21.6}(16sin(4x))dx\\&\text{So the interval is}[4,21.6]\text{ the subintervals have length}\frac{21.6-(4)}{4}=4.4\\&\text{and since we are using the *left*point of each interval, the x-values are:}\\&[4,\frac{42}{5},\frac{64}{5},\frac{86}{5}]\\&\int_{4}^{21.6}(16sin(4x))dx=4.4[(16sin(16))+(16sin(\frac{168}{5}))+(16sin(\frac{256}{5}))+(16sin(\frac{344}{5}))]\\&\int_{4}^{21.6}(16sin(4x))dx=72.11\end{align*}$

Report an Error

Example Question #31 : Riemann Sums

$\begin{align*}&\text{Using the method of midpoint Riemann sums approximate the integral:}\\&\int_{-5}^{6.4}(4\cdot 3^x)dx\\&\text{Using }3\text{ intervals.}\end{align*}$

Possible Answers:

746.83

13644.55

2165.80

251.84

Correct answer:

2165.80

Explanation:

$\begin{align*}&\text{A Riemann sum integral approximation over an interval [a, b]}\\&\text{with n subintervals follows the form:}\\&\int_a^b f(x)dx \approx \frac{b-a}{n}(f(x_1)+f(x_2)+...+f(x_n))\\&\text{It is essentially a sum of n rectangles, each with a base of}\\&\text{length :}\frac{b-a}{n}\text{ and variable heights :}f(x_i)\text{, which depend on the function value at }x_i\\&\text{We're asked to approximate}\int_{-5}^{6.4}(4\cdot 3^x)dx\\&\text{So the interval is}[-5,6.4]\text{ the subintervals have length}\frac{6.4-(-5)}{3}=3.8\\&\text{and since we are using the *mid*point of each interval, the x-values are:}\\&[-\frac{31}{10},\frac{7}{10},\frac{9}{2}]\\&\int_{-5}^{6.4}(4\cdot 3^x)dx=3.8[(\frac{(4\cdot 3^{(\frac{9}{10})})}{81})+(4\cdot 3^{(\frac{7}{10})})+(324\cdot 3^{(\frac{1}{2})})]\\&\int_{-5}^{6.4}(4\cdot 3^x)dx=2165.80\end{align*}$

Report an Error

Example Question #82 : Introduction To Integrals

$\begin{align*}&\text{Using }4\text{ intervals, and the method of midpoint Riemann sums approximate the integral:}\\&\int_{-4}^{8.8}(-10tan(6x))dx\end{align*}$

Possible Answers:

127.96

39.71

345.50

61.70

Correct answer:

345.50

Explanation:

$\begin{align*}&\text{A Riemann sum integral approximation over an interval [a, b]}\\&\text{with n subintervals follows the form:}\\&\int_a^b f(x)dx \approx \frac{b-a}{n}(f(x_1)+f(x_2)+...+f(x_n))\\&\text{It is essentially a sum of n rectangles, each with a base of}\\&\text{length :}\frac{b-a}{n}\text{ and variable heights :}f(x_i)\text{, which depend on the function value at }x_i\\&\text{We're asked to approximate}\int_{-4}^{8.8}(-10tan(6x))dx\\&\text{So the interval is}[-4,8.8]\text{ the subintervals have length}\frac{8.8-(-4)}{4}=3.2\\&\text{and since we are using the *mid*point of each interval, the x-values are:}\\&[-\frac{12}{5},\frac{4}{5},4,\frac{36}{5}]\\&\int_{-4}^{8.8}(-10tan(6x))dx=3.2[(10tan(\frac{72}{5}))+(-10tan(\frac{24}{5}))+(-10tan(24))+(-10tan(\frac{216}{5}))]\\&\int_{-4}^{8.8}(-10tan(6x))dx=345.50\end{align*}$

Report an Error

Example Question #81 : Introduction To Integrals

$\begin{align*}&\text{Calculate the Riemann sums integral approximation of :}\\&\int_{-2}^{0.4}(-9e^{(6x)})dx\\&\text{Using midpoints over }4\text{ intervals.}\end{align*}$

Possible Answers:

-10.12

-99.14

-3.89

-1.61

Correct answer:

-10.12

Explanation:

$\begin{align*}&\text{A Riemann sum integral approximation over an interval [a, b]}\\&\text{with n subintervals follows the form:}\\&\int_a^b f(x)dx \approx \frac{b-a}{n}(f(x_1)+f(x_2)+...+f(x_n))\\&\text{It is essentially a sum of n rectangles, each with a base of}\\&\text{length :}\frac{b-a}{n}\text{ and variable heights :}f(x_i)\text{, which depend on the function value at }x_i\\&\text{We're asked to approximate}\int_{-2}^{0.4}(-9e^{(6x)})dx\\&\text{So the interval is}[-2,0.4]\text{ the subintervals have length}\frac{0.4-(-2)}{4}=0.6\\&\text{and since we are using the *mid*point of each interval, the x-values are:}\\&[-\frac{17}{10},-\frac{11}{10},-\frac{1}{2},\frac{1}{10}]\\&\int_{-2}^{0.4}(-9e^{(6x)})dx=0.6[(-9e^{(-\frac{51}{5})})+(-9e^{(-\frac{33}{5})})+(-9e^{(-3)})+(-9e^{(\frac{3}{5})})]\\&\int_{-2}^{0.4}(-9e^{(6x)})dx=-10.12\end{align*}$

Report an Error

Example Question #84 : Introduction To Integrals

$\begin{align*}&\text{Using the method of midpoint Riemann sums approximate the integral:}\\&\int_{5}^{18.2}(-cos(3x))dx\\&\text{Using }3\text{ intervals.}\end{align*}$

Possible Answers:

1.12

11.16

4.65

73.63

Correct answer:

11.16

Explanation:

$\begin{align*}&\text{A Riemann sum integral approximation over an interval [a, b]}\\&\text{with n subintervals follows the form:}\\&\int_a^b f(x)dx \approx \frac{b-a}{n}(f(x_1)+f(x_2)+...+f(x_n))\\&\text{It is essentially a sum of n rectangles, each with a base of}\\&\text{length :}\frac{b-a}{n}\text{ and variable heights :}f(x_i)\text{, which depend on the function value at }x_i\\&\text{We're asked to approximate}\int_{5}^{18.2}(-cos(3x))dx\\&\text{So the interval is}[5,18.2]\text{ the subintervals have length}\frac{18.2-(5)}{3}=4.4\\&\text{and since we are using the *mid*point of each interval, the x-values are:}\\&[\frac{36}{5},\frac{58}{5},16]\\&\int_{5}^{18.2}(-cos(3x))dx=4.4[(-cos(\frac{108}{5}))+(-cos(\frac{174}{5}))+(-cos(48))]\\&\int_{5}^{18.2}(-cos(3x))dx=11.16\end{align*}$

Report an Error

Example Question #31 : Riemann Sums

$\begin{align*}&\text{Using the method of midpoint Riemann sums approximate the integral:}\\&\int_{-2}^{2.4}(13sin(2x))dx\\&\text{Using }4\text{ intervals.}\end{align*}$

Possible Answers:

-51.73

-5.95

-20.22

-1.19

Correct answer:

-5.95

Explanation:

$\begin{align*}&\text{A Riemann sum integral approximation over an interval [a, b]}\\&\text{with n subintervals follows the form:}\\&\int_a^b f(x)dx \approx \frac{b-a}{n}(f(x_1)+f(x_2)+...+f(x_n))\\&\text{It is essentially a sum of n rectangles, each with a base of}\\&\text{length :}\frac{b-a}{n}\text{ and variable heights :}f(x_i)\text{, which depend on the function value at }x_i\\&\text{We're asked to approximate}\int_{-2}^{2.4}(13sin(2x))dx\\&\text{So the interval is}[-2,2.4]\text{ the subintervals have length}\frac{2.4-(-2)}{4}=1.1\\&\text{and since we are using the *mid*point of each interval, the x-values are:}\\&[-\frac{29}{20},-\frac{7}{20},\frac{3}{4},\frac{37}{20}]\\&\int_{-2}^{2.4}(13sin(2x))dx=1.1[(-13sin(\frac{29}{10}))+(-13sin(\frac{7}{10}))+(13sin(\frac{3}{2}))+(13sin(\frac{37}{10}))]\\&\int_{-2}^{2.4}(13sin(2x))dx=-5.95\end{align*}$

Report an Error

Example Question #83 : Introduction To Integrals

$\begin{align*}&\text{Calculate the Riemann sums integral approximation of :}\\&\int_{-5}^{0.6}(10tan(6x))dx\\&\text{Using midpoints over }4\text{ intervals.}\end{align*}$

Possible Answers:

10.71

603.79

25.16

100.63

Correct answer:

100.63

Explanation:

$\begin{align*}&\text{A Riemann sum integral approximation over an interval [a, b]}\\&\text{with n subintervals follows the form:}\\&\int_a^b f(x)dx \approx \frac{b-a}{n}(f(x_1)+f(x_2)+...+f(x_n))\\&\text{It is essentially a sum of n rectangles, each with a base of}\\&\text{length :}\frac{b-a}{n}\text{ and variable heights :}f(x_i)\text{, which depend on the function value at }x_i\\&\text{We're asked to approximate}\int_{-5}^{0.6}(10tan(6x))dx\\&\text{So the interval is}[-5,0.6]\text{ the subintervals have length}\frac{0.6-(-5)}{4}=1.4\\&\text{and since we are using the *mid*point of each interval, the x-values are:}\\&[-\frac{43}{10},-\frac{29}{10},-\frac{3}{2},-\frac{1}{10}]\\&\int_{-5}^{0.6}(10tan(6x))dx=1.4[(-10tan(\frac{129}{5}))+(-10tan(\frac{87}{5}))+(-10tan(9))+(-10tan(\frac{3}{5}))]\\&\int_{-5}^{0.6}(10tan(6x))dx=100.63\end{align*}$

Report an Error

Example Question #87 : Introduction To Integrals

$\begin{align*}&\text{Using the method of midpoint Riemann sums approximate the integral:}\\&\int_{1}^{17.8}(-10cos(6x))dx\\&\text{Using }4\text{ intervals.}\end{align*}$

Possible Answers:

-165.68

-579.87

-18.62

-977.50

Correct answer:

-165.68

Explanation:

$\begin{align*}&\text{A Riemann sum integral approximation over an interval [a, b]}\\&\text{with n subintervals follows the form:}\\&\int_a^b f(x)dx \approx \frac{b-a}{n}(f(x_1)+f(x_2)+...+f(x_n))\\&\text{It is essentially a sum of n rectangles, each with a base of}\\&\text{length :}\frac{b-a}{n}\text{ and variable heights :}f(x_i)\text{, which depend on the function value at }x_i\\&\text{We're asked to approximate}\int_{1}^{17.8}(-10cos(6x))dx\\&\text{So the interval is}[1,17.8]\text{ the subintervals have length}\frac{17.8-(1)}{4}=4.2\\&\text{and since we are using the *mid*point of each interval, the x-values are:}\\&[\frac{31}{10},\frac{73}{10},\frac{23}{2},\frac{157}{10}]\\&\int_{1}^{17.8}(-10cos(6x))dx=4.2[(-10cos(\frac{93}{5}))+(-10cos(\frac{219}{5}))+(-10cos(69))+(-10cos(\frac{471}{5}))]\\&\int_{1}^{17.8}(-10cos(6x))dx=-165.68\end{align*}$

Report an Error

Example Question #88 : Introduction To Integrals

$\begin{align*}&\text{Using the method of midpoint Riemann sums approximate the integral:}\\&\int_{5}^{15.8}(-8ln(5x))dx\\&\text{Using }4\text{ intervals.}\end{align*}$

Possible Answers:

-34.79

-337.47

-146.73

-1754.83

Correct answer:

-337.47

Explanation:

$\begin{align*}&\text{A Riemann sum integral approximation over an interval [a, b]}\\&\text{with n subintervals follows the form:}\\&\int_a^b f(x)dx \approx \frac{b-a}{n}(f(x_1)+f(x_2)+...+f(x_n))\\&\text{It is essentially a sum of n rectangles, each with a base of}\\&\text{length :}\frac{b-a}{n}\text{ and variable heights :}f(x_i)\text{, which depend on the function value at }x_i\\&\text{We're asked to approximate}\int_{5}^{15.8}(-8ln(5x))dx\\&\text{So the interval is}[5,15.8]\text{ the subintervals have length}\frac{15.8-(5)}{4}=2.7\\&\text{and since we are using the *mid*point of each interval, the x-values are:}\\&[\frac{127}{20},\frac{181}{20},\frac{47}{4},\frac{289}{20}]\\&\int_{5}^{15.8}(-8ln(5x))dx=2.7[(-8ln(\frac{127}{4}))+(-8ln(\frac{181}{4}))+(-8ln(\frac{235}{4}))+(-8ln(\frac{289}{4}))]\\&\int_{5}^{15.8}(-8ln(5x))dx=-337.47\end{align*}$

Report an Error

Example Question #81 : Introduction To Integrals

$\begin{align*}&\text{Using }4\text{ intervals, and the method of midpoint Riemann sums approximate the integral:}\\&\int_{2}^{9.2}(-7x^{2})dx\end{align*}$

Possible Answers:

-1784.66

-200.52

-356.93

-892.33

Correct answer:

-1784.66

Explanation:

$\begin{align*}&\text{A Riemann sum integral approximation over an interval [a, b]}\\&\text{with n subintervals follows the form:}\\&\int_a^b f(x)dx \approx \frac{b-a}{n}(f(x_1)+f(x_2)+...+f(x_n))\\&\text{It is essentially a sum of n rectangles, each with a base of}\\&\text{length :}\frac{b-a}{n}\text{ and variable heights :}f(x_i)\text{, which depend on the function value at }x_i\\&\text{We're asked to approximate}\int_{2}^{9.2}(-7x^{2})dx\\&\text{So the interval is}[2,9.2]\text{ the subintervals have length}\frac{9.2-(2)}{4}=1.8\\&\text{and since we are using the *mid*point of each interval, the x-values are:}\\&[\frac{29}{10},\frac{47}{10},\frac{13}{2},\frac{83}{10}]\\&\int_{2}^{9.2}(-7x^{2})dx=1.8[(-\frac{5887}{100})+(-\frac{15463}{100})+(-\frac{1183}{4})+(-\frac{48223}{100})]\\&\int_{2}^{9.2}(-7x^{2})dx=-1784.66\end{align*}$

Report an Error

View Calculus 2 Tutors

Phoenix
Certified Tutor

Spelman College, Bachelor of Science, Chemistry. University of Michigan-Ann Arbor, Doctor of Philosophy, Organic Chemistry.

View Calculus 2 Tutors

Peter
Certified Tutor

Kansas State University, Bachelors, Mathematics. Bowling Green State University-Main Campus, Master of Science, Management In...

View Calculus 2 Tutors

Steven
Certified Tutor

Florida International University, Bachelor of Science, Biology, General.

All Calculus 2 Resources

9 Diagnostic Tests 308 Practice Tests Question of the Day Flashcards Learn by Concept

Popular Subjects

Computer Science Tutors in Phoenix, Physics Tutors in Boston, Calculus Tutors in Los Angeles, GMAT Tutors in Houston, Chemistry Tutors in San Francisco-Bay Area, GMAT Tutors in Seattle, Computer Science Tutors in Philadelphia, Algebra Tutors in Houston, Spanish Tutors in Phoenix, Biology Tutors in Atlanta

Popular Courses & Classes

ISEE Courses & Classes in Dallas Fort Worth, ISEE Courses & Classes in Houston, GMAT Courses & Classes in Atlanta, MCAT Courses & Classes in San Diego, GRE Courses & Classes in Miami, Spanish Courses & Classes in Washington DC, GRE Courses & Classes in Seattle, ACT Courses & Classes in Washington DC, SSAT Courses & Classes in Seattle, MCAT Courses & Classes in Phoenix

Popular Test Prep

GRE Test Prep in New York City, ISEE Test Prep in Denver, LSAT Test Prep in Miami, MCAT Test Prep in Dallas Fort Worth, ISEE Test Prep in Houston, GMAT Test Prep in Atlanta, ISEE Test Prep in Dallas Fort Worth, GRE Test Prep in San Francisco-Bay Area, SAT Test Prep in Washington DC, SSAT Test Prep in Washington DC

DMCA Complaint

If you believe that content available by means of the Website (as defined in our Terms of Service) infringes one or more of your copyrights, please notify us by providing a written notice (“Infringement Notice”) containing the information described below to the designated agent listed below. If Varsity Tutors takes action in response to an Infringement Notice, it will make a good faith attempt to contact the party that made such content available by means of the most recent email address, if any, provided by such party to Varsity Tutors.

Your Infringement Notice may be forwarded to the party that made the content available or to third parties such as ChillingEffects.org.

Please be advised that you will be liable for damages (including costs and attorneys’ fees) if you materially misrepresent that a product or activity is infringing your copyrights. Thus, if you are not sure content located on or linked-to by the Website infringes your copyright, you should consider first contacting an attorney.

Please follow these steps to file a notice:

You must include the following:

A physical or electronic signature of the copyright owner or a person authorized to act on their behalf; An identification of the copyright claimed to have been infringed; A description of the nature and exact location of the content that you claim to infringe your copyright, in \ sufficient detail to permit Varsity Tutors to find and positively identify that content; for example we require a link to the specific question (not just the name of the question) that contains the content and a description of which specific portion of the question – an image, a link, the text, etc – your complaint refers to; Your name, address, telephone number and email address; and A statement by you: (a) that you believe in good faith that the use of the content that you claim to infringe your copyright is not authorized by law, or by the copyright owner or such owner’s agent; (b) that all of the information contained in your Infringement Notice is accurate, and (c) under penalty of perjury, that you are either the copyright owner or a person authorized to act on their behalf.

Send your complaint to our designated agent at:

Charles Cohn Varsity Tutors LLC
101 S. Hanley Rd, Suite 300
St. Louis, MO 63105

Or fill out the form below:

Do not fill in this field

Contact Information

* Full legal name

Company name

* Phone number

* Email address

Address

* Address1

Address2

* City

* State

* Zipcode

* Country

Complaint Details

* URL of copyrighted work (where your original material is located)

* Please describe the copyrighted work so that it may be easily identified

I am the owner, or an agent authorized to act on behalf of the owner of an exclusive right that is allegedly infringed.

I have a good faith belief that the use of the material in the manner complained of is not authorized by the copyright owner, its agent, or the law.

This notification is accurate.

I acknowledge that there may be adverse legal consequences for making false or bad faith allegations of copyright infringement by using this process.

* Signature (your digital signature is legally binding)

HIGH SCHOOL

GRADUATE SCHOOL

K-8

Search 50+ Tests

math tutoring

science tutoring

foreign languages

elementary tutoring

other

Search 350+ Subjects

Calculus 2 : Riemann Sums

Study concepts, example questions & explanations for Calculus 2

All Calculus 2 Resources

Example Questions

Example Question #80 : Introduction To Integrals

Example Question #31 : Riemann Sums

Example Question #82 : Introduction To Integrals

Example Question #81 : Introduction To Integrals

Example Question #84 : Introduction To Integrals

Example Question #31 : Riemann Sums

Example Question #83 : Introduction To Integrals

Example Question #87 : Introduction To Integrals

Example Question #88 : Introduction To Integrals

Example Question #81 : Introduction To Integrals

All Calculus 2 Resources

Report an issue with this question

DMCA Complaint

Contact Information

Address

Complaint Details

Email address:
Your name:
Feedback: