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Calculus 3 : 3-Dimensional Space

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Example Questions

Example Question #1932 : Calculus 3

$\begin{align*}&\text{A point in space is located, in Cartesian coordinates, at } (-125,-82,124).\\&\text{What is the position of this point in cylindrical coordinates?}\end{align*}$

Possible Answers:

$(207,-146.74^{\circ},124)$

$(149.5,-146.74^{\circ},124)$

$(207,33.26^{\circ},124)$

$(149.5,33.26^{\circ},124)$

Correct answer:

$(149.5,-146.74^{\circ},124)$

Explanation:

$\begin{align*}&\text{When converting Cartesian coordinates of the form} (x,y,z)\\&\text{to cylindrical coordinates of the form }(r,\theta,z)\text{, the first and third terms}\\& \text{are the most straightforward: }\\& r=\sqrt{x^2+y^2}\\&z=z\\&\text{However, it is prudent to be carful when calculating }\theta.\\&\text{The formula for it is as follows:}\\& \theta=arctan(\frac{y}{x})\\&\text{Remember, it is important to be mindful of the signs of }x\text{ and }y\text{, bearing in mind}\\& \text{which quadrant the point lies in; this determines the value of }\theta.\\& \text{Negative }y\text{ values lead to a negative }\theta\text{; negative }x\\&\text{values lead to }|\theta|>90^{\circ}\\&\\&\text{For our coordinates: }(-125,-82,124)\\&r=\sqrt{(-125)^2+(-82)^2}=149.5\\&\theta=arctan(\frac{-82}{-125})=-146.74^{\circ}\\&z=124\end{align*}$

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Example Question #272 : 3 Dimensional Space

$\begin{align*}&\text{A point in space is located, in Cartesian coordinates, at } (-105,98,12).\\&\text{What is the position of this point in cylindrical coordinates?}\end{align*}$

Possible Answers:

$(143.63,43.03^{\circ},12)$

$(7,43.03^{\circ},12)$

$(7,136.97^{\circ},12)$

$(143.63,136.97^{\circ},12)$

Correct answer:

$(143.63,136.97^{\circ},12)$

Explanation:

$\begin{align*}&\text{When converting Cartesian coordinates of the form} (x,y,z)\\&\text{to cylindrical coordinates of the form }(r,\theta,z)\text{, the first and third terms}\\& \text{are the most straightforward: }\\& r=\sqrt{x^2+y^2}\\&z=z\\&\text{However, it is prudent to be carful when calculating }\theta.\\&\text{The formula for it is as follows:}\\& \theta=arctan(\frac{y}{x})\\&\text{Remember, it is important to be mindful of the signs of }x\text{ and }y\text{, bearing in mind}\\& \text{which quadrant the point lies in; this determines the value of }\theta.\\& \text{Negative }y\text{ values lead to a negative }\theta\text{; negative }x\\&\text{values lead to }|\theta|>90^{\circ}\\&\\&\text{For our coordinates: }(-105,98,12)\\&r=\sqrt{(-105)^2+(98)^2}=143.63\\&\theta=arctan(\frac{98}{-105})=136.97^{\circ}\\&z=12\end{align*}$

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Example Question #273 : 3 Dimensional Space

$\begin{align*}&\text{A point in space is located, in Cartesian coordinates, at } (149,-127,-17).\\&\text{What is the position of this point in cylindrical coordinates?}\end{align*}$

Possible Answers:

$(22,-40.44^{\circ},-17)$

$(22,139.56^{\circ},-17)$

$(195.78,139.56^{\circ},-17)$

$(195.78,-40.44^{\circ},-17)$

Correct answer:

$(195.78,-40.44^{\circ},-17)$

Explanation:

$\begin{align*}&\text{When converting Cartesian coordinates of the form} (x,y,z)\\&\text{to cylindrical coordinates of the form }(r,\theta,z)\text{, the first and third terms}\\& \text{are the most straightforward: }\\& r=\sqrt{x^2+y^2}\\&z=z\\&\text{However, it is prudent to be carful when calculating }\theta.\\&\text{The formula for it is as follows:}\\& \theta=arctan(\frac{y}{x})\\&\text{Remember, it is important to be mindful of the signs of }x\text{ and }y\text{, bearing in mind}\\& \text{which quadrant the point lies in; this determines the value of }\theta.\\& \text{Negative }y\text{ values lead to a negative }\theta\text{; negative }x\\&\text{values lead to }|\theta|>90^{\circ}\\&\\&\text{For our coordinates: }(149,-127,-17)\\&r=\sqrt{(149)^2+(-127)^2}=195.78\\&\theta=arctan(\frac{-127}{149})=-40.44^{\circ}\\&z=-17\end{align*}$

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Example Question #181 : Cylindrical Coordinates

$\begin{align*}&\text{A point in space is located, in Cartesian coordinates, at } (-118,139,-149).\\&\text{What is the position of this point in cylindrical coordinates?}\end{align*}$

Possible Answers:

$(182.33,130.33^{\circ},-149)$

$(21,130.33^{\circ},-149)$

$(21,-49.67^{\circ},-149)$

$(182.33,-49.67^{\circ},-149)$

Correct answer:

$(182.33,130.33^{\circ},-149)$

Explanation:

$\begin{align*}&\text{When converting Cartesian coordinates of the form} (x,y,z)\\&\text{to cylindrical coordinates of the form }(r,\theta,z)\text{, the first and third terms}\\& \text{are the most straightforward: }\\& r=\sqrt{x^2+y^2}\\&z=z\\&\text{However, it is prudent to be carful when calculating }\theta.\\&\text{The formula for it is as follows:}\\& \theta=arctan(\frac{y}{x})\\&\text{Remember, it is important to be mindful of the signs of }x\text{ and }y\text{, bearing in mind}\\& \text{which quadrant the point lies in; this determines the value of }\theta.\\& \text{Negative }y\text{ values lead to a negative }\theta\text{; negative }x\\&\text{values lead to }|\theta|>90^{\circ}\\&\\&\text{For our coordinates: }(-118,139,-149)\\&r=\sqrt{(-118)^2+(139)^2}=182.33\\&\theta=arctan(\frac{139}{-118})=130.33^{\circ}\\&z=-149\end{align*}$

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Example Question #181 : Cylindrical Coordinates

$\begin{align*}&\text{A point in space is located, in Cartesian coordinates, at } (95,122,-112).\\&\text{What is the position of this point in cylindrical coordinates?}\end{align*}$

Possible Answers:

$(154.63,52.09^{\circ},-112)$

$(217,52.09^{\circ},-112)$

$(154.63,-127.91^{\circ},-112)$

$(217,-127.91^{\circ},-112)$

Correct answer:

$(154.63,52.09^{\circ},-112)$

Explanation:

$\begin{align*}&\text{When converting Cartesian coordinates of the form} (x,y,z)\\&\text{to cylindrical coordinates of the form }(r,\theta,z)\text{, the first and third terms}\\& \text{are the most straightforward: }\\& r=\sqrt{x^2+y^2}\\&z=z\\&\text{However, it is prudent to be carful when calculating }\theta.\\&\text{The formula for it is as follows:}\\& \theta=arctan(\frac{y}{x})\\&\text{Remember, it is important to be mindful of the signs of }x\text{ and }y\text{, bearing in mind}\\& \text{which quadrant the point lies in; this determines the value of }\theta.\\& \text{Negative }y\text{ values lead to a negative }\theta\text{; negative }x\\&\text{values lead to }|\theta|>90^{\circ}\\&\\&\text{For our coordinates: }(95,122,-112)\\&r=\sqrt{(95)^2+(122)^2}=154.63\\&\theta=arctan(\frac{122}{95})=52.09^{\circ}\\&z=-112\end{align*}$

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Example Question #182 : Cylindrical Coordinates

$\begin{align*}&\text{A point in space is located, in Cartesian coordinates, at } (124,40,-121).\\&\text{What is the position of this point in cylindrical coordinates?}\end{align*}$

Possible Answers:

$(164,17.88^{\circ},-121)$

$(130.29,17.88^{\circ},-121)$

$(164,-162.12^{\circ},-121)$

$(130.29,-162.12^{\circ},-121)$

Correct answer:

$(130.29,17.88^{\circ},-121)$

Explanation:

$\begin{align*}&\text{When converting Cartesian coordinates of the form} (x,y,z)\\&\text{to cylindrical coordinates of the form }(r,\theta,z)\text{, the first and third terms}\\& \text{are the most straightforward: }\\& r=\sqrt{x^2+y^2}\\&z=z\\&\text{However, it is prudent to be carful when calculating }\theta.\\&\text{The formula for it is as follows:}\\& \theta=arctan(\frac{y}{x})\\&\text{Remember, it is important to be mindful of the signs of }x\text{ and }y\text{, bearing in mind}\\& \text{which quadrant the point lies in; this determines the value of }\theta.\\& \text{Negative }y\text{ values lead to a negative }\theta\text{; negative }x\\&\text{values lead to }|\theta|>90^{\circ}\\&\\&\text{For our coordinates: }(124,40,-121)\\&r=\sqrt{(124)^2+(40)^2}=130.29\\&\theta=arctan(\frac{40}{124})=17.88^{\circ}\\&z=-121\end{align*}$

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Example Question #191 : Cylindrical Coordinates

$\begin{align*}&\text{A point in space is located, in Cartesian coordinates, at } (-67,14,138).\\&\text{What is the position of this point in cylindrical coordinates?}\end{align*}$

Possible Answers:

$(53,-11.8^{\circ},138)$

$(68.45,-11.8^{\circ},138)$

$(53,168.2^{\circ},138)$

$(68.45,168.2^{\circ},138)$

Correct answer:

$(68.45,168.2^{\circ},138)$

Explanation:

$\begin{align*}&\text{When converting Cartesian coordinates of the form} (x,y,z)\\&\text{to cylindrical coordinates of the form }(r,\theta,z)\text{, the first and third terms}\\& \text{are the most straightforward: }\\& r=\sqrt{x^2+y^2}\\&z=z\\&\text{However, it is prudent to be carful when calculating }\theta.\\&\text{The formula for it is as follows:}\\& \theta=arctan(\frac{y}{x})\\&\text{Remember, it is important to be mindful of the signs of }x\text{ and }y\text{, bearing in mind}\\& \text{which quadrant the point lies in; this determines the value of }\theta.\\& \text{Negative }y\text{ values lead to a negative }\theta\text{; negative }x\\&\text{values lead to }|\theta|>90^{\circ}\\&\\&\text{For our coordinates: }(-67,14,138)\\&r=\sqrt{(-67)^2+(14)^2}=68.45\\&\theta=arctan(\frac{14}{-67})=168.2^{\circ}\\&z=138\end{align*}$

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Example Question #191 : Cylindrical Coordinates

$\begin{align*}&\text{A point in space is located, in Cartesian coordinates, at } (140,-103,142).\\&\text{What is the position of this point in cylindrical coordinates?}\end{align*}$

Possible Answers:

$(37,-36.34^{\circ},142)$

$(173.81,-36.34^{\circ},142)$

$(173.81,143.66^{\circ},142)$

$(37,143.66^{\circ},142)$

Correct answer:

$(173.81,-36.34^{\circ},142)$

Explanation:

$\begin{align*}&\text{When converting Cartesian coordinates of the form} (x,y,z)\\&\text{to cylindrical coordinates of the form }(r,\theta,z)\text{, the first and third terms}\\& \text{are the most straightforward: }\\& r=\sqrt{x^2+y^2}\\&z=z\\&\text{However, it is prudent to be carful when calculating }\theta.\\&\text{The formula for it is as follows:}\\& \theta=arctan(\frac{y}{x})\\&\text{Remember, it is important to be mindful of the signs of }x\text{ and }y\text{, bearing in mind}\\& \text{which quadrant the point lies in; this determines the value of }\theta.\\& \text{Negative }y\text{ values lead to a negative }\theta\text{; negative }x\\&\text{values lead to }|\theta|>90^{\circ}\\&\\&\text{For our coordinates: }(140,-103,142)\\&r=\sqrt{(140)^2+(-103)^2}=173.81\\&\theta=arctan(\frac{-103}{140})=-36.34^{\circ}\\&z=142\end{align*}$

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Example Question #193 : Cylindrical Coordinates

$\begin{align*}&\text{A point in space is located, in Cartesian coordinates, at } (138,-4,90).\\&\text{What is the position of this point in cylindrical coordinates?}\end{align*}$

Possible Answers:

$(134,178.34^{\circ},90)$

$(138.06,-1.66^{\circ},90)$

$(134,-1.66^{\circ},90)$

$(138.06,178.34^{\circ},90)$

Correct answer:

$(138.06,-1.66^{\circ},90)$

Explanation:

$\begin{align*}&\text{When converting Cartesian coordinates of the form} (x,y,z)\\&\text{to cylindrical coordinates of the form }(r,\theta,z)\text{, the first and third terms}\\& \text{are the most straightforward: }\\& r=\sqrt{x^2+y^2}\\&z=z\\&\text{However, it is prudent to be carful when calculating }\theta.\\&\text{The formula for it is as follows:}\\& \theta=arctan(\frac{y}{x})\\&\text{Remember, it is important to be mindful of the signs of }x\text{ and }y\text{, bearing in mind}\\& \text{which quadrant the point lies in; this determines the value of }\theta.\\& \text{Negative }y\text{ values lead to a negative }\theta\text{; negative }x\\&\text{values lead to }|\theta|>90^{\circ}\\&\\&\text{For our coordinates: }(138,-4,90)\\&r=\sqrt{(138)^2+(-4)^2}=138.06\\&\theta=arctan(\frac{-4}{138})=-1.66^{\circ}\\&z=90\end{align*}$

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Example Question #194 : Cylindrical Coordinates

$\begin{align*}&\text{A point in space is located, in Cartesian coordinates, at } (-108,-24,125).\\&\text{What is the position of this point in cylindrical coordinates?}\end{align*}$

Possible Answers:

$(132,12.53^{\circ},125)$

$(132,-167.47^{\circ},125)$

$(110.63,12.53^{\circ},125)$

$(110.63,-167.47^{\circ},125)$

Correct answer:

$(110.63,-167.47^{\circ},125)$

Explanation:

$\begin{align*}&\text{When converting Cartesian coordinates of the form} (x,y,z)\\&\text{to cylindrical coordinates of the form }(r,\theta,z)\text{, the first and third terms}\\& \text{are the most straightforward: }\\& r=\sqrt{x^2+y^2}\\&z=z\\&\text{However, it is prudent to be carful when calculating }\theta.\\&\text{The formula for it is as follows:}\\& \theta=arctan(\frac{y}{x})\\&\text{Remember, it is important to be mindful of the signs of }x\text{ and }y\text{, bearing in mind}\\& \text{which quadrant the point lies in; this determines the value of }\theta.\\& \text{Negative }y\text{ values lead to a negative }\theta\text{; negative }x\\&\text{values lead to }|\theta|>90^{\circ}\\&\\&\text{For our coordinates: }(-108,-24,125)\\&r=\sqrt{(-108)^2+(-24)^2}=110.63\\&\theta=arctan(\frac{-24}{-108})=-167.47^{\circ}\\&z=125\end{align*}$

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Calculus 3 : 3-Dimensional Space

Study concepts, example questions & explanations for Calculus 3

All Calculus 3 Resources

Example Questions

Example Question #1932 : Calculus 3

Example Question #272 : 3 Dimensional Space

Example Question #273 : 3 Dimensional Space

Example Question #181 : Cylindrical Coordinates

Example Question #181 : Cylindrical Coordinates

Example Question #182 : Cylindrical Coordinates

Example Question #191 : Cylindrical Coordinates

Example Question #191 : Cylindrical Coordinates

Example Question #193 : Cylindrical Coordinates

Example Question #194 : Cylindrical Coordinates

All Calculus 3 Resources

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