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Calculus 3 : Cylindrical Coordinates

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Example Questions

Example Question #1943 : Calculus 3

$\begin{align*}&\text{A point in space is located, in Cartesian coordinates, at } (-67,14,138).\\&\text{What is the position of this point in cylindrical coordinates?}\end{align*}$

Possible Answers:

$(68.45,168.2^{\circ},138)$

$(53,168.2^{\circ},138)$

$(53,-11.8^{\circ},138)$

$(68.45,-11.8^{\circ},138)$

Correct answer:

$(68.45,168.2^{\circ},138)$

Explanation:

$\begin{align*}&\text{When converting Cartesian coordinates of the form} (x,y,z)\\&\text{to cylindrical coordinates of the form }(r,\theta,z)\text{, the first and third terms}\\& \text{are the most straightforward: }\\& r=\sqrt{x^2+y^2}\\&z=z\\&\text{However, it is prudent to be carful when calculating }\theta.\\&\text{The formula for it is as follows:}\\& \theta=arctan(\frac{y}{x})\\&\text{Remember, it is important to be mindful of the signs of }x\text{ and }y\text{, bearing in mind}\\& \text{which quadrant the point lies in; this determines the value of }\theta.\\& \text{Negative }y\text{ values lead to a negative }\theta\text{; negative }x\\&\text{values lead to }|\theta|>90^{\circ}\\&\\&\text{For our coordinates: }(-67,14,138)\\&r=\sqrt{(-67)^2+(14)^2}=68.45\\&\theta=arctan(\frac{14}{-67})=168.2^{\circ}\\&z=138\end{align*}$

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Example Question #1944 : Calculus 3

$\begin{align*}&\text{A point in space is located, in Cartesian coordinates, at } (140,-103,142).\\&\text{What is the position of this point in cylindrical coordinates?}\end{align*}$

Possible Answers:

$(37,143.66^{\circ},142)$

$(173.81,-36.34^{\circ},142)$

$(173.81,143.66^{\circ},142)$

$(37,-36.34^{\circ},142)$

Correct answer:

$(173.81,-36.34^{\circ},142)$

Explanation:

$\begin{align*}&\text{When converting Cartesian coordinates of the form} (x,y,z)\\&\text{to cylindrical coordinates of the form }(r,\theta,z)\text{, the first and third terms}\\& \text{are the most straightforward: }\\& r=\sqrt{x^2+y^2}\\&z=z\\&\text{However, it is prudent to be carful when calculating }\theta.\\&\text{The formula for it is as follows:}\\& \theta=arctan(\frac{y}{x})\\&\text{Remember, it is important to be mindful of the signs of }x\text{ and }y\text{, bearing in mind}\\& \text{which quadrant the point lies in; this determines the value of }\theta.\\& \text{Negative }y\text{ values lead to a negative }\theta\text{; negative }x\\&\text{values lead to }|\theta|>90^{\circ}\\&\\&\text{For our coordinates: }(140,-103,142)\\&r=\sqrt{(140)^2+(-103)^2}=173.81\\&\theta=arctan(\frac{-103}{140})=-36.34^{\circ}\\&z=142\end{align*}$

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Example Question #1945 : Calculus 3

$\begin{align*}&\text{A point in space is located, in Cartesian coordinates, at } (138,-4,90).\\&\text{What is the position of this point in cylindrical coordinates?}\end{align*}$

Possible Answers:

$(134,178.34^{\circ},90)$

$(138.06,-1.66^{\circ},90)$

$(134,-1.66^{\circ},90)$

$(138.06,178.34^{\circ},90)$

Correct answer:

$(138.06,-1.66^{\circ},90)$

Explanation:

$\begin{align*}&\text{When converting Cartesian coordinates of the form} (x,y,z)\\&\text{to cylindrical coordinates of the form }(r,\theta,z)\text{, the first and third terms}\\& \text{are the most straightforward: }\\& r=\sqrt{x^2+y^2}\\&z=z\\&\text{However, it is prudent to be carful when calculating }\theta.\\&\text{The formula for it is as follows:}\\& \theta=arctan(\frac{y}{x})\\&\text{Remember, it is important to be mindful of the signs of }x\text{ and }y\text{, bearing in mind}\\& \text{which quadrant the point lies in; this determines the value of }\theta.\\& \text{Negative }y\text{ values lead to a negative }\theta\text{; negative }x\\&\text{values lead to }|\theta|>90^{\circ}\\&\\&\text{For our coordinates: }(138,-4,90)\\&r=\sqrt{(138)^2+(-4)^2}=138.06\\&\theta=arctan(\frac{-4}{138})=-1.66^{\circ}\\&z=90\end{align*}$

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Example Question #1946 : Calculus 3

$\begin{align*}&\text{A point in space is located, in Cartesian coordinates, at } (-108,-24,125).\\&\text{What is the position of this point in cylindrical coordinates?}\end{align*}$

Possible Answers:

$(132,-167.47^{\circ},125)$

$(110.63,-167.47^{\circ},125)$

$(110.63,12.53^{\circ},125)$

$(132,12.53^{\circ},125)$

Correct answer:

$(110.63,-167.47^{\circ},125)$

Explanation:

$\begin{align*}&\text{When converting Cartesian coordinates of the form} (x,y,z)\\&\text{to cylindrical coordinates of the form }(r,\theta,z)\text{, the first and third terms}\\& \text{are the most straightforward: }\\& r=\sqrt{x^2+y^2}\\&z=z\\&\text{However, it is prudent to be carful when calculating }\theta.\\&\text{The formula for it is as follows:}\\& \theta=arctan(\frac{y}{x})\\&\text{Remember, it is important to be mindful of the signs of }x\text{ and }y\text{, bearing in mind}\\& \text{which quadrant the point lies in; this determines the value of }\theta.\\& \text{Negative }y\text{ values lead to a negative }\theta\text{; negative }x\\&\text{values lead to }|\theta|>90^{\circ}\\&\\&\text{For our coordinates: }(-108,-24,125)\\&r=\sqrt{(-108)^2+(-24)^2}=110.63\\&\theta=arctan(\frac{-24}{-108})=-167.47^{\circ}\\&z=125\end{align*}$

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Example Question #1947 : Calculus 3

$\begin{align*}&\text{A point in space is located, in Cartesian coordinates, at } (88,138,47).\\&\text{What is the position of this point in cylindrical coordinates?}\end{align*}$

Possible Answers:

$(163.67,57.48^{\circ},47)$

$(226,-122.52^{\circ},47)$

$(163.67,-122.52^{\circ},47)$

$(226,57.48^{\circ},47)$

Correct answer:

$(163.67,57.48^{\circ},47)$

Explanation:

$\begin{align*}&\text{When converting Cartesian coordinates of the form} (x,y,z)\\&\text{to cylindrical coordinates of the form }(r,\theta,z)\text{, the first and third terms}\\& \text{are the most straightforward: }\\& r=\sqrt{x^2+y^2}\\&z=z\\&\text{However, it is prudent to be carful when calculating }\theta.\\&\text{The formula for it is as follows:}\\& \theta=arctan(\frac{y}{x})\\&\text{Remember, it is important to be mindful of the signs of }x\text{ and }y\text{, bearing in mind}\\& \text{which quadrant the point lies in; this determines the value of }\theta.\\& \text{Negative }y\text{ values lead to a negative }\theta\text{; negative }x\\&\text{values lead to }|\theta|>90^{\circ}\\&\\&\text{For our coordinates: }(88,138,47)\\&r=\sqrt{(88)^2+(138)^2}=163.67\\&\theta=arctan(\frac{138}{88})=57.48^{\circ}\\&z=47\end{align*}$

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Example Question #191 : Cylindrical Coordinates

$\begin{align*}&\text{A point in space is located, in Cartesian coordinates, at } (-140,105,131).\\&\text{What is the position of this point in cylindrical coordinates?}\end{align*}$

Possible Answers:

$(175,143.13^{\circ},131)$

$(35,143.13^{\circ},131)$

$(35,-36.87^{\circ},131)$

$(175,-36.87^{\circ},131)$

Correct answer:

$(175,143.13^{\circ},131)$

Explanation:

$\begin{align*}&\text{When converting Cartesian coordinates of the form} (x,y,z)\\&\text{to cylindrical coordinates of the form }(r,\theta,z)\text{, the first and third terms}\\& \text{are the most straightforward: }\\& r=\sqrt{x^2+y^2}\\&z=z\\&\text{However, it is prudent to be carful when calculating }\theta.\\&\text{The formula for it is as follows:}\\& \theta=arctan(\frac{y}{x})\\&\text{Remember, it is important to be mindful of the signs of }x\text{ and }y\text{, bearing in mind}\\& \text{which quadrant the point lies in; this determines the value of }\theta.\\& \text{Negative }y\text{ values lead to a negative }\theta\text{; negative }x\\&\text{values lead to }|\theta|>90^{\circ}\\&\\&\text{For our coordinates: }(-140,105,131)\\&r=\sqrt{(-140)^2+(105)^2}=175\\&\theta=arctan(\frac{105}{-140})=143.13^{\circ}\\&z=131\end{align*}$

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Example Question #1948 : Calculus 3

$\begin{align*}&\text{A point in space is located, in Cartesian coordinates, at } (54,78,73).\\&\text{What is the position of this point in cylindrical coordinates?}\end{align*}$

Possible Answers:

$(132,-124.7^{\circ},73)$

$(94.87,-124.7^{\circ},73)$

$(94.87,55.3^{\circ},73)$

$(132,55.3^{\circ},73)$

Correct answer:

$(94.87,55.3^{\circ},73)$

Explanation:

$\begin{align*}&\text{When converting Cartesian coordinates of the form} (x,y,z)\\&\text{to cylindrical coordinates of the form }(r,\theta,z)\text{, the first and third terms}\\& \text{are the most straightforward: }\\& r=\sqrt{x^2+y^2}\\&z=z\\&\text{However, it is prudent to be carful when calculating }\theta.\\&\text{The formula for it is as follows:}\\& \theta=arctan(\frac{y}{x})\\&\text{Remember, it is important to be mindful of the signs of }x\text{ and }y\text{, bearing in mind}\\& \text{which quadrant the point lies in; this determines the value of }\theta.\\& \text{Negative }y\text{ values lead to a negative }\theta\text{; negative }x\\&\text{values lead to }|\theta|>90^{\circ}\\&\\&\text{For our coordinates: }(54,78,73)\\&r=\sqrt{(54)^2+(78)^2}=94.87\\&\theta=arctan(\frac{78}{54})=55.3^{\circ}\\&z=73\end{align*}$

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Example Question #1949 : Calculus 3

$\begin{align*}&\text{A point in space is located, in Cartesian coordinates, at } (-32,47,-99).\\&\text{What is the position of this point in cylindrical coordinates?}\end{align*}$

Possible Answers:

$(15,-55.75^{\circ},-99)$

$(56.86,-55.75^{\circ},-99)$

$(56.86,124.25^{\circ},-99)$

$(15,124.25^{\circ},-99)$

Correct answer:

$(56.86,124.25^{\circ},-99)$

Explanation:

$\begin{align*}&\text{When converting Cartesian coordinates of the form} (x,y,z)\\&\text{to cylindrical coordinates of the form }(r,\theta,z)\text{, the first and third terms}\\& \text{are the most straightforward: }\\& r=\sqrt{x^2+y^2}\\&z=z\\&\text{However, it is prudent to be carful when calculating }\theta.\\&\text{The formula for it is as follows:}\\& \theta=arctan(\frac{y}{x})\\&\text{Remember, it is important to be mindful of the signs of }x\text{ and }y\text{, bearing in mind}\\& \text{which quadrant the point lies in; this determines the value of }\theta.\\& \text{Negative }y\text{ values lead to a negative }\theta\text{; negative }x\\&\text{values lead to }|\theta|>90^{\circ}\\&\\&\text{For our coordinates: }(-32,47,-99)\\&r=\sqrt{(-32)^2+(47)^2}=56.86\\&\theta=arctan(\frac{47}{-32})=124.25^{\circ}\\&z=-99\end{align*}$

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Example Question #1951 : Calculus 3

$\begin{align*}&\text{A point in space is located, in Cartesian coordinates, at } (62,-141,-67).\\&\text{What is the position of this point in cylindrical coordinates?}\end{align*}$

Possible Answers:

$(154.03,-66.26^{\circ},-67)$

$(79,113.74^{\circ},-67)$

$(154.03,113.74^{\circ},-67)$

$(79,-66.26^{\circ},-67)$

Correct answer:

$(154.03,-66.26^{\circ},-67)$

Explanation:

$\begin{align*}&\text{When converting Cartesian coordinates of the form} (x,y,z)\\&\text{to cylindrical coordinates of the form }(r,\theta,z)\text{, the first and third terms}\\& \text{are the most straightforward: }\\& r=\sqrt{x^2+y^2}\\&z=z\\&\text{However, it is prudent to be carful when calculating }\theta.\\&\text{The formula for it is as follows:}\\& \theta=arctan(\frac{y}{x})\\&\text{Remember, it is important to be mindful of the signs of }x\text{ and }y\text{, bearing in mind}\\& \text{which quadrant the point lies in; this determines the value of }\theta.\\& \text{Negative }y\text{ values lead to a negative }\theta\text{; negative }x\\&\text{values lead to }|\theta|>90^{\circ}\\&\\&\text{For our coordinates: }(62,-141,-67)\\&r=\sqrt{(62)^2+(-141)^2}=154.03\\&\theta=arctan(\frac{-141}{62})=-66.26^{\circ}\\&z=-67\end{align*}$

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Example Question #1952 : Calculus 3

$\begin{align*}&\text{A point in space is located, in Cartesian coordinates, at } (-137,-121,97).\\&\text{What is the position of this point in cylindrical coordinates?}\end{align*}$

Possible Answers:

$(182.78,-138.55^{\circ},97)$

$(182.78,41.45^{\circ},97)$

$(258,41.45^{\circ},97)$

$(258,-138.55^{\circ},97)$

Correct answer:

$(182.78,-138.55^{\circ},97)$

Explanation:

$\begin{align*}&\text{When converting Cartesian coordinates of the form} (x,y,z)\\&\text{to cylindrical coordinates of the form }(r,\theta,z)\text{, the first and third terms}\\& \text{are the most straightforward: }\\& r=\sqrt{x^2+y^2}\\&z=z\\&\text{However, it is prudent to be carful when calculating }\theta.\\&\text{The formula for it is as follows:}\\& \theta=arctan(\frac{y}{x})\\&\text{Remember, it is important to be mindful of the signs of }x\text{ and }y\text{, bearing in mind}\\& \text{which quadrant the point lies in; this determines the value of }\theta.\\& \text{Negative }y\text{ values lead to a negative }\theta\text{; negative }x\\&\text{values lead to }|\theta|>90^{\circ}\\&\\&\text{For our coordinates: }(-137,-121,97)\\&r=\sqrt{(-137)^2+(-121)^2}=182.78\\&\theta=arctan(\frac{-121}{-137})=-138.55^{\circ}\\&z=97\end{align*}$

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Calculus 3 : Cylindrical Coordinates

Study concepts, example questions & explanations for Calculus 3

All Calculus 3 Resources

Example Questions

Example Question #1943 : Calculus 3

Example Question #1944 : Calculus 3

Example Question #1945 : Calculus 3

Example Question #1946 : Calculus 3

Example Question #1947 : Calculus 3

Example Question #191 : Cylindrical Coordinates

Example Question #1948 : Calculus 3

Example Question #1949 : Calculus 3

Example Question #1951 : Calculus 3

Example Question #1952 : Calculus 3

All Calculus 3 Resources

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