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Calculus 3 : Matrices

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6 Diagnostic Tests 373 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #151 : Matrices

Find the determinant of the 2x2 matrix $\begin{bmatrix} -1& 8\\ 3&5 \end{bmatrix}$

Possible Answers:

Correct answer:

Explanation:

To find the determinant of a 2x2 matrix $a=\begin{bmatrix} x&y \\ z&q \end{bmatrix}$ , we apply the definition:

determinant=xq-zy

Using the matrix from the problem statement, we get

(-1*5)-(3*8)=-29

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Example Question #152 : Matrices

Find the determinant of the 2x2 matrix $\begin{bmatrix} 6&4\\ 1& 5 \end{bmatrix}$

Possible Answers:

Correct answer:

Explanation:

To find the determinant of a 2x2 matrix $a=\begin{bmatrix} w&x \\ y&z \end{bmatrix}$ , we use the formula

determinant=wz-yx

Applying to the matrix from the problem statement, we get

(6*5)-(1*4)=26

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Example Question #153 : Matrices

Find the determinant of the 2x2 matrix $\begin{bmatrix} 8&1 \\ 7& 2 \end{bmatrix}$

Possible Answers:

Correct answer:

Explanation:

To find the determinant of a 2x2 matrix $a=\begin{bmatrix} w&x \\ y&z \end{bmatrix}$ , we use the formula

determinant=wz-yx

Applying to the matrix from the problem statement, we get

(8*2)-(7*1)=9

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Example Question #154 : Matrices

Find the determinant of the 3x3 matrix given:

$\begin{bmatrix} 5&-5 &0 \\ 2&4 &7 \\ 1& 1& -2 \end{bmatrix}$

Possible Answers:

130

Correct answer:

Explanation:

To find the determinant of a 3x3 matrix $m=\begin{bmatrix} x&y &z\\ a_1&a_2 &a_3 \\ b_1& b_2&b_3 \end{bmatrix}$ . determinant=x(a_2b_3-b_2a_3)-y(a_1b_3-b_1a_3)+z(a_1b_2-b_1a_2)

Using the vectors from the problem statement, we get

determinant=5(-8-7)+5(-4-7)+0(2-4)=-130

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Example Question #747 : Vectors And Vector Operations

Find the determinant of the 3x3 matrix given:

$\begin{bmatrix} 1&-3 &1 \\ 3&-2 &1 \\ 4& 0& 5 \end{bmatrix}$

Possible Answers:

Correct answer:

Explanation:

To find the determinant of a 3x3 matrix $m=\begin{bmatrix} x&y &z\\ a_1&a_2 &a_3 \\ b_1& b_2&b_3 \end{bmatrix}$ . determinant=x(a_2b_3-b_2a_3)-y(a_1b_3-b_1a_3)+z(a_1b_2-b_1a_2)

Using the vectors from the problem statement, we get

determinant=1(-10-0)+3(15-4)+1(0+8)=31

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Example Question #747 : Vectors And Vector Operations

Find the determinant of the 3x3 matrix $\begin{bmatrix} -4&7 &1 \\ 3&0 &2 \\ -2&2 & 5 \end{bmatrix}$

Possible Answers:

155

121

Correct answer:

Explanation:

To find the determinant of a 3x3 matrix $M=\begin{bmatrix} x&y &z \\ a_1&a_2 &a_3 \\ b_1& b_2&b_3 \end{bmatrix}$ , you use the formula

determinant(M)=x(a_2b_3-b_2a_3)-y(a_1b_3-b_1a_3)+z(a_1b_2-b_1a_2)

Using the matrix from the problem statement, we get

-4(0-4)-7(15+4)+1(6-0)=-111

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Example Question #2752 : Calculus 3

Find the determinant of the 3x3 matrix $\begin{bmatrix} 1&0 &1 \\ 12&2 &4 \\ 5&10 &3 \end{bmatrix}$

Possible Answers:

100

Correct answer:

Explanation:

To find the determinant of a 3x3 matrix $M=\begin{bmatrix} x&y &z \\ a_1&a_2 &a_3 \\ b_1& b_2&b_3 \end{bmatrix}$ , you use the formula

determinant(M)=x(a_2b_3-b_2a_3)-y(a_1b_3-b_1a_3)+z(a_1b_2-b_1a_2)

Using the matrix from the problem statement, we get

1(6-40)-0(36-20)+1(120-10)=76

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Example Question #2753 : Calculus 3

Find the determinant of the matrix $\begin{bmatrix} \hat{i}&\hat{j} &\hat{k} \\ 1&-5 &3 \\ 2& 7& 0 \end{bmatrix}$

Possible Answers:

$\left \langle -21,6,17\right \rangle$

$\left \langle -21,9,17\right \rangle$

$\left \langle -21,-6,17\right \rangle$

$\left \langle -20,6,14\right \rangle$

Correct answer:

$\left \langle -21,6,17\right \rangle$

Explanation:

To find the determinant of a 3x3 matrix $m=\begin{bmatrix} x& y & z\\ a_1&a_2 &a_3 \\ b_1& b_2& b_3 \end{bmatrix}$ , we use the formula

determinant(m)=x(a_2b_3-b_2a_3)-y(a_1b_3-b_1a_3)+z(a_1b_2-b_1a_2)

Using the matrix from the problem statement, we get

$\hat{i}(0-21)-\hat{j}(0-6)+\hat{k}(7+10)=\left \langle -21,6,17\right \rangle$

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Example Question #155 : Matrices

Calculate the determinant of Matrix .

$A=\begin{bmatrix} 1 & 2&3 \\ 0& 2& 1\\ 3& 4& 5 \end{bmatrix}$

Possible Answers:

$\det(A)=-2$

$\det(A)=-6$

$\det(A)=0$

$\det(A)=1$

$\det(A)=6$

Correct answer:

$\det(A)=-6$

Explanation:

In order to find the determinant of , we first need to copy down the first two columns into columns 4 and 5.

$A=\begin{bmatrix} 1 & 2&3 & 1 &2\\ 0& 2& 1&0 &2\\ 3& 4& 5 &3 &4\end{bmatrix}$

The next step is to multiply the down diagonals.

$A_d=1\cdot2\cdot5+2\cdot1\cdot 3+3\cdot0\cdot4=10+6+0=16$

The next step is to multiply the up diagonals.

$A_u=3\cdot2\cdot3+4\cdot1\cdot1+5\cdot0\cdot2=18+4=22$

The last step is to substract A_u from A_d .

$\det(A)=A_d-A_u=16-22=-6$

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Example Question #154 : Matrices

Calculate the determinant of Matrix .

$A=\begin{bmatrix} 1 & 2&3 \\ 0& 2& 1\\ 3& 4& 5 \end{bmatrix}$

Possible Answers:

$\det(A)=-6$

$\det(A)=-2$

$\det(A)=1$

$\det(A)=0$

$\det(A)=6$

Correct answer:

$\det(A)=-6$

Explanation:

In order to find the determinant of , we first need to copy down the first two columns into columns 4 and 5.

$A=\begin{bmatrix} 1 & 2&3 & 1 &2\\ 0& 2& 1&0 &2\\ 3& 4& 5 &3 &4\end{bmatrix}$

The next step is to multiply the down diagonals.

$A_d=1\cdot2\cdot5+2\cdot1\cdot 3+3\cdot0\cdot4=10+6+0=16$

The next step is to multiply the up diagonals.

$A_u=3\cdot2\cdot3+4\cdot1\cdot1+5\cdot0\cdot2=18+4=22$

The last step is to substract A_u from A_d .

$\det(A)=A_d-A_u=16-22=-6$

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Calculus 3 : Matrices

Study concepts, example questions & explanations for Calculus 3

All Calculus 3 Resources

Example Questions

Example Question #151 : Matrices

Example Question #152 : Matrices

Example Question #153 : Matrices

Example Question #154 : Matrices

Example Question #747 : Vectors And Vector Operations

Example Question #747 : Vectors And Vector Operations

Example Question #2752 : Calculus 3

Example Question #2753 : Calculus 3

Example Question #155 : Matrices

Example Question #154 : Matrices

All Calculus 3 Resources

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