Common Core: 3rd Grade Math : Measurement and Estimation

Study concepts, example questions & explanations for Common Core: 3rd Grade Math

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Example Questions

Example Question #111 : Measurement And Estimation

Megan is working on a science experiment. Using the scale below, how much water will she have if she adds \(\displaystyle 18\) more grams of water? 


19 g

Possible Answers:

\(\displaystyle 37g\)

\(\displaystyle 31g\)

\(\displaystyle 42g\)

\(\displaystyle 50g\)

\(\displaystyle 46g\)

Correct answer:

\(\displaystyle 37g\)

Explanation:

Megan has \(\displaystyle 19g\) of water and when she adds \(\displaystyle 18g\) she will have \(\displaystyle 37g\)

\(\displaystyle 19g+18g=37g\)

Example Question #112 : Measurement And Estimation

Megan is working on a science experiment. She needs to evenly divide the water shown in the beaker below into \(\displaystyle 3\) smaller beakers. How much water will be in each beaker? 

36 g

 

Possible Answers:

\(\displaystyle 9g\)

\(\displaystyle 11g\)

\(\displaystyle 10g\)

\(\displaystyle 12g\)

\(\displaystyle 8g\)

Correct answer:

\(\displaystyle 12g\)

Explanation:

Megan has \(\displaystyle 36g\) of water. We can divide \(\displaystyle 36\) by \(\displaystyle 3\) because she is splitting up the \(\displaystyle 36g\) into \(\displaystyle 3\) beakers. 

\(\displaystyle 36\div3=12g\)

Example Question #113 : Measurement And Estimation

Megan is working on a science experiment. She needs to evenly divide the water shown in the beaker below into \(\displaystyle 3\) smaller beakers. How much water will be in each beaker? 

27 g

Possible Answers:

\(\displaystyle 12g\)

\(\displaystyle 9g\)

\(\displaystyle 11g\)

\(\displaystyle 10g\)

\(\displaystyle 13g\)

Correct answer:

\(\displaystyle 9g\)

Explanation:

Megan has \(\displaystyle 27g\) of water. We can divide \(\displaystyle 27\) by \(\displaystyle 3\) because she is splitting up the \(\displaystyle 27\) into \(\displaystyle 3\) beakers. 

\(\displaystyle 27\div3=9g\)

Example Question #114 : Measurement And Estimation

Megan is working on a science experiment. She needs to evenly divide the water shown in the beaker below into \(\displaystyle 3\) smaller beakers. How much water will be in each beaker? 

18 g

Possible Answers:

\(\displaystyle 5g\)

\(\displaystyle 6g\)

\(\displaystyle 7g\)

\(\displaystyle 4g\)

\(\displaystyle 8g\)

Correct answer:

\(\displaystyle 6g\)

Explanation:

Megan has \(\displaystyle 18g\) of water. We can divide \(\displaystyle 36\) by \(\displaystyle 3\) because she is splitting up the \(\displaystyle 18g\) into \(\displaystyle 3\) beakers. 

\(\displaystyle 18\div3=6g\)

Example Question #115 : Measurement And Estimation

Megan is working on a science experiment. She needs \(\displaystyle 4\) times the amount of water that she has shown on the scale below. How much water does she need?  

15 g

Possible Answers:

\(\displaystyle 45g\)

\(\displaystyle 60g\)

\(\displaystyle 50g\)

\(\displaystyle 40g\)

\(\displaystyle 55g\)

Correct answer:

\(\displaystyle 60g\)

Explanation:

Megan has \(\displaystyle 15g\). If she needs \(\displaystyle 4\) times that amount, we can multiply to find our answer. 

\(\displaystyle \frac{\begin{array}[b]{r}15\\ \times\ 4\end{array}}{ \ \ \ \ \space 60g}\)

Example Question #116 : Measurement And Estimation

Megan is working on a science experiment. She needs \(\displaystyle 4\) times the amount of water that she has shown on the scale below. How much water does she need?  

19 g

Possible Answers:

\(\displaystyle 76g\)

\(\displaystyle 82g\)

\(\displaystyle 84g\)

\(\displaystyle 72g\)

\(\displaystyle 70g\)

Correct answer:

\(\displaystyle 76g\)

Explanation:

Megan has \(\displaystyle 19g\). If she needs \(\displaystyle 4\) times that amount, we can multiply to find our answer. 

\(\displaystyle \frac{\begin{array}[b]{r}19\\ \times\ 4\end{array}}{ \ \ \ \space 76g}\)

Example Question #117 : Measurement And Estimation

Megan is working on a science experiment. She needs to have \(\displaystyle 38 \ \space grams (g)\) of water. Based on the scale below, how much more water does she need to add?


15 g

Possible Answers:

\(\displaystyle 20g\)

\(\displaystyle 21g\)

\(\displaystyle 19g\)

\(\displaystyle 23g\)

\(\displaystyle 22g\)

Correct answer:

\(\displaystyle 23g\)

Explanation:

Megan has \(\displaystyle 15g\) of water, but she needs \(\displaystyle 38\). To find out how much more she needs we subtract. 

\(\displaystyle 38g-15g=23g\)

Example Question #118 : Measurement And Estimation

Megan is working on a science experiment. She needs to have \(\displaystyle 17 \ \space grams (g)\) of water. Based on the scale below, how much more water does she need to add?

11 g

Possible Answers:

\(\displaystyle 10g\)

\(\displaystyle 12g\)

\(\displaystyle 7g\)

\(\displaystyle 9g\)

\(\displaystyle 6g\)

Correct answer:

\(\displaystyle 6g\)

Explanation:

Megan has \(\displaystyle 11g\) of water, but she needs \(\displaystyle 17g\). To find out how much more she needs we subtract. 

\(\displaystyle 17g-11g=6g\)

Example Question #119 : Measurement And Estimation

Megan is working on a science experiment. She needs to have \(\displaystyle 42 \ \space grams (g)\) of water. Based on the scale below, how much more water does she need to add?


19 g

Possible Answers:

\(\displaystyle 23g\)

\(\displaystyle 22g\)

\(\displaystyle 21g\)

\(\displaystyle 24g\)

\(\displaystyle 25g\)

Correct answer:

\(\displaystyle 23g\)

Explanation:

Megan has \(\displaystyle 19g\) of water, but she needs \(\displaystyle 42g\). To find out how much more she needs we subtract. 

\(\displaystyle 42g-19g=23g\)

Example Question #120 : Measurement And Estimation

Megan is working on a science experiment. She needs \(\displaystyle 4\) times the amount of water that she has shown on the scale below. How much water does she need?  

11 g

Possible Answers:

\(\displaystyle 56g\)

\(\displaystyle 44g\)

\(\displaystyle 52g\)

\(\displaystyle 40g\)

\(\displaystyle 48g\)

Correct answer:

\(\displaystyle 44g\)

Explanation:

Megan has \(\displaystyle 11g\) of water. If she needs \(\displaystyle 4\) times that amount, we can multiply to find our answer. 

\(\displaystyle \frac{\begin{array}[b]{r}11\\ \times\ 4\end{array}}{ \ \ \ \ \ \space 44g}\)

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