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Common Core: 3rd Grade Math : Measurement & Data

Study concepts, example questions & explanations for Common Core: 3rd Grade Math

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All Common Core: 3rd Grade Math Resources

7 Diagnostic Tests 226 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #41 : Measurement & Data

When Aubtin got home from school he immediately started watching a television show. He watched the show for $\displaystyle 1$ hour and $\displaystyle 45$ minutes. If it is 5:56 $\displaystyle 5:56$ when he stops watching the show, what time did he start watching the show?

Possible Answers:

4:23 $\displaystyle 4:23$

3:19 $\displaystyle 3:19$

5:11 $\displaystyle 5:11$

3:42 $\displaystyle 3:42$

4:11 $\displaystyle 4:11$

Correct answer:

4:11 $\displaystyle 4:11$

Explanation:

For this problem we are subtracting to find a previous time.

We can subtract $\displaystyle 1$ hour from $\displaystyle 5$ and $\displaystyle 45$ minutes from $\displaystyle 56$.

$\frac{\begin{array}[b]{r}5\\ -\ 1\end{array}}{ \ \ \ \space4}$ $\displaystyle \frac{\begin{array}[b]{r}5\\ -\ 1\end{array}}{ \ \ \ \space4}$ $\frac{\begin{array}[b]{r}56\\ -\ 45\end{array}}{ \ \ \ \space 11}$ $\displaystyle \frac{\begin{array}[b]{r}56\\ -\ 45\end{array}}{ \ \ \ \space 11}$

He started watching the television show at 4:11 $\displaystyle 4:11$

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Example Question #41 : Measurement & Data

When Armen got home from school he immediately started watching a television show. He watched the show for $\displaystyle 1$ hour and $\displaystyle 17$ minutes. If it is 5:42 $\displaystyle 5:42$ when he stops watching the show, what time did he start watching the show?

Possible Answers:

5:00 $\displaystyle 5:00$

3:47 $\displaystyle 3:47$

5:23 $\displaystyle 5:23$

3:23 $\displaystyle 3:23$

4:25 $\displaystyle 4:25$

Correct answer:

4:25 $\displaystyle 4:25$

Explanation:

For this problem we are subtracting to find a previous time.

We can subtract $\displaystyle 1$ hour from $\displaystyle 5$ and $\displaystyle 17$ minutes from $\displaystyle 42$.

$\frac{\begin{array}[b]{r}5\\ -\ 1\end{array}}{ \ \ \ \space4}$ $\displaystyle \frac{\begin{array}[b]{r}5\\ -\ 1\end{array}}{ \ \ \ \space4}$ $\frac{\begin{array}[b]{r}42\\ -\ 17\end{array}}{ \ \ \ \space 25}$ $\displaystyle \frac{\begin{array}[b]{r}42\\ -\ 17\end{array}}{ \ \ \ \space 25}$

He started watching the television show at 4:25 $\displaystyle 4:25$

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Example Question #41 : Tell And Write Time To The Nearest Minute And Solve Word Problems Involving Time: Ccss.Math.Content.3.Md.A.1

When Joe got home from school he immediately started watching a television show. He watched the show for $\displaystyle 2$ hours and $\displaystyle 20$ minutes. If it is 8:30 $\displaystyle 8:30$ when he stops watching the show, what time did he start watching the show?

Possible Answers:

10:20 $\displaystyle 10:20$

10:10 $\displaystyle 10:10$

7:20 $\displaystyle 7:20$

6:10 $\displaystyle 6:10$

6:15 $\displaystyle 6:15$

Correct answer:

6:10 $\displaystyle 6:10$

Explanation:

For this problem we are subtracting to find a previous time.

We can subtract $\displaystyle 2$ hours from $\displaystyle 8$ and $\displaystyle 20$ minutes from $\displaystyle 30$.

$\frac{\begin{array}[b]{r}8\\ -\ 2\end{array}}{ \ \ \ \space6}$ $\displaystyle \frac{\begin{array}[b]{r}8\\ -\ 2\end{array}}{ \ \ \ \space6}$ $\frac{\begin{array}[b]{r}30\\ -\ 20\end{array}}{ \ \ \ \space 10}$ $\displaystyle \frac{\begin{array}[b]{r}30\\ -\ 20\end{array}}{ \ \ \ \space 10}$

He started watching the television show at 6:10 $\displaystyle 6:10$

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Example Question #41 : Measurement & Data

When Greg got home from school he immediately started watching a television show. He watched the show for $\displaystyle 2$ hours and $\displaystyle 14$ minutes. If it is 8:17 $\displaystyle 8:17$ when he stops watching the show, what time did he start watching the show?

Possible Answers:

6:05 $\displaystyle 6:05$

7:13 $\displaystyle 7:13$

6:03 $\displaystyle 6:03$

10:03 $\displaystyle 10:03$

10:05 $\displaystyle 10:05$

Correct answer:

6:03 $\displaystyle 6:03$

Explanation:

For this problem we are subtracting to find a previous time.

We can subtract $\displaystyle 2$ hours from $\displaystyle 8$ and $\displaystyle 14$ minutes from $\displaystyle 17$.

$\frac{\begin{array}[b]{r}8\\ -\ 2\end{array}}{ \ \ \ \space6}$ $\displaystyle \frac{\begin{array}[b]{r}8\\ -\ 2\end{array}}{ \ \ \ \space6}$ $\frac{\begin{array}[b]{r}17\\ -\ 14\end{array}}{ \ \ \ \space 3}$ $\displaystyle \frac{\begin{array}[b]{r}17\\ -\ 14\end{array}}{ \ \ \ \space 3}$

He started watching the television show at 6:03 $\displaystyle 6:03$

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Example Question #41 : Measurement & Data

When Eric got home from school he immediately started watching a television show. He watched the show for $\displaystyle 2$ hours and $\displaystyle 37$ minutes. If it is 8:53 $\displaystyle 8:53$ when he stops watching the show, what time did he start watching the show?

Possible Answers:

10:34 $\displaystyle 10:34$

10:19 $\displaystyle 10:19$

7:19 $\displaystyle 7:19$

7:34 $\displaystyle 7:34$

6:16 $\displaystyle 6:16$

Correct answer:

6:16 $\displaystyle 6:16$

Explanation:

For this problem we are subtracting to find a previous time.

We can subtract $\displaystyle 2$ hours from $\displaystyle 8$ and $\displaystyle 37$ minutes from $\displaystyle 53$.

$\frac{\begin{array}[b]{r}8\\ -\ 2\end{array}}{ \ \ \ \space6}$ $\displaystyle \frac{\begin{array}[b]{r}8\\ -\ 2\end{array}}{ \ \ \ \space6}$ $\frac{\begin{array}[b]{r}53\\ -\ 37\end{array}}{ \ \ \ \space 16}$ $\displaystyle \frac{\begin{array}[b]{r}53\\ -\ 37\end{array}}{ \ \ \ \space 16}$

He started watching the television show at 6:16 $\displaystyle 6:16$

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Example Question #41 : Measurement And Estimation

When David got home from school he immediately started watching a television show. He watched the show for $\displaystyle 2$ hours and $\displaystyle 19$ minutes. If it is 8:45 $\displaystyle 8:45$ when he stops watching the show, what time did he start watching the show?

Possible Answers:

6:45 $\displaystyle 6:45$

4:23 $\displaystyle 4:23$

6:26 $\displaystyle 6:26$

4:45 $\displaystyle 4:45$

5:23 $\displaystyle 5:23$

Correct answer:

6:26 $\displaystyle 6:26$

Explanation:

For this problem we are subtracting to find a previous time.

We can subtract $\displaystyle 2$ hours from $\displaystyle 8$ and $\displaystyle 19$ minutes from $\displaystyle 45$.

$\frac{\begin{array}[b]{r}8\\ -\ 2\end{array}}{ \ \ \ \space6}$ $\displaystyle \frac{\begin{array}[b]{r}8\\ -\ 2\end{array}}{ \ \ \ \space6}$ $\frac{\begin{array}[b]{r}45\\ -\ 19\end{array}}{ \ \ \ \space 26}$ $\displaystyle \frac{\begin{array}[b]{r}45\\ -\ 19\end{array}}{ \ \ \ \space 26}$

He started watching the television show at 6:26 $\displaystyle 6:26$

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Example Question #41 : Measurement & Data

When Mitch got home from school he immediately started watching a television show. He watched the show for $\displaystyle 2$ hours and $\displaystyle 39$ minutes. If it is 8:48 $\displaystyle 8:48$ when he stops watching the show, what time did he start watching the show?

Possible Answers:

5:09 $\displaystyle 5:09$

6:14 $\displaystyle 6:14$

5:34 $\displaystyle 5:34$

5:14 $\displaystyle 5:14$

6:09 $\displaystyle 6:09$

Correct answer:

6:09 $\displaystyle 6:09$

Explanation:

For this problem we are subtracting to find a previous time.

We can subtract $\displaystyle 2$ hours from $\displaystyle 8$ and $\displaystyle 39$ minutes from $\displaystyle 48$.

$\frac{\begin{array}[b]{r}8\\ -\ 2\end{array}}{ \ \ \ \space6}$ $\displaystyle \frac{\begin{array}[b]{r}8\\ -\ 2\end{array}}{ \ \ \ \space6}$ $\frac{\begin{array}[b]{r}48\\ -\ 39\end{array}}{ \ \ \ \space 9}$ $\displaystyle \frac{\begin{array}[b]{r}48\\ -\ 39\end{array}}{ \ \ \ \space 9}$

He started watching the television show at 6:09 $\displaystyle 6:09$

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Example Question #42 : Measurement And Estimation

Megan left for the carnival at 4:18 $\displaystyle 4:18$. She returned home $\displaystyle 3$ hours and $\displaystyle 26$ minutes later. What time was it when she returned home?

Possible Answers:

6:34 $\displaystyle 6:34$

7:44 $\displaystyle 7:44$

1:26 $\displaystyle 1:26$

7:26 $\displaystyle 7:26$

1:44 $\displaystyle 1:44$

Correct answer:

7:44 $\displaystyle 7:44$

Explanation:

For this problem we are adding to find a future time.

We can add $\displaystyle 3$ hour to $\displaystyle 4$ and $\displaystyle 26$ minutes to $\displaystyle 18$.

$\frac{\begin{array}[b]{r}4\\ +\ 3\end{array}}{ \ \ \ \space7}$ $\displaystyle \frac{\begin{array}[b]{r}4\\ +\ 3\end{array}}{ \ \ \ \space7}$ $\frac{\begin{array}[b]{r}18\\ +\ 26\end{array}}{ \ \ \ \space 44}$ $\displaystyle \frac{\begin{array}[b]{r}18\\ +\ 26\end{array}}{ \ \ \ \space 44}$

She returned home at 7:44 $\displaystyle 7:44$

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Example Question #43 : Measurement And Estimation

Elizabeth left for the carnival at 4:05 $\displaystyle 4:05$. She returned home $\displaystyle 3$ hours and $\displaystyle 30$ minutes later. What time was it when she returned home?

Possible Answers:

8:25 $\displaystyle 8:25$

7:30 $\displaystyle 7:30$

7:45 $\displaystyle 7:45$

7:35 $\displaystyle 7:35$

8:20 $\displaystyle 8:20$

Correct answer:

7:35 $\displaystyle 7:35$

Explanation:

For this problem we are adding to find a future time.

We can add $\displaystyle 3$ hour to $\displaystyle 4$ and $\displaystyle 30$ minutes to $\displaystyle 5$.

$\frac{\begin{array}[b]{r}4\\ +\ 3\end{array}}{ \ \ \ \space7}$ $\displaystyle \frac{\begin{array}[b]{r}4\\ +\ 3\end{array}}{ \ \ \ \space7}$ $\frac{\begin{array}[b]{r}5\\ +\ 30\end{array}}{ \ \ \ \space 35}$ $\displaystyle \frac{\begin{array}[b]{r}5\\ +\ 30\end{array}}{ \ \ \ \space 35}$

She returned home at 7:35 $\displaystyle 7:35$

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Example Question #43 : Measurement & Data

Sarah left for the carnival at 4:10 $\displaystyle 4:10$. She returned home $\displaystyle 3$ hours and $\displaystyle 19$ minutes later. What time was it when she returned home?

Possible Answers:

7:46 $\displaystyle 7:46$

8:11 $\displaystyle 8:11$

7:29 $\displaystyle 7:29$

6:27 $\displaystyle 6:27$

6:43 $\displaystyle 6:43$

Correct answer:

7:29 $\displaystyle 7:29$

Explanation:

For this problem we are adding to find a future time.

We can add $\displaystyle 3$ hour to $\displaystyle 4$ and $\displaystyle 19$ minutes to $\displaystyle 10$.

$\frac{\begin{array}[b]{r}4\\ +\ 3\end{array}}{ \ \ \ \space7}$ $\displaystyle \frac{\begin{array}[b]{r}4\\ +\ 3\end{array}}{ \ \ \ \space7}$ $\frac{\begin{array}[b]{r}10\\ +\ 19\end{array}}{ \ \ \ \space 29}$ $\displaystyle \frac{\begin{array}[b]{r}10\\ +\ 19\end{array}}{ \ \ \ \space 29}$

She returned home at 7:29 $\displaystyle 7:29$

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Common Core: 3rd Grade Math : Measurement & Data

Study concepts, example questions & explanations for Common Core: 3rd Grade Math

All Common Core: 3rd Grade Math Resources

Example Questions

Example Question #41 : Measurement & Data

Example Question #41 : Measurement & Data

Example Question #41 : Tell And Write Time To The Nearest Minute And Solve Word Problems Involving Time: Ccss.Math.Content.3.Md.A.1

Example Question #41 : Measurement & Data

Example Question #41 : Measurement & Data

Example Question #41 : Measurement And Estimation

Example Question #41 : Measurement & Data

Example Question #42 : Measurement And Estimation

Example Question #43 : Measurement And Estimation

Example Question #43 : Measurement & Data

All Common Core: 3rd Grade Math Resources

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