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Common Core: 4th Grade Math : Common Core Math: Grade 4

Study concepts, example questions & explanations for Common Core: 4th Grade Math

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All Common Core: 4th Grade Math Resources

7 Diagnostic Tests 189 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #1 : Apply Area And Perimeter Formulas For Rectangles: Ccss.Math.Content.4.Md.A.3

What is the length of a rectangular room with a perimeter of 59ft $\displaystyle 59ft$ and a width of 17ft? $\displaystyle 17ft?$

Possible Answers:

15.5ft $\displaystyle 15.5ft$

12.5ft $\displaystyle 12.5ft$

15ft $\displaystyle 15ft$

12ft $\displaystyle 12ft$

25ft $\displaystyle 25ft$

Correct answer:

12.5ft $\displaystyle 12.5ft$

Explanation:

$\displaystyle P=2l+ 2w$

We have the perimeter and the width, so we can plug those values into our equation and solve for our unknown.

$\displaystyle 59=2l+2(17)$

$\displaystyle 59=2l+34$

Subtract $\displaystyle 34$ from both sides

$\displaystyle 59-34=2l+134-34$

25=2l $\displaystyle 25=2l$

Divide $\displaystyle 2$ by both sides

$\frac{25}{2}=\frac{2l}{2}$ $\displaystyle \frac{25}{2}=\frac{2l}{2}$

12.5=l $\displaystyle 12.5=l$

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Example Question #4 : Apply Area And Perimeter Formulas For Rectangles: Ccss.Math.Content.4.Md.A.3

What is the length of a rectangular room with a perimeter of 66ft $\displaystyle 66ft$ and a width of 18ft? $\displaystyle 18ft?$

Possible Answers:

14ft $\displaystyle 14ft$

15ft $\displaystyle 15ft$

12ft $\displaystyle 12ft$

13ft $\displaystyle 13ft$

11ft $\displaystyle 11ft$

Correct answer:

15ft $\displaystyle 15ft$

Explanation:

$\displaystyle P=2l+ 2w$

We have the perimeter and the width, so we can plug those values into our equation and solve for our unknown.

$\displaystyle 66=2l+2(18)$

$\displaystyle 66=2l+36$

Subtract $\displaystyle 36$ from both sides

$\displaystyle 66-36=2l+36-36$

30=2l $\displaystyle 30=2l$

Divide $\displaystyle 2$ by both sides

$\frac{30}{2}=\frac{2l}{2}$ $\displaystyle \frac{30}{2}=\frac{2l}{2}$

15=l $\displaystyle 15=l$

Report an Error

Example Question #3 : Apply Area And Perimeter Formulas For Rectangles: Ccss.Math.Content.4.Md.A.3

What is the length of a rectangular room with a perimeter of 60ft $\displaystyle 60ft$ and a width of 14ft? $\displaystyle 14ft?$

Possible Answers:

18ft $\displaystyle 18ft$

30ft $\displaystyle 30ft$

32ft $\displaystyle 32ft$

26ft $\displaystyle 26ft$

16ft $\displaystyle 16ft$

Correct answer:

16ft $\displaystyle 16ft$

Explanation:

$\displaystyle P=2l+ 2w$

We have the perimeter and the width, so we can plug those values into our equation and solve for our unknown.

$\displaystyle 60=2l+2(14)$

$\displaystyle 60=2l+28$

Subtract $\displaystyle 28$ from both sides

$\displaystyle 60-28=2l+28-28$

32=2l $\displaystyle 32=2l$

Divide $\displaystyle 2$ by both sides

$\frac{32}{2}=\frac{2l}{2}$ $\displaystyle \frac{32}{2}=\frac{2l}{2}$

16=l $\displaystyle 16=l$

Report an Error

Example Question #303 : Geometry

What is the length of a rectangular room with a perimeter of 40ft $\displaystyle 40ft$ and a width of 6ft? $\displaystyle 6ft?$

Possible Answers:

32ft $\displaystyle 32ft$

14ft $\displaystyle 14ft$

18ft $\displaystyle 18ft$

16ft $\displaystyle 16ft$

28ft $\displaystyle 28ft$

Correct answer:

14ft $\displaystyle 14ft$

Explanation:

$\displaystyle P=2l+ 2w$

We have the perimeter and the width, so we can plug those values into our equation and solve for our unknown.

$\displaystyle 40=2l+2(6)$

$\displaystyle 40=2l+12$

Subtract $\displaystyle 12$ from both sides

$\displaystyle 40-12=2l+12-12$

28=2l $\displaystyle 28=2l$

Divide $\displaystyle 2$ by both sides

$\frac{28}{2}=\frac{2l}{2}$ $\displaystyle \frac{28}{2}=\frac{2l}{2}$

14=l $\displaystyle 14=l$

Report an Error

Example Question #3 : Apply Area And Perimeter Formulas For Rectangles: Ccss.Math.Content.4.Md.A.3

What is the length of a rectangular room with a perimeter of 96ft $\displaystyle 96ft$ and a width of 30ft? $\displaystyle 30ft?$

Possible Answers:

19ft $\displaystyle 19ft$

20ft $\displaystyle 20ft$

24ft $\displaystyle 24ft$

22ft $\displaystyle 22ft$

18ft $\displaystyle 18ft$

Correct answer:

18ft $\displaystyle 18ft$

Explanation:

$\displaystyle P=2l+ 2w$

We have the perimeter and the width, so we can plug those values into our equation and solve for our unknown.

$\displaystyle 96=2l+2(30)$

$\displaystyle 96=2l+60$

Subtract $\displaystyle 60$ from both sides

$\displaystyle 96-60=2l+60-60$

36=2l $\displaystyle 36=2l$

Divide $\displaystyle 2$ by both sides

$\frac{36}{2}=\frac{2l}{2}$ $\displaystyle \frac{36}{2}=\frac{2l}{2}$

18=l $\displaystyle 18=l$

Report an Error

Example Question #4 : Solving For Length

What is the length of a rectangular room with a perimeter of 90ft $\displaystyle 90ft$ and a width of 12ft $\displaystyle 12ft$

Possible Answers:

33ft $\displaystyle 33ft$

22ft $\displaystyle 22ft$

66ft $\displaystyle 66ft$

55ft $\displaystyle 55ft$

44ft $\displaystyle 44ft$

Correct answer:

33ft $\displaystyle 33ft$

Explanation:

$\displaystyle P=2l+ 2w$

We have the perimeter and the width, so we can plug those values into our equation and solve for our unknown.

$\displaystyle 90=2l+2(12)$

$\displaystyle 90=2l+24$

Subtract $\displaystyle 24$ from both sides

$\displaystyle 90-24=2l+24-24$

66=2l $\displaystyle 66=2l$

Divide $\displaystyle 2$ by both sides

$\frac{66}{2}=\frac{2l}{2}$ $\displaystyle \frac{66}{2}=\frac{2l}{2}$

33=l $\displaystyle 33=l$

Report an Error

Example Question #2 : Apply Area And Perimeter Formulas For Rectangles: Ccss.Math.Content.4.Md.A.3

What is the length of a rectangular room with a perimeter of 100ft $\displaystyle 100ft$ and a width of 18ft $\displaystyle 18ft$

Possible Answers:

32ft $\displaystyle 32ft$

58ft $\displaystyle 58ft$

60ft $\displaystyle 60ft$

68ft $\displaystyle 68ft$

34ft $\displaystyle 34ft$

Correct answer:

32ft $\displaystyle 32ft$

Explanation:

$\displaystyle P=2l+ 2w$

We have the perimeter and the width, so we can plug those values into our equation and solve for our unknown.

$\displaystyle 100=2l+2(18)$

$\displaystyle 100=2l+36$

Subtract $\displaystyle 36$ from both sides

$\displaystyle 100-36=2l+36-36$

64=2l $\displaystyle 64=2l$

Divide $\displaystyle 2$ by both sides

$\frac{64}{2}=\frac{2l}{2}$ $\displaystyle \frac{64}{2}=\frac{2l}{2}$

32=l $\displaystyle 32=l$

Report an Error

Example Question #5626 : Ssat Elementary Level Quantitative (Math)

What is the length of a rectangular room with a perimeter of 50ft $\displaystyle 50ft$ and a width of 7ft? $\displaystyle 7ft?$

Possible Answers:

20ft $\displaystyle 20ft$

28ft $\displaystyle 28ft$

18ft $\displaystyle 18ft$

36ft $\displaystyle 36ft$

14ft $\displaystyle 14ft$

Correct answer:

18ft $\displaystyle 18ft$

Explanation:

$\displaystyle P=2l+ 2w$

We have the perimeter and the width, so we can plug those values into our equation and solve for our unknown.

$\displaystyle 50=2l+2(7)$

$\displaystyle 50=2l+14$

Subtract $\displaystyle 14$ from both sides

$\displaystyle 50-14=2l+14-14$

36=2l $\displaystyle 36=2l$

Divide $\displaystyle 2$ by both sides

$\frac{36}{2}=\frac{2l}{2}$ $\displaystyle \frac{36}{2}=\frac{2l}{2}$

18=l $\displaystyle 18=l$

Report an Error

Example Question #11 : Solving For Length

What is the length of a rectangular room with an area of 56ft^2 $\displaystyle 56ft^2$ and a width of 7ft? $\displaystyle 7ft?$

Possible Answers:

5ft $\displaystyle 5ft$

8ft $\displaystyle 8ft$

6ft $\displaystyle 6ft$

7ft $\displaystyle 7ft$

9ft $\displaystyle 9ft$

Correct answer:

8ft $\displaystyle 8ft$

Explanation:

$A=l\times w$ $\displaystyle A=l\times w$

We have the area and the width, so we can plug those values into our equation and solve for our unknown.

$56=l\times 7$ $\displaystyle 56=l\times 7$

$\frac{56}{7}=\frac{l\times 7}{7}$ $\displaystyle \frac{56}{7}=\frac{l\times 7}{7}$

8=l $\displaystyle 8=l$

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Example Question #61 : Parallelograms

What is the length of a rectangular room with an area of 80ft^2 $\displaystyle 80ft^2$ and a width of 8ft? $\displaystyle 8ft?$

Possible Answers:

20ft $\displaystyle 20ft$

8ft $\displaystyle 8ft$

10ft $\displaystyle 10ft$

18ft $\displaystyle 18ft$

16ft $\displaystyle 16ft$

Correct answer:

10ft $\displaystyle 10ft$

Explanation:

$A=l\times w$ $\displaystyle A=l\times w$

We have the area and the width, so we can plug those values into our equation and solve for our unknown.

$80=l\times 8$ $\displaystyle 80=l\times 8$

$\frac{80}{8}=\frac{l\times 8}{8}$ $\displaystyle \frac{80}{8}=\frac{l\times 8}{8}$

10=l $\displaystyle 10=l$

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Common Core: 4th Grade Math : Common Core Math: Grade 4

Study concepts, example questions & explanations for Common Core: 4th Grade Math

All Common Core: 4th Grade Math Resources

Example Questions

Example Question #1 : Apply Area And Perimeter Formulas For Rectangles: Ccss.Math.Content.4.Md.A.3

Example Question #4 : Apply Area And Perimeter Formulas For Rectangles: Ccss.Math.Content.4.Md.A.3

Example Question #3 : Apply Area And Perimeter Formulas For Rectangles: Ccss.Math.Content.4.Md.A.3

Example Question #303 : Geometry

Example Question #3 : Apply Area And Perimeter Formulas For Rectangles: Ccss.Math.Content.4.Md.A.3

Example Question #4 : Solving For Length

Example Question #2 : Apply Area And Perimeter Formulas For Rectangles: Ccss.Math.Content.4.Md.A.3

Example Question #5626 : Ssat Elementary Level Quantitative (Math)

Example Question #11 : Solving For Length

Example Question #61 : Parallelograms

All Common Core: 4th Grade Math Resources

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