The first thing we need to do is put our minutes into hours because our final answer is asking for hours. We know that \(\displaystyle 1 hr=60min\). We can set up a proportion and cross multiply to solve. 

\(\displaystyle \frac{1hr}{60min}=\frac{x}{180min}\)

\(\displaystyle 60min(x)=1hr(180min)\)

Then we can divide to isolate the \(\displaystyle x\).

\(\displaystyle \frac{60min(x)}{60min}=\frac{1hr(180min)}{60min}\)

\(\displaystyle x=3hr\)

Now we can add our hours together to find the total. 

\(\displaystyle 3hr+2hr=5hr\)

The first thing we need to do is put our minutes into hours because our final answer is asking for hours. We know that \(\displaystyle 1hr=60min\). We can set up a proportion and cross multiply to solve. 

\(\displaystyle \frac{1hr}{60min}=\frac{x}{180min}\)

\(\displaystyle 60min(x)=180min(1hr)\)

Then we can divide to isolate the \(\displaystyle x\).

\(\displaystyle \frac{60min(x)}{60min}=\frac{180min(1hr)}{60min}\)

\(\displaystyle x=3hr\)

Now we need to multiply \(\displaystyle 3\times5\) because Matt studied for \(\displaystyle 3\) hours each day. 

\(\displaystyle 3hr\times5=15hr\)

The first thing we need to do is put our hours into minutes because our final answer is asking for minutes. We know that \(\displaystyle 1 hr=60min\). We can set up a proportion and cross multiply to solve. 

\(\displaystyle \frac{1hr}{60min}=\frac{2hr}{x}\)

\(\displaystyle 1hr(x)=60min(2hr)\)

Then we can divide to isolate the \(\displaystyle x\).

\(\displaystyle \frac{1hr(x)}{1hr}=\frac{60min(2hr)}{1hr}\)

\(\displaystyle x=60min(2)\)

\(\displaystyle x=120 min\)

Now we can add our minutes from before and after dinner together to find our total. 

\(\displaystyle 120min+120min=240min\)

The first thing we need to do is put our seconds into minutes because our final answer is asking for minutes. We know that \(\displaystyle 1min=60sec\). We can set up a proportion and cross multiply to solve. 

\(\displaystyle \frac{1min}{60sec}=\frac{x}{120sec}\)

\(\displaystyle 60sec(x)=120sec(1min)\)

Then we can divide to isolate the \(\displaystyle x\).

\(\displaystyle \frac{60sec(x)}{60sec}=\frac{120sec(1min)}{60sec}\)

\(\displaystyle x=2min\)

Now we need to subtract to find our difference. 

\(\displaystyle 7min-2min=5min\)

The first thing we need to do is put our feet into inches because our final answer is asking for inches. We know that \(\displaystyle 1ft=12in\). We can set up a proportion and cross multiply to solve. 

\(\displaystyle \frac{1ft}{12in}=\frac{7ft}{x}\)

\(\displaystyle 1ft(x)=7ft(12in)\)

Then we can divide to isolate the \(\displaystyle x\).

\(\displaystyle \frac{1ft(x))}{1ft}=\frac{7ft(12in)}{1ft}\)

\(\displaystyle x=84in\)

Now we can add our inches together to find our total. 

\(\displaystyle 84in+36in=120in\)

The first thing we need to do is put our liters into milliliters because our final answer is asking for milliliters. We know that \(\displaystyle 1l=1,000ml\). We can set up a proportion and cross multiply to solve. 

\(\displaystyle \frac{1l}{1,000ml}=\frac{2l}{x}\)

\(\displaystyle 1l(x)=1,000ml(2l)\)

Then we can divide to isolate the \(\displaystyle x\).

\(\displaystyle \frac{1l(x)}{1l}=\frac{1,000ml(2l)}{1l}\)

\(\displaystyle x=2,000ml\)

Now we can subtract to find out how much is left. 

\(\displaystyle 2,000ml-7ml=1,993\)

The first thing we need to do is put our inches into feet because our final answer is asking for feet. We know that \(\displaystyle 1ft=12in\). We can set up a proportion and cross multiply to solve. 

\(\displaystyle \frac{1ft}{12in}=\frac{x}{24in}\)

\(\displaystyle 12in(x)=1ft(24in)\)

Then we can divide to isolate the \(\displaystyle x\).

\(\displaystyle \frac{12in(x)}{12in}=\frac{1ft(24in)}{12in}\)

\(\displaystyle x=2ft\)

Now we can add our feet together to find our total. 

\(\displaystyle 5ft+2ft=7ft\)

Because our systems of measurements are the same, the first thing we want to do is subtract. 

 \(\displaystyle 8l-3l=5l\)

Our answer is asking us for milliliters, so we need to convert \(\displaystyle 5l\) into milliliters. We know that \(\displaystyle 1l=1,000ml\). We can set up a proportion and cross multiply to solve. 

\(\displaystyle \frac{1l}{1,000ml}=\frac{5l}{x}\)

\(\displaystyle 1l(x)=1,000ml(2l)\)

Then we can divide to isolate the \(\displaystyle x\).

\(\displaystyle \frac{1l(x)}{1l}=\frac{1,000ml(5l)}{1l}\)

\(\displaystyle x=5,000ml\)

The first thing we need to do is put our pounds into ounces because our final answer is asking for ounces. We know that \(\displaystyle 1lb=16oz\). We can set up a proportion and cross multiply to solve. 

\(\displaystyle \frac{1lb}{16oz}=\frac{4lb}{x}\)

\(\displaystyle 1lb(x)=16oz(4lb)\)

Then we can divide to isolate the \(\displaystyle x\).

\(\displaystyle \frac{1lb(x)}{1lb}=\frac{16oz(4lb)}{1lb}\)

\(\displaystyle x=64oz\)

Now we need to divide our \(\displaystyle 64oz\) by \(\displaystyle 4\) because we are splitting the peanuts up equally between \(\displaystyle 4\) people. 

\(\displaystyle 64oz\div4=16oz\)

The first thing we need to do is put our pounds into ounces because our final answer is asking for ounces. We know that \(\displaystyle 1lb=16oz\). We can set up a proportion and cross multiply to solve. 

\(\displaystyle \frac{1lb}{16oz}=\frac{6lb}{x}\)

\(\displaystyle 1lb(x)=16oz(6lb)\)

Then we can divide to isolate the \(\displaystyle x\).

\(\displaystyle \frac{1lb(x)}{1lb}=\frac{16oz(6lb)}{1lb}\)

\(\displaystyle x=96oz\)

Now we need to divide our \(\displaystyle 96oz\) by \(\displaystyle 3\) because we are splitting the peanuts up equally between \(\displaystyle 3\) people. 

\(\displaystyle 96oz\div3=32oz\)