Common Core: 5th Grade Math : Add Fractions with Unlike Denominators

Study concepts, example questions & explanations for Common Core: 5th Grade Math

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Example Questions

Example Question #11 : Add Fractions With Unlike Denominators

Solve:

\(\displaystyle \frac{7}8{+\frac{2}{4}}\)

Possible Answers:

\(\displaystyle 1\frac{3}{8}\)

\(\displaystyle \frac{8}{11}\)

\(\displaystyle \frac{9}{12}\)

\(\displaystyle \frac{11}{16}\)

\(\displaystyle \frac{16}{11}\)

Correct answer:

\(\displaystyle 1\frac{3}{8}\)

Explanation:

\(\displaystyle \frac{7}8{+\frac{2}{4}}\)

In order to solve this problem, we first have to find common denominators. \(\displaystyle \frac{2}{4}\times\frac{2}{2}=\frac{4}{8}\)

Now that we have common denominators, we can add the fractions. Remember, when we add and subtract fractions, we only add or subtract the numerator. 

\(\displaystyle \frac{7}{8}+\frac{4}{8}=\frac{11}{8}\)

\(\displaystyle \frac{11}{8}=1\frac{3}{8}\) because \(\displaystyle 8\) can go into \(\displaystyle 11\) one time with \(\displaystyle 3\) left over. 

Example Question #12 : Add Fractions With Unlike Denominators

Solve:

\(\displaystyle \frac{3}{5}+\frac{1}3\)

Possible Answers:

\(\displaystyle \frac{1}{2}\)

\(\displaystyle \frac{4}{8}\)

\(\displaystyle \frac{13}{15}\)

\(\displaystyle \frac{14}{30}\)

\(\displaystyle \frac{14}{15}\)

Correct answer:

\(\displaystyle \frac{14}{15}\)

Explanation:

\(\displaystyle \frac{3}{5}+\frac{1}3\)

In order to solve this problem, we first have to find common denominators. 

\(\displaystyle \frac{3}5{} \times\frac{3}{3}=\frac{9}{15}\)

\(\displaystyle \frac{1}{3}\times\frac{5}{5}=\frac{5}{15}\)

Now that we have common denominators, we can add the fractions. Remember, when we add and subtract fractions, we only add or subtract the numerator. 

\(\displaystyle \frac{9}{15}+\frac{5}{15}=\frac{14}{15}\)

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