Common Core: 5th Grade Math : Common Core Math: Grade 5

Study concepts, example questions & explanations for Common Core: 5th Grade Math

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Example Questions

Example Question #2061 : Common Core Math: Grade 5

Solve:

\(\displaystyle \frac{7}{8}-\frac{3}{16}\)

Possible Answers:

\(\displaystyle \frac{13}{16}\)

\(\displaystyle \frac{4}{16}\)

\(\displaystyle \frac{4}{8}\)

\(\displaystyle \frac{11}{16}\)

\(\displaystyle \frac{1}{4}\)

Correct answer:

\(\displaystyle \frac{11}{16}\)

Explanation:

\(\displaystyle \frac{7}{8}-\frac{3}{16}\)

In order to solve this problem, we first have to find common denominators. 

\(\displaystyle \frac{7}{8}\times\frac{2}{2}=\frac{14}{16}\)

Now that we have common denominators, we can subtract the fractions. Remember, when we add and subtract fractions, we only add or subtract the numerator. 

\(\displaystyle \frac{14}{16}-\frac{3}{16}=\frac{11}{16}\)

Example Question #2062 : Common Core Math: Grade 5

\(\displaystyle \frac{6}{7}-\frac{1}{2}\)

Possible Answers:

\(\displaystyle \frac{6}{0}\)

\(\displaystyle \frac{5}{14}\)

\(\displaystyle \frac{7}{8}\)

\(\displaystyle \frac{5}{5}\)

Correct answer:

\(\displaystyle \frac{5}{14}\)

Explanation:

\(\displaystyle \frac{6}{7}-\frac{1}{2}\)

In order to solve this problem, we first have to find common denominators. 

\(\displaystyle \frac{6}{7}\times \frac{2}{2}=\frac{12}{14}\)

\(\displaystyle \frac{1}{2}\times\frac{7}{7}=\frac{7}{14}\)

Now that we have common denominators, we can subtract the fractions. Remember, when we add and subtract fractions, we only add or subtract the numerator. 

\(\displaystyle \frac{12}{14}-\frac{7}{14}=\frac{5}{14}\)

Example Question #672 : Number & Operations With Fractions

\(\displaystyle \frac{1}{4}-\frac{1}{7}\)

Possible Answers:

\(\displaystyle -\frac{0}{3}\)

\(\displaystyle \frac{1}{12}\)

\(\displaystyle \frac{3}{28}\)

\(\displaystyle \frac{0}{3}\)

Correct answer:

\(\displaystyle \frac{3}{28}\)

Explanation:

\(\displaystyle \frac{1}{4}-\frac{1}{7}\)

In order to solve this problem, we first have to find common denominators. 

\(\displaystyle \frac{1}{4}\times\frac{7}{7}=\frac{7}{28}\)

\(\displaystyle \frac{1}{7}\times \frac{4}{4}=\frac{4}{28}\)

Now that we have common denominators, we can subtract the fractions. Remember, when we add and subtract fractions, we only add or subtract the numerator. 

\(\displaystyle \frac{7}{28}-\frac{4}{28}=\frac{3}{28}\)

Example Question #2064 : Common Core Math: Grade 5

\(\displaystyle \frac{7}{11}-\frac{2}{5}\)

Possible Answers:

\(\displaystyle \frac{5}{55}\)

\(\displaystyle \frac{5}{6}\)

\(\displaystyle \frac{3}{1}\)

\(\displaystyle \frac{13}{55}\)

Correct answer:

\(\displaystyle \frac{13}{55}\)

Explanation:

\(\displaystyle \frac{7}{11}-\frac{2}{5}\)

In order to solve this problem, we first have to find common denominators. 

\(\displaystyle \frac{7}{11}\times\frac{5}{5}=\frac{35}{55}\)

\(\displaystyle \frac{2}{5}\times \frac{11}{11}=\frac{22}{55}\)

Now that we have common denominators, we can subtract the fractions. Remember, when we add and subtract fractions, we only add or subtract the numerator. 

\(\displaystyle \frac{35}{55}-\frac{22}{55}=\frac{13}{55}\)

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