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Common Core: 5th Grade Math : Number & Operations with Fractions

Study concepts, example questions & explanations for Common Core: 5th Grade Math

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All Common Core: 5th Grade Math Resources

7 Diagnostic Tests 225 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #671 : Number & Operations With Fractions

Solve:

$\frac{2}{3}-\frac{3}{5}$ $\displaystyle \frac{2}{3}-\frac{3}{5}$

Possible Answers:

$\frac{1}{3}$ $\displaystyle \frac{1}{3}$

$\frac{1}{2}$ $\displaystyle \frac{1}{2}$

$\frac{1}{30}$ $\displaystyle \frac{1}{30}$

$\frac{1}{15}$ $\displaystyle \frac{1}{15}$

$\frac{5}{15}$ $\displaystyle \frac{5}{15}$

Correct answer:

$\frac{1}{15}$ $\displaystyle \frac{1}{15}$

Explanation:

$\frac{2}{3}-\frac{3}{5}$ $\displaystyle \frac{2}{3}-\frac{3}{5}$

In order to solve this problem, we first have to find common denominators.

$\frac{2}{3}\times\frac{5}{5}=\frac{10}{15}$ $\displaystyle \frac{2}{3}\times\frac{5}{5}=\frac{10}{15}$

$\frac{3}{5}\times \frac{3}{3}=\frac{9}{15}$ $\displaystyle \frac{3}{5}\times \frac{3}{3}=\frac{9}{15}$

Now that we have common denominators, we can subtract the fractions. Remember, when we add and subtract fractions, we only add or subtract the numerator.

$\frac{10}{15}-\frac{9}{15}=\frac{1}{15}$ $\displaystyle \frac{10}{15}-\frac{9}{15}=\frac{1}{15}$

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Example Question #672 : Number & Operations With Fractions

Solve:

$\frac{7}{8}-\frac{3}{16}$ $\displaystyle \frac{7}{8}-\frac{3}{16}$

Possible Answers:

$\frac{1}{4}$ $\displaystyle \frac{1}{4}$

$\frac{4}{8}$ $\displaystyle \frac{4}{8}$

$\frac{11}{16}$ $\displaystyle \frac{11}{16}$

$\frac{4}{16}$ $\displaystyle \frac{4}{16}$

$\frac{13}{16}$ $\displaystyle \frac{13}{16}$

Correct answer:

$\frac{11}{16}$ $\displaystyle \frac{11}{16}$

Explanation:

$\frac{7}{8}-\frac{3}{16}$ $\displaystyle \frac{7}{8}-\frac{3}{16}$

In order to solve this problem, we first have to find common denominators.

$\frac{7}{8}\times\frac{2}{2}=\frac{14}{16}$ $\displaystyle \frac{7}{8}\times\frac{2}{2}=\frac{14}{16}$

Now that we have common denominators, we can subtract the fractions. Remember, when we add and subtract fractions, we only add or subtract the numerator.

$\frac{14}{16}-\frac{3}{16}=\frac{11}{16}$ $\displaystyle \frac{14}{16}-\frac{3}{16}=\frac{11}{16}$

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Example Question #2062 : Common Core Math: Grade 5

$\frac{6}{7}-\frac{1}{2}$ $\displaystyle \frac{6}{7}-\frac{1}{2}$

Possible Answers:

$\frac{6}{0}$ $\displaystyle \frac{6}{0}$

$\frac{5}{14}$ $\displaystyle \frac{5}{14}$

$\frac{7}{8}$ $\displaystyle \frac{7}{8}$

$\frac{5}{5}$ $\displaystyle \frac{5}{5}$

Correct answer:

$\frac{5}{14}$ $\displaystyle \frac{5}{14}$

Explanation:

$\frac{6}{7}-\frac{1}{2}$ $\displaystyle \frac{6}{7}-\frac{1}{2}$

In order to solve this problem, we first have to find common denominators.

$\frac{6}{7}\times \frac{2}{2}=\frac{12}{14}$ $\displaystyle \frac{6}{7}\times \frac{2}{2}=\frac{12}{14}$

$\frac{1}{2}\times\frac{7}{7}=\frac{7}{14}$ $\displaystyle \frac{1}{2}\times\frac{7}{7}=\frac{7}{14}$

Now that we have common denominators, we can subtract the fractions. Remember, when we add and subtract fractions, we only add or subtract the numerator.

$\frac{12}{14}-\frac{7}{14}=\frac{5}{14}$ $\displaystyle \frac{12}{14}-\frac{7}{14}=\frac{5}{14}$

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Example Question #672 : Number & Operations With Fractions

$\frac{1}{4}-\frac{1}{7}$ $\displaystyle \frac{1}{4}-\frac{1}{7}$

Possible Answers:

$-\frac{0}{3}$ $\displaystyle -\frac{0}{3}$

$\frac{1}{12}$ $\displaystyle \frac{1}{12}$

$\frac{3}{28}$ $\displaystyle \frac{3}{28}$

$\frac{0}{3}$ $\displaystyle \frac{0}{3}$

Correct answer:

$\frac{3}{28}$ $\displaystyle \frac{3}{28}$

Explanation:

$\frac{1}{4}-\frac{1}{7}$ $\displaystyle \frac{1}{4}-\frac{1}{7}$

In order to solve this problem, we first have to find common denominators.

$\frac{1}{4}\times\frac{7}{7}=\frac{7}{28}$ $\displaystyle \frac{1}{4}\times\frac{7}{7}=\frac{7}{28}$

$\frac{1}{7}\times \frac{4}{4}=\frac{4}{28}$ $\displaystyle \frac{1}{7}\times \frac{4}{4}=\frac{4}{28}$

Now that we have common denominators, we can subtract the fractions. Remember, when we add and subtract fractions, we only add or subtract the numerator.

$\frac{7}{28}-\frac{4}{28}=\frac{3}{28}$ $\displaystyle \frac{7}{28}-\frac{4}{28}=\frac{3}{28}$

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Example Question #2064 : Common Core Math: Grade 5

$\frac{7}{11}-\frac{2}{5}$ $\displaystyle \frac{7}{11}-\frac{2}{5}$

Possible Answers:

$\frac{5}{55}$ $\displaystyle \frac{5}{55}$

$\frac{5}{6}$ $\displaystyle \frac{5}{6}$

$\frac{3}{1}$ $\displaystyle \frac{3}{1}$

$\frac{13}{55}$ $\displaystyle \frac{13}{55}$

Correct answer:

$\frac{13}{55}$ $\displaystyle \frac{13}{55}$

Explanation:

$\frac{7}{11}-\frac{2}{5}$ $\displaystyle \frac{7}{11}-\frac{2}{5}$

In order to solve this problem, we first have to find common denominators.

$\frac{7}{11}\times\frac{5}{5}=\frac{35}{55}$ $\displaystyle \frac{7}{11}\times\frac{5}{5}=\frac{35}{55}$

$\frac{2}{5}\times \frac{11}{11}=\frac{22}{55}$ $\displaystyle \frac{2}{5}\times \frac{11}{11}=\frac{22}{55}$

Now that we have common denominators, we can subtract the fractions. Remember, when we add and subtract fractions, we only add or subtract the numerator.

$\frac{35}{55}-\frac{22}{55}=\frac{13}{55}$ $\displaystyle \frac{35}{55}-\frac{22}{55}=\frac{13}{55}$

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Common Core: 5th Grade Math : Number & Operations with Fractions

Study concepts, example questions & explanations for Common Core: 5th Grade Math

All Common Core: 5th Grade Math Resources

Example Questions

Example Question #671 : Number & Operations With Fractions

Example Question #672 : Number & Operations With Fractions

Example Question #2062 : Common Core Math: Grade 5

Example Question #672 : Number & Operations With Fractions

Example Question #2064 : Common Core Math: Grade 5

All Common Core: 5th Grade Math Resources

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