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Common Core: 7th Grade Math : Area of a circle

Study concepts, example questions & explanations for Common Core: 7th Grade Math

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All Common Core: 7th Grade Math Resources

7 Diagnostic Tests 110 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #122 : Geometry

What is the area of the circle provided?

Possible Answers:

$1\textup,400\pi\textup{ in}^2$

$1\textup,600\pi\textup{ in}^2$

$1\textup,200\pi\textup{ in}^2$

$400\pi\textup{ in}^2$

$40\pi\textup{ in}^2$

Correct answer:

$400\pi\textup{ in}^2$

Explanation:

In order to solve this problem, we need to recall the formula for the area of a circle:

$A= r^2\pi$

The circle in this question provides us with the diameter, so we first have to solve for the radius. Remember, the radius is half the diameter:

$r=\frac{d}{2}$

$r=\frac{40}{2}$

r=20

Now that we have the radius we can use the formula to solve:

$A=20^2\pi$

Solve:

$A=400\pi\textup{ in}^2$

Report an Error

Example Question #952 : Grade 7

What is the area of the circle provided?

Possible Answers:

$321\pi\textup{ in}^2$

$324\pi\textup{ in}^2$

$325\pi\textup{ in}^2$

$323\pi\textup{ in}^2$

$322\pi\textup{ in}^2$

Correct answer:

$324\pi\textup{ in}^2$

Explanation:

In order to solve this problem, we need to recall the formula for the area of a circle:

$A= r^2\pi$

The circle in this question provides us with the diameter, so we first have to solve for the radius. Remember, the radius is half the diameter:

$r=\frac{d}{2}$

$r=\frac{36}{2}$

r=18

Now that we have the radius we can use the formula to solve:

$A=18^2\pi$

Solve:

$A=324\pi\textup{ in}^2$

Report an Error

Example Question #123 : Geometry

What is the area of the circle provided?

Possible Answers:

$193\pi\textup{ in}^2$

$196\pi\textup{ in}^2$

$192\pi\textup{ in}^2$

$194\pi\textup{ in}^2$

$195\pi\textup{ in}^2$

Correct answer:

$196\pi\textup{ in}^2$

Explanation:

In order to solve this problem, we need to recall the formula for the area of a circle:

$A= r^2\pi$

The circle in this question provides us with the diameter, so we first have to solve for the radius. Remember, the radius is half the diameter:

$r=\frac{d}{2}$

$r=\frac{28}{2}$

r=14

Now that we have the radius we can use the formula to solve:

$A=14^2\pi$

Solve:

$A=196\pi\textup{ in}^2$

Report an Error

Example Question #954 : Grade 7

What is the area of the circle provided?

Possible Answers:

$67\pi\textup{ in}^2$

$68\pi\textup{ in}^2$

$66\pi\textup{ in}^2$

$64\pi\textup{ in}^2$

$65\pi\textup{ in}^2$

Correct answer:

$64\pi\textup{ in}^2$

Explanation:

In order to solve this problem, we need to recall the formula for the area of a circle:

$A= r^2\pi$

The circle in this question provides us with the diameter, so we first have to solve for the radius. Remember, the radius is half the diameter:

$r=\frac{d}{2}$

$r=\frac{16}{2}$

r=8

Now that we have the radius we can use the formula to solve:

$A=8^2\pi$

Solve:

$A=64\pi\textup{ in}^2$

Report an Error

Example Question #131 : Geometry

What is the area of the circle provided?

Possible Answers:

$40\pi\textup{ in}^2$

$37\pi\textup{ in}^2$

$39\pi\textup{ in}^2$

$36\pi\textup{ in}^2$

$38\pi\textup{ in}^2$

Correct answer:

$36\pi\textup{ in}^2$

Explanation:

In order to solve this problem, we need to recall the formula for the area of a circle:

$A= r^2\pi$

The circle in this question provides us with the diameter, so we first have to solve for the radius. Remember, the radius is half the diameter:

$r=\frac{d}{2}$

$r=\frac{12}{2}$

r=6

Now that we have the radius we can use the formula to solve:

$A=6^2\pi$

Solve:

$A=36\pi\textup{ in}^2$

Report an Error

Example Question #132 : Geometry

What is the area of the circle provided?

Possible Answers:

$18\pi\textup{ in}^2$

$15\pi\textup{ in}^2$

$17\pi\textup{ in}^2$

$19\pi\textup{ in}^2$

$16\pi\textup{ in}^2$

Correct answer:

$16\pi\textup{ in}^2$

Explanation:

In order to solve this problem, we need to recall the formula for the area of a circle:

$A= r^2\pi$

The circle in this question provides us with the diameter, so we first have to solve for the radius. Remember, the radius is half the diameter:

$r=\frac{d}{2}$

$r=\frac{8}{2}$

r=4

Now that we have the radius we can use the formula to solve:

$A=4^2\pi$

Solve:

$A=16\pi\textup{ in}^2$

Report an Error

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Common Core: 7th Grade Math : Area of a circle

Study concepts, example questions & explanations for Common Core: 7th Grade Math

All Common Core: 7th Grade Math Resources

Example Questions

Example Question #122 : Geometry

Example Question #952 : Grade 7

Example Question #123 : Geometry

Example Question #954 : Grade 7

Example Question #131 : Geometry

Example Question #132 : Geometry

All Common Core: 7th Grade Math Resources

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