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Flashcards: Solve Systems of Linear Equations Exactly and Approximately: CCSS.Math.Content.HSA-REI.C.6

Where do the following lines intersect?

$\displaystyle y = 39 x - 23$ and $\displaystyle y = 41 x + 84$

x = 6 $\displaystyle x = 6$

$x = - \frac{107}{2}$ $\displaystyle x = - \frac{107}{2}$

$x = \frac{107}{2}$ $\displaystyle x = \frac{107}{2}$

$\displaystyle x = -107$

x = -5 $\displaystyle x = -5$

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Flashcards: Solve Systems of Linear Equations Exactly and Approximately: CCSS.Math.Content.HSA-REI.C.6

Where do the following lines intersect?

$\displaystyle y = 39 x - 23$ and $\displaystyle y = 41 x + 84$

x = 6 $\displaystyle x = 6$

$x = - \frac{107}{2}$ $\displaystyle x = - \frac{107}{2}$

$x = \frac{107}{2}$ $\displaystyle x = \frac{107}{2}$

$\displaystyle x = -107$

x = -5 $\displaystyle x = -5$

Report an Error Copyright Notice

Flashcards: Solve Systems of Linear Equations Exactly and Approximately: CCSS.Math.Content.HSA-REI.C.6

Where do the following lines intersect?

$\displaystyle y = 39 x - 23$ and $\displaystyle y = 41 x + 84$

Your answer:

x = 6 $\displaystyle x = 6$

Your answer:

$x = \frac{107}{2}$ $\displaystyle x = \frac{107}{2}$

Your answer:

$\displaystyle x = -107$

Your answer:

x = -5 $\displaystyle x = -5$

Correct answer:

$x = - \frac{107}{2}$ $\displaystyle x = - \frac{107}{2}$

Explanation:

In order to figure out this problem, we need to set each of the equations equal to each other, and solve for $\uptext{x}$ $\displaystyle \uptext{x}$.

$\displaystyle 39 x - 23 = 41 x + 84$

$\displaystyle 39 x - 23 + 23 = 41 x + 84 + 23$

$\displaystyle 39 x = 41 x + 107$

$\displaystyle 39 x - 41 x = 41 x + 107 - 41 x$

$\displaystyle - 2 x = 107$

$x = - \frac{107}{2}$ $\displaystyle x = - \frac{107}{2}$

Flashcards: Solve Systems of Linear Equations Exactly and Approximately: CCSS.Math.Content.HSA-REI.C.6

Where do the following lines intersect?

$\displaystyle y = 22 x - 27$ and $\displaystyle y = 2 x + 95$

$x=\frac{61}{5}$ $\displaystyle x=\frac{61}{5}$

$x=- \frac{61}{10}$ $\displaystyle x=- \frac{61}{10}$

x=-5 $\displaystyle x=-5$

$x=\frac{61}{10}$ $\displaystyle x=\frac{61}{10}$

x=6 $\displaystyle x=6$

Report an Error Copyright Notice

Flashcards: Solve Systems of Linear Equations Exactly and Approximately: CCSS.Math.Content.HSA-REI.C.6

Where do the following lines intersect?

$\displaystyle y = 22 x - 27$ and $\displaystyle y = 2 x + 95$

Your answer:

$x=\frac{61}{5}$ $\displaystyle x=\frac{61}{5}$

Your answer:

$x=- \frac{61}{10}$ $\displaystyle x=- \frac{61}{10}$

Your answer:

x=-5 $\displaystyle x=-5$

Your answer:

x=6 $\displaystyle x=6$

Correct answer:

$x=\frac{61}{10}$ $\displaystyle x=\frac{61}{10}$

Explanation:

In order to figure out this problem, we need to set each of the equations equal to each other, and solve for $\uptext{x}$ $\displaystyle \uptext{x}$.

$\displaystyle 22 x - 27 = 2 x + 95$

$\displaystyle 22 x - 27 + 27 = 2 x + 95 + 27$22 x = 2 x + 122

$\displaystyle 22 x - 2 x = 2 x + 122 - 2 x$

$\displaystyle 20 x = 122$

$x = \frac{61}{10}$ $\displaystyle x = \frac{61}{10}$

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Flashcards: Solve Systems of Linear Equations Exactly and Approximately: CCSS.Math.Content.HSA-REI.C.6

All Common Core: High School - Algebra Resources

Flashcards: Solve Systems of Linear Equations Exactly and Approximately: CCSS.Math.Content.HSA-REI.C.6

Flashcards: Solve Systems of Linear Equations Exactly and Approximately: CCSS.Math.Content.HSA-REI.C.6

Flashcards: Solve Systems of Linear Equations Exactly and Approximately: CCSS.Math.Content.HSA-REI.C.6

Flashcards: Solve Systems of Linear Equations Exactly and Approximately: CCSS.Math.Content.HSA-REI.C.6

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