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Common Core: High School - Algebra : Solve Systems of Linear Equations Exactly and Approximately: CCSS.Math.Content.HSA-REI.C.6

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All Common Core: High School - Algebra Resources

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Example Questions

Example Question #541 : High School: Algebra

Where do the following lines intersect?

y = 21 x - 47 and y = 40 x + 28

Possible Answers:

x = -5

x = 6

$x = - \frac{75}{19}$

$x = \frac{75}{19}$

$x = - \frac{150}{19}$

Correct answer:

$x = - \frac{75}{19}$

Explanation:

In order to figure out this problem, we need to set each of the equations equal to each other, and solve for $\uptext{x$ .

21 x - 47 = 40 x + 28

21 x - 47 + 47 = 40 x + 28 + 47

21 x = 40 x + 75

21 x - 40 x = 40 x + 75 - 40 x

- 19 x = 75

$x = - \frac{75}{19}$

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Example Question #542 : High School: Algebra

Where do the following lines intersect?

y = 28 x - 40 and y = 34 x - 90

Possible Answers:

${x=\frac{25}{3}}$

${x=- \frac{25}{3}}$

${x = \frac{50}{3}}$

$\uptext{x}=-5$

$\uptext{x}=6$

Correct answer:

${x=\frac{25}{3}}$

Explanation:

In order to figure out this problem, we need to set each of the equations equal to each other, and solve for $\uptext{x}$ .

28 x - 40 = 34 x - 90

28 x - 40+40=34 x - 90+40

28 x=34 x - 50

28 x-34 x=34 x - 50-34 x

- 6 x=-50

$x=\frac{25}{3}$

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Example Question #543 : High School: Algebra

Where do the following lines intersect?

y = 14 x + 36 and y = 26 x - 10

Possible Answers:

$\uptext{x}=6$

${x=\frac{23}{6}}$

$\uptext{x}=-5$

${x=- \frac{23}{6}}$

${x = \frac{23}{3}}$

Correct answer:

${x=\frac{23}{6}}$

Explanation:

In order to figure out this problem, we need to set each of the equations equal to each other, and solve for $\uptext{x}$ .

14 x + 36 = 26 x - 10

14 x + 36-36=26 x - 10-36

14 x=26 x - 46

14 x-26 x=26 x - 46-26 x

- 12 x=-46

$x=\frac{23}{6}$

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Example Question #544 : High School: Algebra

Where do the following lines intersect?

y = 48 x + 21 and y = 43 x + 15

Possible Answers:

$\uptext{x}=6$

$\uptext{x}=-5$

${x=\frac{6}{5}}$

${x = - \frac{12}{5}}$

${x=- \frac{6}{5}}$

Correct answer:

${x=- \frac{6}{5}}$

Explanation:

In order to figure out this problem, we need to set each of the equations equal to each other, and solve for $\uptext{x}$ .

48 x + 21 = 43 x + 15

48 x + 21-21=43 x + 15-21

48 x=43 x - 6

48 x-43 x=43 x - 6-43 x

5 x=-6

$x=- \frac{6}{5}$

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Example Question #545 : High School: Algebra

Where do the following lines intersect?

y = 48 x + 29 and y = 29 x - 87

Possible Answers:

$\uptext{x}=6$

${x = - \frac{232}{19}}$

${x=- \frac{116}{19}}$

$\uptext{x}=-5$

${x=\frac{116}{19}}$

Correct answer:

${x=- \frac{116}{19}}$

Explanation:

In order to figure out this problem, we need to set each of the equations equal to each other, and solve for $\uptext{x}$ .

48 x + 29 = 29 x - 87

48 x + 29-29=29 x - 87-29

48 x=29 x - 116

48 x-29 x=29 x - 116-29 x

19 x=-116

$x=- \frac{116}{19}$

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Example Question #91 : Reasoning With Equations & Inequalities

Where do the following lines intersect?

y = 16 x + 79 and y = 31 x + 50

Possible Answers:

${x=- \frac{29}{15}}$

$\uptext{x}=6$

${x=\frac{29}{15}}$

$\uptext{x}=-5$

${x = \frac{58}{15}}$

Correct answer:

${x=\frac{29}{15}}$

Explanation:

In order to figure out this problem, we need to set each of the equations equal to each other, and solve for $\uptext{x}$ .

16 x + 79 = 31 x + 50

16 x + 79-79=31 x + 50-79

16 x=31 x - 29

16 x-31 x=31 x - 29-31 x

- 15 x=-29

$x=\frac{29}{15}$

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Example Question #92 : Reasoning With Equations & Inequalities

Where do the following lines intersect?

y = 26 x + 5 and y = 36 x - 87

Possible Answers:

${x = \frac{92}{5}}$

$\uptext{x}=-5$

${x=- \frac{46}{5}}$

${x=\frac{46}{5}}$

$\uptext{x}=6$

Correct answer:

${x=\frac{46}{5}}$

Explanation:

In order to figure out this problem, we need to set each of the equations equal to each other, and solve for $\uptext{x}$ .

26 x + 5 = 36 x - 87

26 x + 5-5=36 x - 87-5

26 x=36 x - 92

26 x-36 x=36 x - 92-36 x

- 10 x=-92

$x=\frac{46}{5}$

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Example Question #93 : Reasoning With Equations & Inequalities

Where do the following lines intersect?

y = 46 x + 47 and y = 27 x + 12

Possible Answers:

${x=\frac{35}{19}}$

$\uptext{x}=6$

${x=- \frac{35}{19}}$

${x = - \frac{70}{19}}$

$\uptext{x}=-5$

Correct answer:

${x=- \frac{35}{19}}$

Explanation:

In order to figure out this problem, we need to set each of the equations equal to each other, and solve for $\uptext{x}$ .

46 x + 47 = 27 x + 12

46 x + 47-47=27 x + 12-47

46 x=27 x - 35

46 x-27 x=27 x - 35-27 x

19 x=-35

$x=- \frac{35}{19}$

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Example Question #94 : Reasoning With Equations & Inequalities

Where do the following lines intersect?

y = 48 x + 35 and y = 23 x + 83

Possible Answers:

$\uptext{x}=-5$

${x=\frac{48}{25}}$

${x = \frac{96}{25}}$

${x=- \frac{48}{25}}$

$\uptext{x}=6$

Correct answer:

${x=\frac{48}{25}}$

Explanation:

In order to figure out this problem, we need to set each of the equations equal to each other, and solve for $\uptext{x}$ .

48 x + 35 = 23 x + 83

48 x + 35-35=23 x + 83-35

48 x=23 x + 48

48 x-23 x=23 x + 48-23 x

25 x=48

$x=\frac{48}{25}$

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Example Question #95 : Reasoning With Equations & Inequalities

Where do the following lines intersect?

y = 23 x - 53 and y = 41 x + 35

Possible Answers:

${x=\frac{44}{9}}$

${x = - \frac{88}{9}}$

$\uptext{x}=-5$

$\uptext{x}=6$

${x=- \frac{44}{9}}$

Correct answer:

${x=- \frac{44}{9}}$

Explanation:

In order to figure out this problem, we need to set each of the equations equal to each other, and solve for $\uptext{x}$ .

23 x - 53 = 41 x + 35

23 x - 53+53=41 x + 35+53

23 x=41 x + 88

23 x-41 x=41 x + 88-41 x

- 18 x=88

$x=- \frac{44}{9}$

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All Common Core: High School - Algebra Resources

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Common Core: High School - Algebra : Solve Systems of Linear Equations Exactly and Approximately: CCSS.Math.Content.HSA-REI.C.6

Study concepts, example questions & explanations for Common Core: High School - Algebra

All Common Core: High School - Algebra Resources

Example Questions

Example Question #541 : High School: Algebra

Example Question #542 : High School: Algebra

Example Question #543 : High School: Algebra

Example Question #544 : High School: Algebra

Example Question #545 : High School: Algebra

Example Question #91 : Reasoning With Equations & Inequalities

Example Question #92 : Reasoning With Equations & Inequalities

Example Question #93 : Reasoning With Equations & Inequalities

Example Question #94 : Reasoning With Equations & Inequalities

Example Question #95 : Reasoning With Equations & Inequalities

All Common Core: High School - Algebra Resources

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