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All Common Core: High School - Functions Resources

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Flashcards: Function Notation: CCSS.Math.Content.HSF-IF.A.2

Given the following functions and , calculate g(f(2)) .

$\\f(x)=3x+2 \\g(x)=x^2-2x+1$

g(f(2))=36

g(f(2))=49

g(f(2))=27

g(f(2))=29

g(f(2))=57

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Flashcards: Function Notation: CCSS.Math.Content.HSF-IF.A.2

Given the following functions and , calculate g(f(2)) .

$\\f(x)=3x+2 \\g(x)=x^2-2x+1$

Your answer:

g(f(2))=36

Your answer:

g(f(2))=27

Your answer:

g(f(2))=29

Your answer:

g(f(2))=57

Correct answer:

g(f(2))=49

Explanation:

This question is testing the knowledge and skills of calculating a function value. Similar to domain and range, calculating the function value requires the application of input values into the function to find the output value. In other words, evaluating a function at a particular value results in the function value; which is another way of saying function value is the output.

For the purpose of Common Core Standards, function notation and evaluation fall within the Cluster A of the function and use of function notation concept (CCSS.MATH.CONTENT.HSF-IF.A).

Knowing the standard and the concept for which it relates to, we can now do the step-by-step process to solve the problem in question.

Step 1: Identify the input value.

Since the inside function is in the form f(x) and the question asks to calculate f(2) we know that the input value is two.

$f(2)\rightarrow x=2$

After the function value of f(2) is calculated, it will be the input value for g(x) .

Step 2: Given the function, input the desired value.

In step one the input value of two was found. Now substitute 2 in for every in the function f(x) .

f(x)=3x+2

$\\ f(2)=3(2)+2 \\f(2)=6+2 \\f(2)=8$

Step 3: Substitute the function value of the inside portion into g(x) .

g(f(2))=g(8)

$\\g(x)=x^2-2x+1 \\g(8)=8^2-2(8)+1 \\g(8)=64-16+1 \\g(8)=49$

Flashcards: Function Notation: CCSS.Math.Content.HSF-IF.A.2

Given the following function , calculate g(2) .

$g(x)=\frac{x^2-3}{x^3+1}$

$g(2)=\frac{1}{10}$

$g(2)=\frac{6}{9}$

$g(2)=\frac{2}{9}$

$g(2)=\frac{1}{9}$

g(2)=1

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Flashcards: Function Notation: CCSS.Math.Content.HSF-IF.A.2

Given the following function , calculate g(2) .

$g(x)=\frac{x^2-3}{x^3+1}$

Your answer:

$g(2)=\frac{1}{10}$

Your answer:

$g(2)=\frac{6}{9}$

Your answer:

$g(2)=\frac{2}{9}$

Your answer:

g(2)=1

Correct answer:

$g(2)=\frac{1}{9}$

Explanation:

For the purpose of Common Core Standards, function notation and evaluation fall within the Cluster A of the function and use of function notation concept (CCSS.MATH.CONTENT.HSF-IF.A).

Knowing the standard and the concept for which it relates to, we can now do the step-by-step process to solve the problem in question.

Step 1: Identify the input value.

Since the function is in the form g(x) and the question asks to calculate g(2) we know that the input value is two.

$g(2)\rightarrow x=2$

Step 2: Given the function, input the desired value.

In step one the input value of two was found. Now substitute 2 in for every in the function.

$g(x)=\frac{x^2-3}{x^3+1}$

$g(2)=\frac{2^2-3}{2^3+1}$

$g(2)=\frac{4-3}{8+1}$

$g(2)=\frac{1}{9}$

Step 3: Answer the question.

This particular function when solved algebraically results in one value.

The answer is

$g(2)=\frac{1}{9}$

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All Common Core: High School - Functions Resources

Flashcards: Function Notation: CCSS.Math.Content.HSF-IF.A.2

Flashcards: Function Notation: CCSS.Math.Content.HSF-IF.A.2

Flashcards: Function Notation: CCSS.Math.Content.HSF-IF.A.2

Flashcards: Function Notation: CCSS.Math.Content.HSF-IF.A.2

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