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All Common Core: High School - Number and Quantity Resources

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Flashcards: Compute Magnitude and Direction of a Scalar Multiple: CCSS.Math.Content.HSN-VM.B.5b

Calculate $\left \| -3v\right \|$ , where v=<0,2> . Also determine the direction of the resulting vector.

$\left \| -3\:v\right \|=-3$ , Direction is away from .

$\left \| -3\:v\right \|=-6$ , Direction is away from .

$\left \| -3\:v\right \|=6$ , Direction is away from .

$\left \| -3\:v\right \|=3$ , Direction is the same as .

$\left \| -3\:v\right \|=6$ , Direction is the same as .

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Flashcards: Compute Magnitude and Direction of a Scalar Multiple: CCSS.Math.Content.HSN-VM.B.5b

Calculate $\left \| -3v\right \|$ , where v=<0,2> . Also determine the direction of the resulting vector.

Your answer:

$\left \| -3\:v\right \|=-3$ , Direction is away from .

Your answer:

$\left \| -3\:v\right \|=-6$ , Direction is away from .

Your answer:

$\left \| -3\:v\right \|=3$ , Direction is the same as .

Your answer:

$\left \| -3\:v\right \|=6$ , Direction is the same as .

Correct answer:

$\left \| -3\:v\right \|=6$ , Direction is away from .

Explanation:

In order to solve the first part of the problem, we need to remember how to take the magnitude of a vector and scalar.

Now lets calculate this.

$=3\cdot\sqrt{0^2+2^2}=3\cdot\sqrt{0+4}=3\sqrt{4}=3\cdot2=6$

As for the direction of the vector, since c<0 , the resulting vector will be against the original vector .

See below for a picture.

Vecscale

Flashcards: Compute Magnitude and Direction of a Scalar Multiple: CCSS.Math.Content.HSN-VM.B.5b

Calculate $\left \| 1v\right \|$ , where v=<-2,-4> . Also determine the direction of the resulting vector.

$\left \| 1\:v\right \|=2\sqrt{5}$ , Direction is the same as .

$\left \| 1\:v\right \|=2\sqrt{5}$ , Direction is away from .

$\left \| 1\:v\right \|=-2\sqrt{5}$ , Direction is away from .

$\left \| 1\:v\right \|=2$ , Direction is the same as .

$\left \| 1\:v\right \|=\sqrt{5}$ , Direction is the same as .

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Flashcards: Compute Magnitude and Direction of a Scalar Multiple: CCSS.Math.Content.HSN-VM.B.5b

Calculate $\left \| 1v\right \|$ , where v=<-2,-4> . Also determine the direction of the resulting vector.

Your answer:

$\left \| 1\:v\right \|=2\sqrt{5}$ , Direction is away from .

Your answer:

$\left \| 1\:v\right \|=-2\sqrt{5}$ , Direction is away from .

Your answer:

$\left \| 1\:v\right \|=2$ , Direction is the same as .

Your answer:

$\left \| 1\:v\right \|=\sqrt{5}$ , Direction is the same as .

Correct answer:

$\left \| 1\:v\right \|=2\sqrt{5}$ , Direction is the same as .

Explanation:

In order to solve the first part of the problem, we need to remember how to take the magnitude of a vector and scalar.

Now lets calculate this.

$=1\cdot\sqrt{(-2)^2+(-4)^2}=1\cdot\sqrt{4+16}=1\sqrt{20}=2\sqrt{5}$

As for the direction of the vector, since c>0 , the resulting vector will be in the same direction as the original vector

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All Common Core: High School - Number and Quantity Resources

Flashcards: Compute Magnitude and Direction of a Scalar Multiple: CCSS.Math.Content.HSN-VM.B.5b

Flashcards: Compute Magnitude and Direction of a Scalar Multiple: CCSS.Math.Content.HSN-VM.B.5b

Flashcards: Compute Magnitude and Direction of a Scalar Multiple: CCSS.Math.Content.HSN-VM.B.5b

Flashcards: Compute Magnitude and Direction of a Scalar Multiple: CCSS.Math.Content.HSN-VM.B.5b

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