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High School Chemistry : Identifying Unknown Concentration

Study concepts, example questions & explanations for High School Chemistry

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Example Questions

Example Question #11 : Titrations

30mL of a solution of NaOH of unknown concentration mixed with 19mL of $10^{-3}M$ HCl produced a solution with a pH of 7. What is the concentration of the NaOH solution?

Possible Answers:

0.002

$6.3\cdot 10^{-4}$

$6.3\cdot 10^{-3}$

None of these

0.0001

Correct answer:

$6.3\cdot 10^{-4}$

Explanation:

For this question use the following formula:

N_A M_A V_A = N_B M_B V_B

N_A is the number of acidic hydrogens on the acid, is the molarity of the acid, is the volume of the acid, is the number of basic hydroxides on the base, is the molarity of the base, is the volume of the base

Rearrange the equation for the molarity of the base:

$\frac{N_A M_A V_A }{N_B V_B}= M_B$

Plug in known values and solve.

$M_B=6.3\cdot10^{-4}M$

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Example Question #72 : Acid Base Chemistry

29mL of a solution of $10^{-4}M$ NaOH is mixed with 65mL of an HCl solution of unknown concentration produced a solution with a pH of 7. What is the concentration of the HCl solution?

Possible Answers:

$3.0\cdot10^{-5}M$

None of these

$10^{-4}M$

$1.5\cdot10^{-5}M$

$4.5\cdot10^{-5}M$

Correct answer:

$4.5\cdot10^{-5}M$

Explanation:

For this question use the following formula:

N_A M_A V_A = N_B M_B V_B

Rearrange the equation for the molarity of the acid:

$\frac{N_B M_B V_B }{N_A V_A}= M_A$

Plug in known values and solve.

$M_A=4.5\cdot10^{-4}M$

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Example Question #11 : Titrations

39mL of a solution of $10^{-4}M$ NaOH is mixed with 24mL of an HCl solution of unknown concentration produced a solution with a pH of 7. What is the concentration of the HCl solution?

Possible Answers:

None of these

$1.5\cdot10^{-4}$

$1.63\cdot10^{-4}M$

$2.5\cdot10^{-4}$

$3.75\cdot10^{-4}$

Correct answer:

$1.63\cdot10^{-4}M$

Explanation:

For this question use the following formula:

N_A M_A V_A = N_B M_B V_B

Rearrange the equation for the molarity of the acid:

$\frac{N_B M_B V_B }{N_A V_A}= M_A$

Plug in known values and solve.

$M_A=1.63\cdot10^{-4}M$

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Example Question #482 : High School Chemistry

It takes 25mL of a .001M NaOH

to neutralize 5mL of a solution of HCl

of unknown concentration. What is the concentration of the unknown solution?

Possible Answers:

.05M

.015M

.005M

.010M

None of these

Correct answer:

.005M

Explanation:

For this question use the following formula:

N_A M_A V_A = N_B M_B V_B

Rearrange the equation for the molarity of the acid:

$\frac{N_B M_B V_B }{N_A V_A}= M_A$

Plug in known values and solve.

M_A=0.005M

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Example Question #481 : High School Chemistry

It takes 35mL of .01M HCl

to neutralize 5mL of a solution of NaOH

of unknown concentration. What is the concentration of the unknown solution?

Possible Answers:

.007M

.014M

.07M

None of these

.035M

Correct answer:

.07M

Explanation:

For this question use the following formula:

is the number of acidic hydrogens on the acid, is the molarity of the acid, is the volume of the acid, is the number of basic hydroxides on the base, is the molarity of the base, is the volume of the base

Rearrange the equation for the molarity of the acid:

Plug in known values and solve.

Report an Error

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High School Chemistry : Identifying Unknown Concentration

Study concepts, example questions & explanations for High School Chemistry

All High School Chemistry Resources

Example Questions

Example Question #11 : Titrations

Example Question #72 : Acid Base Chemistry

Example Question #11 : Titrations

Example Question #482 : High School Chemistry

Example Question #481 : High School Chemistry

All High School Chemistry Resources

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