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High School Math : Area of a Figure

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Example Questions

Example Question #1 : How To Find The Area Of A Triangle In Pre Algebra

If a triangle has an area of $\displaystyle 44$ and a base of $\displaystyle 11$, what is the height?

Possible Answers:

$\displaystyle 4$

$\displaystyle 8$

$\displaystyle 16$

$\displaystyle 32$

$\displaystyle 2$

Correct answer:

$\displaystyle 8$

Explanation:

The formula for the area of a triangle is half of the base times the height: $A=\frac{1}{2}bh$ $\displaystyle A=\frac{1}{2}bh$

Plug in our given information and solve:

$A=\frac{1}{2}bh$ $\displaystyle A=\frac{1}{2}bh$

$44=\frac{1}{2}*11*h$ $\displaystyle 44=\frac{1}{2}*11*h$

Multiply both sides by $\displaystyle 2$ to get rid of the $\frac{1}{2}$ $\displaystyle \frac{1}{2}$:

88=11*h $\displaystyle 88=11*h$

Divide both sides by $\displaystyle 11$:

$\frac{88}{11}=h$ $\displaystyle \frac{88}{11}=h$

8=h $\displaystyle 8=h$

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Example Question #4 : How To Find The Area Of A Triangle In Pre Algebra

What is the area of a triangle with a base of $\displaystyle 16$ and a height of $\displaystyle 3$?

Possible Answers:

$\displaystyle 48$

$\displaystyle 19$

$\displaystyle 32$

$\displaystyle 24$

$\displaystyle 12$

Correct answer:

$\displaystyle 24$

Explanation:

The formula for the area of a triangle is $A=\frac{1}{2}b*h$ $\displaystyle A=\frac{1}{2}b*h$.

Plug in our given values.

$A=\frac{1}{2}b*h$ $\displaystyle A=\frac{1}{2}b*h$

$A=\frac{1}{2}(16)*3$ $\displaystyle A=\frac{1}{2}(16)*3$

A=8*3 $\displaystyle A=8*3$

A=24 $\displaystyle A=24$

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Example Question #1 : How To Find The Area Of A Triangle In Pre Algebra

What is the area of a triangle with a base of $\displaystyle 5$ and a height of $\displaystyle 12$?

Possible Answers:

$\displaystyle 13$

$\displaystyle 17$

$\displaystyle 30$

$\displaystyle 24$

$\displaystyle 34$

Correct answer:

$\displaystyle 30$

Explanation:

The formula for the area of a triangle is $A=\frac{1}{2}b*h$ $\displaystyle A=\frac{1}{2}b*h$.

Plug in our given values.

$A=\frac{1}{2}b*h$ $\displaystyle A=\frac{1}{2}b*h$

$A=\frac{1}{2}5*12$ $\displaystyle A=\frac{1}{2}5*12$

$A=\frac{1}{2}*60$ $\displaystyle A=\frac{1}{2}*60$

A=30 $\displaystyle A=30$

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Example Question #6 : How To Find The Area Of A Triangle In Pre Algebra

What is the base of a triangle if the height is $\displaystyle 20$ and the area is $\displaystyle 50$?

Possible Answers:

$\displaystyle 30$

2.5 $\displaystyle 2.5$

$\displaystyle 5$

$\displaystyle 50$

$\displaystyle 10$

Correct answer:

$\displaystyle 5$

Explanation:

The formula for the area of a triangle is $A=\frac{1}{2}*b*h$ $\displaystyle A=\frac{1}{2}*b*h$.

Plug in our given values.

$50=\frac{1}{2}*b*20$ $\displaystyle 50=\frac{1}{2}*b*20$

Combine like terms.

$50=(\frac{1}{2}*20)*b$ $\displaystyle 50=(\frac{1}{2}*20)*b$

50=10*b $\displaystyle 50=10*b$

Divide both sides by $\displaystyle 10$ to isolate $\displaystyle b$.

$\frac{50}{10}=b$ $\displaystyle \frac{50}{10}=b$

5=b $\displaystyle 5=b$

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Example Question #2 : How To Find The Area Of A Triangle In Pre Algebra

What is the area of a triangle with a base of $\displaystyle 4$ and a height of $\displaystyle 90$?

Possible Answers:

270 $\displaystyle 270$

188 $\displaystyle 188$

360 $\displaystyle 360$

180 $\displaystyle 180$

Correct answer:

180 $\displaystyle 180$

Explanation:

The equation for the area of a triangle is

$A=(\frac{1}{2})(base)(height)$ $\displaystyle A=(\frac{1}{2})(base)(height)$

We plug the base of $\displaystyle 4$ and the height of $\displaystyle 90$ into the equation to get

$A=(\frac{1}{2})(4)(90)$ $\displaystyle A=(\frac{1}{2})(4)(90)$

We then multiply to get the answer of A=180 $\displaystyle A=180$.

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Example Question #451 : Pre Algebra

What is the area of a triangle with a base of $\displaystyle 4$ and a height of $\displaystyle 7$?

Possible Answers:

8.06 $\displaystyle 8.06$

$\displaystyle 18$

$\displaystyle 14$

$\displaystyle 28$

$\displaystyle 15$

Correct answer:

$\displaystyle 14$

Explanation:

The formula for the area of a triangle is $A=\frac{1}{2}bh$ $\displaystyle A=\frac{1}{2}bh$.

Plug in our given values and solve.

$A=\frac{1}{2}bh$ $\displaystyle A=\frac{1}{2}bh$

$A=\frac{1}{2}(4)(7)$ $\displaystyle A=\frac{1}{2}(4)(7)$

A=2*7 $\displaystyle A=2*7$

A=14 $\displaystyle A=14$

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Example Question #9 : How To Find The Area Of A Triangle In Pre Algebra

What is the area of a triangle with a base of $\displaystyle 80$ and a height of 120 $\displaystyle 120$?

Possible Answers:

A=200 $\displaystyle A=200$

A=4800 $\displaystyle A=4800$

A=9600 $\displaystyle A=9600$

A=2400 $\displaystyle A=2400$

Correct answer:

A=4800 $\displaystyle A=4800$

Explanation:

The equation for the area of a triangle is .

We plug the base of $\displaystyle 80$ and the height of 120 $\displaystyle 120$ into the equation to get $A=\frac{1}{2}(80)(120)$ $\displaystyle A=\frac{1}{2}(80)(120)$.

We then multiply to get the answer of A=4800 $\displaystyle A=4800$.

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Example Question #8 : How To Find The Area Of A Triangle In Pre Algebra

What is the area of a triangle with a base of $\displaystyle 8$ and a height of $\displaystyle 28$?

Possible Answers:

A=192 $\displaystyle A=192$

A=112 $\displaystyle A=112$

A=120 $\displaystyle A=120$

A=98 $\displaystyle A=98$

Correct answer:

A=112 $\displaystyle A=112$

Explanation:

The equation for the area of a triangle is

We plug the base of $\displaystyle 8$ and the height of $\displaystyle 28$ into the equation to get

$A=(\frac{1}{2})(8)(28)$ $\displaystyle A=(\frac{1}{2})(8)(28)$

We then multiply to get the answer of A=112 $\displaystyle A=112$.

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Example Question #11 : How To Find The Area Of A Triangle In Pre Algebra

What is the area of a triangle with a base of $\displaystyle 5$ and a height of $\displaystyle 14$?

Possible Answers:

$\displaystyle 30$

$\displaystyle 45$

$\displaystyle 70$

$\displaystyle 35$

Correct answer:

$\displaystyle 35$

Explanation:

To find the area of a triangle, use the equation:

$Area=\frac{1}{2}(Base)(Height)$ $\displaystyle Area=\frac{1}{2}(Base)(Height)$

Substitute the given values for base and height into the equation:

$Area=\frac{1}{2}(5)(14)$ $\displaystyle Area=\frac{1}{2}(5)(14)$

Area=35 $\displaystyle Area=35$

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Example Question #41 : Area Of A Figure

Find the area of a triangle with a base of 3 inches and a height of 14 inches.

Possible Answers:

$48\ in^{2}$ $\displaystyle 48\ in^{2}$

$52\ in^{2}$ $\displaystyle 52\ in^{2}$

$21\ in^{2}$ $\displaystyle 21\ in^{2}$

$42\ in^{2}$ $\displaystyle 42\ in^{2}$

$24\ in^{2}$ $\displaystyle 24\ in^{2}$

Correct answer:

$21\ in^{2}$ $\displaystyle 21\ in^{2}$

Explanation:

Apply the formula for the area of a triangle: $\frac{1}{2}bh$ $\displaystyle \frac{1}{2}bh$

A = 3 * 14 * (1/2) = 21

Make sure that your units are squared.

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High School Math : Area of a Figure

Study concepts, example questions & explanations for High School Math

All High School Math Resources

Example Questions

Example Question #1 : How To Find The Area Of A Triangle In Pre Algebra

Example Question #4 : How To Find The Area Of A Triangle In Pre Algebra

Example Question #1 : How To Find The Area Of A Triangle In Pre Algebra

Example Question #6 : How To Find The Area Of A Triangle In Pre Algebra

Example Question #2 : How To Find The Area Of A Triangle In Pre Algebra

Example Question #451 : Pre Algebra

Example Question #9 : How To Find The Area Of A Triangle In Pre Algebra

Example Question #8 : How To Find The Area Of A Triangle In Pre Algebra

Example Question #11 : How To Find The Area Of A Triangle In Pre Algebra

Example Question #41 : Area Of A Figure

All High School Math Resources

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