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High School Math : Algebraic Equations

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Example Questions

Example Question #334 : High School Math

Solve for when x+18=43

Possible Answers:

x=25

x=41

x=31

x=61

Correct answer:

x=25

Explanation:

To solve for we must get all of the numbers on the other side of the equation as .

To do this in a problem where a number is being added to , we must subtract the number from both sides of the equation.

In this case the number is so we subtract from each side of the equation to make it look like this x+18-18=43-18

The 's on the left side cancel to get x=43-18 .

Then we perform the necessary subtraction to get the answer of x=25 .

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Example Question #51 : How To Solve One Step Equations With Integers In Pre Algebra

Solve for when 15x=45 .

Possible Answers:

x=15

x=30

x=3

x=675

Correct answer:

x=3

Explanation:

To solve for we must get all of the numbers on the other side of the equation as .

To do this in a problem where is being multiplied by a number, we must divide both sides of the equation by the number.

In this case the number is so we divide each side of the equation by to make it look like this

$\frac{15x}{15}=\frac{45}{15}$

The 's cancel to leave by itself

$x=\frac{45}{15}$

Then we perform the necessary division to get the answer of x=3 .

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Example Question #52 : How To Solve One Step Equations With Integers In Pre Algebra

Solve for when x-52=53

Possible Answers:

x=105

x=47

x=1

x=93

Correct answer:

x=105

Explanation:

To solve for we must get all of the numbers on the other side of the equation as .

To do this in a problem where is being subtracted by a number, we must add the number to both sides of the equation.

In this case the number is so we add to each side of the equation to make it look like this

x-52+52=53+52

The 's cancel on the left side and leave by itself

x=52+53

Then we perform the necessary addition to get the answer of x=105 .

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Example Question #53 : How To Solve One Step Equations With Integers In Pre Algebra

Solve for when x+52=68

Possible Answers:

x=120

x=64

x=140

x=16

Correct answer:

x=16

Explanation:

To solve for we must get all of the numbers on the other side of the equation as .

To do this in a problem where a number is being added to , we must subtract the number from both sides of the equation.

In this case the number is so we subtract from each side of the equation to make it look like this

x+52-52=68-52

The 's on the left side cancel to get

x=68-52

Then we perform the necessary subtraction to get the answer of x=16 .

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Example Question #54 : How To Solve One Step Equations With Integers In Pre Algebra

Solve for when

$\frac{x}{15}=3$

Possible Answers:

x=50

x=5

x=45

x=30

Correct answer:

x=45

Explanation:

To solve for we must get all of the numbers on the other side of the equation as .

To do this in a problem where is being divided by a number, we must multiply both sides of the equation by the number.

In this case the number is so we multiply each side of the equation by to make it look like this

$15\cdot \left(\frac{x}{15}\right)=3\cdot (15)$

The 's on the left side cancel so we only have

x=3(15)

Then we perform the necessary multiplication to get the answer of x=45 .

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Example Question #55 : How To Solve One Step Equations With Integers In Pre Algebra

Solve for when

$\frac{x}{3}=16$

Possible Answers:

x=8

x=39

x=24

x=48

Correct answer:

x=48

Explanation:

To solve for we must get all of the numbers on the other side of the equation as .

To do this in a problem where is being divided by a number, we must multiply both sides of the equation by the number.

In this case the number is so we multiply each side of the equation by to make it look like this

$3\cdot \left(\frac{x}{3}\right)=(16)\cdot 3$

The 's on the left side cancel so we only have

x=16(3)

Then we perform the necessary multiplication to get the answer of x=48 .

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Example Question #81 : Algebraic Equations

Solve for when 8x=32 .

Possible Answers:

x=8

x=4

x=32

x=16

Correct answer:

x=4

Explanation:

To solve for we must get all of the numbers on the other side of the equation as .

To do this in a problem where is being multiplied by a number, we must divide both sides of the equation by the number.

In this case the number is so we divide each side of the equation by to make it look like this

$\frac{8x}{8}=\frac{32}{8}$

The 's cancel to leave by itself

$x=\frac{32}{8}$

Then we perform the necessary division to get the answer of x=4 .

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Example Question #51 : How To Solve One Step Equations With Integers In Pre Algebra

Solve for when x-71=64

Possible Answers:

x=132

x=151

x=135

x=-7

Correct answer:

x=135

Explanation:

To solve for we must get all of the numbers on the other side of the equation as .

To do this in a problem where is being subtracted by a number, we must add the number to both sides of the equation.

In this case the number is so we add to each side of the equation to make it look like this

x-71+71=64+71

The 's cancel on the left side and leave by itself

x=64+71

Then we perform the necessary addition to get the answer of x=135 .

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Example Question #51 : How To Solve One Step Equations

Solve for when x+93=151 .

Possible Answers:

x=93

x=244

x=58

x=51

Correct answer:

x=58

Explanation:

To solve for we must get all of the numbers on the other side of the equation as .

To do this in a problem where a number is being added to , we must subtract the number from both sides of the equation.

In this case the number is so we subtract from each side of the equation to make it look like this

x+93-93=151-93

The 's on the left side cancel to get

x=151-93

Then we perform the necessary subtraction to get the answer of x=58 .

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Example Question #51 : How To Solve One Step Equations With Integers In Pre Algebra

Solve for :

4=7-p

Possible Answers:

p=3

p=0

p=2

p=1

Correct answer:

p=3

Explanation:

4=7-p

4+p=7-p+p

4+p-4=7-4

p=3

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High School Math : Algebraic Equations

Study concepts, example questions & explanations for High School Math

All High School Math Resources

Example Questions

Example Question #334 : High School Math

Example Question #51 : How To Solve One Step Equations With Integers In Pre Algebra

Example Question #52 : How To Solve One Step Equations With Integers In Pre Algebra

Example Question #53 : How To Solve One Step Equations With Integers In Pre Algebra

Example Question #54 : How To Solve One Step Equations With Integers In Pre Algebra

Example Question #55 : How To Solve One Step Equations With Integers In Pre Algebra

Example Question #81 : Algebraic Equations

Example Question #51 : How To Solve One Step Equations With Integers In Pre Algebra

Example Question #51 : How To Solve One Step Equations

Example Question #51 : How To Solve One Step Equations With Integers In Pre Algebra

All High School Math Resources

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