High School Physics : Understanding Wavelength and Frequency

Study concepts, example questions & explanations for High School Physics

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Example Questions

Example Question #21 : Understanding Wavelength And Frequency

A saxophone plays a B-flat at \(\displaystyle 466.16Hz\) in normal air at \(\displaystyle 20^\circ C\). What is the wavelength of the note?

\(\displaystyle v_{sound}=343\frac{m}{s}\)

Possible Answers:

\(\displaystyle 123m\)

\(\displaystyle 1.4m\)

\(\displaystyle 0.74m\)

\(\displaystyle 0.67m\)

\(\displaystyle 1.6*10^5m\)

Correct answer:

\(\displaystyle 0.74m\)

Explanation:

Remember that the velocity of a wave is always equal to the wavelength times the frequency:

\(\displaystyle v=\lambda*f\)

All sound waves will travel with the same velocity, the speed of sound. Using this value and the given frequency, we can calculate the wavelength.

\(\displaystyle 343\frac{m}{s}=\lambda*466.16Hz\)

\(\displaystyle \frac{343\frac{m}{s}}{466.16Hz}=\lambda\)

\(\displaystyle 0.74m=\lambda\)

Example Question #22 : Understanding Wavelength And Frequency

A flute plays a note with a frequency of \(\displaystyle 481Hz\). What is the period of this note?

Possible Answers:

\(\displaystyle 0.046s\)

\(\displaystyle 0.002s\)

\(\displaystyle 0.015s\)

\(\displaystyle 21.93s\)

\(\displaystyle 0.21s\)

Correct answer:

\(\displaystyle 0.002s\)

Explanation:

Period is the inverse of frequency:

\(\displaystyle T=\frac{1}{f}\).

Given the frequency, we simply need to take the reciprocal in order to find the period.

\(\displaystyle T=\frac{1}{481Hz}\)

\(\displaystyle T=0.002s\)

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