The measures of the four angles of a quadrilateral total $\displaystyle 360^{\circ }$, so set up this equation and solve:

$\displaystyle 84 + 97+ x + (x + 15) = 360$

$\displaystyle x + x + 84 + 97 + 15 = 360$

$\displaystyle 2x + 196 = 360$

$\displaystyle 2x + 196 -196 = 360-196$

$\displaystyle 2x = 164$

$\displaystyle 2x \div 2= 164 \div 2$

$\displaystyle x=82^{\circ }$

$\displaystyle x - 7.2 = -1.3$

$\displaystyle x - 7.2 + 7.2 = -1.3+ 7.2$

$\displaystyle x = -1.3+ 7.2 =+\left ( 7.2 - 1.3 \right ) = 5.9$

$\displaystyle t + 5.9 = 2.6$

$\displaystyle t + 5.9 -5.9 = 2.6-5.9$

$\displaystyle t = 2.6-5.9 = 2.6 + (-5.9) = - (5.9 - 2.6) = -3.3$

$\displaystyle 8t - 12 = 3t - 43$

$\displaystyle 8t -3t - 12 = 3t -3t - 43$

$\displaystyle (8 -3)t - 12 = - 43$

$\displaystyle 5t - 12 = - 43$

$\displaystyle 5t - 12+12 = - 43+12$

$\displaystyle 5t = - (43 - 12)$

$\displaystyle 5t = - 31$

$\displaystyle 5t \div 5 = - 31 \div 5$

$\displaystyle t = -6 \frac{1}{5}$

Solve the exponents:

$\displaystyle 2^{2}=4$

Then solve:

$\displaystyle 4+6=10$

Answer: $\displaystyle 10$

Multiply: $\displaystyle 5\cdot 5\cdot 5\cdot 5=625$

Answer: $\displaystyle 625$

Multiply:

$\displaystyle 6\cdot 6\cdot 6\cdot 6=1296$

Answer: $\displaystyle 1296$

Multiply:

$\displaystyle 9\cdot 9\cdot 9=729$

Answer: $\displaystyle 729$

$\displaystyle 2+4(x-1)=26$

By using order of operations we must first multiply by using the distributive property

$\displaystyle 4(x-1)=4(x)+4(-1)$

This gives us: $\displaystyle 2+ 4x-4=26$ 

Next we must combine like terms: $\displaystyle 2-4=-2$

Rewrite the equation after combining like terms: $\displaystyle 4x-2=26$

Add a positive 2 to both sides of the equation. $\displaystyle 4x-2+2=26+2$

Again combine like terms and rewrite equation $\displaystyle 4x=28$

Divide by 4 on both sides of the equation 

$\displaystyle \frac{4x}{4}=\frac{28}{4}$

$\displaystyle x=7$

When we have an exponent raised to an exponent, our rule is to multiply the exponent by the exponent.  Lets look at an easier problem to show this rule.

$\displaystyle (2^2)^2$

In this problem it is saying two squared, times two squared correct? (Yes)

So what is 2 squared? (4), what is 2 squared again? (4).

So this problem is saying $\displaystyle 4\times 4$ which is $\displaystyle 16$. This is one way we can do the equation. Another is a rule that was mentioned before. When we have an exponent raised by an exponent *only in these cases* we can multiply the exponents by each other. 

So in our easier example the exponent $\displaystyle (2)$ times the other exponent $\displaystyle (2)$$\displaystyle =4$.

Looks like this 

$\displaystyle 2^{2\times 2}= 2^4$

Or the same thing as saying

$\displaystyle 2\times 2\times 2\times 2=16$. Either way we get the same answer!

Returning back to the original problem. We have the exponent 2 raised to the exponent 8. We can multiply them by each other in this case. $\displaystyle 2\times 8=16$

So as the question asks us to simplify we just need to put $\displaystyle 3^1^6$