In order to solve this problem, use the given information to work backwards to find a side length of the rhombus: 

$\displaystyle A=(base\times altitude)$


$\displaystyle 108=(base\times 12)$


$\displaystyle base=108\div12=9$

Then apply the perimeter formula: 

$\displaystyle P=4S$, where $\displaystyle S$ is equal to the length of one side of the rhombus. 

The solution is:

$\displaystyle P=4\times9=36$

In order to solve this problem, use the given information to work backwards to find a side length of the rhombus: 

$\displaystyle A=(base\times altitude)$


$\displaystyle 56=(base\times 7)$

$\displaystyle base=\frac{56}{7}=8$


Then apply the perimeter formula: 

$\displaystyle p=4S$, where $\displaystyle s=$ the length of one side of the rhombus.

$\displaystyle p=4(8)=32$

In order to solve this problem, use the given information to work backwards to find a side length of the rhombus: 

$\displaystyle A=(base\times altitude)$

$\displaystyle 240=(base\times 16)$

$\displaystyle base=\frac{240}{16}=15$

Then apply the formula: $\displaystyle p=4S$, where $\displaystyle S= 15$

$\displaystyle p=4(15)=60$

In order to solve this problem, use the given information to work backwards to find a side length of the rhombus: 

$\displaystyle A=(base\times altitude)$


$\displaystyle 9=(base\times 1.8)$

$\displaystyle base=\frac{9}{1.8}=5$
Then apply the formula: $\displaystyle P=4S$, where $\displaystyle S=5$

$\displaystyle P=4\times5=20$

Recall that the diagonals of a rhombus bisect each other and are perpendicular to one another.

In order to find the length of the side, we can use Pythagorean's theorem. The lengths of half of the diagonals are the legs, and the length of the side of the rhombus is the hypotenuse.

First, find the lengths of half of the diagonals.

$\displaystyle \frac{\text{Diagonal 1}}{2}=\frac{14}{2}=7$

$\displaystyle \frac{\text{Diagonal 2}}{2}=\frac{16}{2}=8$

Next, substitute these half diagonals as the legs in a right triangle using the Pythagorean theorem.

$\displaystyle 7^2+8^2=\text{side length}^2$

$\displaystyle \text{side length}^2=49+64=113$

$\displaystyle \text{side length}=\sqrt{113}$

Since the sides of a rhombus all have the same length, multiply the side length by $\displaystyle 4$ in order to find the perimeter.

$\displaystyle \text{Perimeter}=4(\text{side length})$

$\displaystyle \text{Perimeter}=4\sqrt{113}$

Solve and round to two decimal places.

 $\displaystyle \text{Perimeter}=42.52$

Recall that the diagonals of a rhombus bisect each other and are perpendicular to one another.

In order to find the length of the side, we can use Pythagorean's theorem. The lengths of half of the diagonals are the legs, and the length of the side of the rhombus is the hypotenuse.

First, find the lengths of half of the diagonals.

$\displaystyle \frac{\text{Diagonal 1}}{2}=\frac{8}{2}=4$

$\displaystyle \frac{\text{Diagonal 2}}{2}=\frac{12}{2}=6$

Next, substitute these half diagonals as the legs in a right triangle using the Pythagorean theorem.

$\displaystyle 4^2+6^2=\text{side length}^2$

$\displaystyle \text{side length}^2=16+36=52$

$\displaystyle \text{side length}=2\sqrt{13}$

Since the sides of a rhombus all have the same length, multiply the side length by $\displaystyle 4$ in order to find the perimeter.

$\displaystyle \text{Perimeter}=4(\text{side length})$

$\displaystyle \text{Perimeter}=4(2\sqrt{13})$

Solve and round to two decimal places.

$\displaystyle \text{Perimeter}=28.84$

Recall that the diagonals of a rhombus bisect each other and are perpendicular to one another.

In order to find the length of the side, we can use Pythagorean's theorem. The lengths of half of the diagonals are the legs, and the length of the side of the rhombus is the hypotenuse.

First, find the lengths of half of the diagonals.

$\displaystyle \frac{\text{Diagonal 1}}{2}=\frac{14}{2}=7$

$\displaystyle \frac{\text{Diagonal 2}}{2}=\frac{18}{2}=9$

Next, substitute these half diagonals as the legs in a right triangle using the Pythagorean theorem.

$\displaystyle 7^2+9^2=\text{side length}^2$

$\displaystyle \text{side length}^2=49+81=130$

$\displaystyle \text{side length}=\sqrt{130}$

Since the sides of a rhombus all have the same length, multiply the side length by $\displaystyle 4$ in order to find the perimeter.

$\displaystyle \text{Perimeter}=4(\text{side length})$

$\displaystyle \text{Perimeter}=4(\sqrt{130})$

Solve and round to two decimal places.

$\displaystyle \text{Perimeter}=45.61$

Recall that the diagonals of a rhombus bisect each other and are perpendicular to one another.

In order to find the length of the side, we can use Pythagorean's theorem. The lengths of half of the diagonals are the legs, and the length of the side of the rhombus is the hypotenuse.

First, find the lengths of half of the diagonals.

$\displaystyle \frac{\text{Diagonal 1}}{2}=\frac{12}{2}=6$

$\displaystyle \frac{\text{Diagonal 2}}{2}=\frac{16}{2}=8$

Next, substitute these half diagonals as the legs in a right triangle using the Pythagorean theorem.

$\displaystyle 6^2+8^2=\text{side length}^2$

$\displaystyle \text{side length}^2=36+64=100$

$\displaystyle \text{side length}=10$

Since the sides of a rhombus all have the same length, multiply the side length by $\displaystyle 4$ in order to find the perimeter.

$\displaystyle \text{Perimeter}=4(\text{side length})$

$\displaystyle \text{Perimeter}=4(10)$

Solve.

$\displaystyle \text{Perimeter}=40$

Recall that the diagonals of a rhombus bisect each other and are perpendicular to one another.

In order to find the length of the side, we can use Pythagorean's theorem. The lengths of half of the diagonals are the legs, and the length of the side of the rhombus is the hypotenuse.

First, find the lengths of half of the diagonals.

$\displaystyle \frac{\text{Diagonal 1}}{2}=\frac{24}{2}=12$

$\displaystyle \frac{\text{Diagonal 2}}{2}=\frac{26}{2}=13$

Next, substitute these half diagonals as the legs in a right triangle using the Pythagorean theorem.

$\displaystyle 12^2+13^2=\text{side length}^2$

$\displaystyle \text{side length}^2=144+169=313$

$\displaystyle \text{side length}=\sqrt{313}$

Since the sides of a rhombus all have the same length, multiply the side length by $\displaystyle 4$ in order to find the perimeter.

$\displaystyle \text{Perimeter}=4(\text{side length})$

$\displaystyle \text{Perimeter}=4(\sqrt{313})$

Solve and round to two decimal places.

$\displaystyle \text{Perimeter}=70.77$

Recall that the diagonals of a rhombus bisect each other and are perpendicular to one another.

In order to find the length of the side, we can use Pythagorean's theorem. The lengths of half of the diagonals are the legs, and the length of the side of the rhombus is the hypotenuse.

First, find the lengths of half of the diagonals.

$\displaystyle \frac{\text{Diagonal 1}}{2}=\frac{28}{2}=14$

$\displaystyle \frac{\text{Diagonal 2}}{2}=\frac{36}{2}=18$

Next, substitute these half diagonals as the legs in a right triangle using the Pythagorean theorem.

$\displaystyle 14^2+18^2=\text{side length}^2$

$\displaystyle \text{side length}^2=196+324=520$

$\displaystyle \text{side length}=2\sqrt{130}$

Since the sides of a rhombus all have the same length, multiply the side length by $\displaystyle 4$ in order to find the perimeter.

$\displaystyle \text{Perimeter}=4(\text{side length})$

$\displaystyle \text{Perimeter}=4(2\sqrt{130})$

Solve and round to two decimal places.

$\displaystyle \text{Perimeter}=91.21$