We are open Saturday and Sunday!

Call Now to Set Up Tutoring:

(888) 888-0446

Intermediate Geometry : Plane Geometry

Study concepts, example questions & explanations for Intermediate Geometry

Create An Account

All Intermediate Geometry Resources

8 Diagnostic Tests 250 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #831 : Plane Geometry

Find the perimeter of the regular hexagon.

Possible Answers:

112

132

Correct answer:

Explanation:

When all the opposite sides of a regular hexagon are connected, you should notice that six congruent equilateral triangles are created:

Thus, the diagonal of the hexagon is twice the length of a side.

$\text{Diagonal}=2(\text{side})$

$\text{Side}=\frac{\text{Diagonal}}{2}$

Plug in the given diagonal to find the length of a side.

$\text{Side}=\frac{22}{2}=11$

Now, recall how to find the perimeter of a regular hexagon:

$\text{Perimeter}=6(\text{side})$

Plug in the side length to find the perimeter.

$\text{Perimeter}=6(11)=66$

Report an Error

Example Question #832 : Plane Geometry

If the area of a regular hexagon is , what is the perimeter of the hexagon?

Possible Answers:

13.21

14.33

14.42

15.80

Correct answer:

14.42

Explanation:

Recall the formula to find the area of a regular hexagon:

$\text{Area}=\frac{3\sqrt3}{2}(\text{side})^2$

Rearrange the formula to solve for the side.

$(\text{side})^2=\text{Area}(\frac{2}{3\sqrt3})$

$\text{side}=\sqrt{\frac{2(\text{Area})}{3\sqrt3}}$

Now, recall how to find the perimeter of a regular hexagon:

$\text{Perimeter}=6(\text{side})$

Substitute in for the side to solve for the perimeter.

$\text{Perimeter}=6\sqrt{\frac{2(\text{Area})}{3\sqrt3}}$

Plug in the given area and use a calculator to find the perimeter.

$\text{Perimeter}=6\sqrt{\frac{2(15)}{3\sqrt3}}=14.42$

Make sure to round to the two places after the decimal.

Report an Error

Example Question #833 : Plane Geometry

If the area of a regular hexagon is $15\sqrt3$ , what is the perimeter of the hexagon?

Possible Answers:

16.58

19.82

18.97

20.51

Correct answer:

18.97

Explanation:

Recall the formula to find the area of a regular hexagon:

$\text{Area}=\frac{3\sqrt3}{2}(\text{side})^2$

Rearrange the formula to solve for the side.

$(\text{side})^2=\text{Area}(\frac{2}{3\sqrt3})$

$\text{side}=\sqrt{\frac{2(\text{Area})}{3\sqrt3}}$

Now, recall how to find the perimeter of a regular hexagon:

$\text{Perimeter}=6(\text{side})$

Substitute in for the side to solve for the perimeter.

$\text{Perimeter}=6\sqrt{\frac{2(\text{Area})}{3\sqrt3}}$

Plug in the given area and use a calculator to find the perimeter.

$\text{Perimeter}=6\sqrt{\frac{2(15\sqrt3)}{3\sqrt3}}=18.97$

Make sure to round to the two places after the decimal.

Report an Error

Example Question #834 : Plane Geometry

If the area of a regular hexagon is , what is the perimeter of the hexagon?

Possible Answers:

18.61

17.78

19.14

18.12

Correct answer:

18.61

Explanation:

Recall the formula to find the area of a regular hexagon:

$\text{Area}=\frac{3\sqrt3}{2}(\text{side})^2$

Rearrange the formula to solve for the side.

$(\text{side})^2=\text{Area}(\frac{2}{3\sqrt3})$

$\text{side}=\sqrt{\frac{2(\text{Area})}{3\sqrt3}}$

Now, recall how to find the perimeter of a regular hexagon:

$\text{Perimeter}=6(\text{side})$

Substitute in for the side to solve for the perimeter.

$\text{Perimeter}=6\sqrt{\frac{2(\text{Area})}{3\sqrt3}}$

Plug in the given area and use a calculator to find the perimeter.

$\text{Perimeter}=6\sqrt{\frac{2(25)}{3\sqrt3}}=18.61$

Make sure to round to the two places after the decimal.

Report an Error

Example Question #835 : Plane Geometry

If the area of a regular hexagon is , what is the perimeter of the hexagon?

Possible Answers:

32.31

28.88

29.01

22.95

Correct answer:

22.95

Explanation:

Recall the formula to find the area of a regular hexagon:

$\text{Area}=\frac{3\sqrt3}{2}(\text{side})^2$

Rearrange the formula to solve for the side.

$(\text{side})^2=\text{Area}(\frac{2}{3\sqrt3})$

$\text{side}=\sqrt{\frac{2(\text{Area})}{3\sqrt3}}$

Now, recall how to find the perimeter of a regular hexagon:

$\text{Perimeter}=6(\text{side})$

Substitute in for the side to solve for the perimeter.

$\text{Perimeter}=6\sqrt{\frac{2(\text{Area})}{3\sqrt3}}$

Plug in the given area and use a calculator to find the perimeter.

$\text{Perimeter}=6\sqrt{\frac{2(38)}{3\sqrt3}}=22.95$

Make sure to round to the two places after the decimal.

Report an Error

Example Question #836 : Plane Geometry

If the area of a regular hexagon is 178 , what is the perimeter of the hexagon?

Possible Answers:

49.66

45.51

51.09

41.29

Correct answer:

49.66

Explanation:

Recall the formula to find the area of a regular hexagon:

$\text{Area}=\frac{3\sqrt3}{2}(\text{side})^2$

Rearrange the formula to solve for the side.

$(\text{side})^2=\text{Area}(\frac{2}{3\sqrt3})$

$\text{side}=\sqrt{\frac{2(\text{Area})}{3\sqrt3}}$

Now, recall how to find the perimeter of a regular hexagon:

$\text{Perimeter}=6(\text{side})$

Substitute in for the side to solve for the perimeter.

$\text{Perimeter}=6\sqrt{\frac{2(\text{Area})}{3\sqrt3}}$

Plug in the given area and use a calculator to find the perimeter.

$\text{Perimeter}=6\sqrt{\frac{2(178)}{3\sqrt3}}=49.66$

Make sure to round to the two places after the decimal.

Report an Error

Example Question #837 : Plane Geometry

If the area of a regular hexagon is 109 , what is the perimeter of the hexagon?

Possible Answers:

41.12

35.77

32.01

38.86

Correct answer:

38.86

Explanation:

Recall the formula to find the area of a regular hexagon:

$\text{Area}=\frac{3\sqrt3}{2}(\text{side})^2$

Rearrange the formula to solve for the side.

$(\text{side})^2=\text{Area}(\frac{2}{3\sqrt3})$

$\text{side}=\sqrt{\frac{2(\text{Area})}{3\sqrt3}}$

Now, recall how to find the perimeter of a regular hexagon:

$\text{Perimeter}=6(\text{side})$

Substitute in for the side to solve for the perimeter.

$\text{Perimeter}=6\sqrt{\frac{2(\text{Area})}{3\sqrt3}}$

Plug in the given area and use a calculator to find the perimeter.

$\text{Perimeter}=6\sqrt{\frac{2(109)}{3\sqrt3}}=38.86$

Make sure to round to the two places after the decimal.

Report an Error

Example Question #838 : Plane Geometry

If the area of a regular hexagon is 120 , what is the perimeter of the hexagon?

Possible Answers:

50.69

40.78

45.12

39.51

Correct answer:

40.78

Explanation:

Recall the formula to find the area of a regular hexagon:

$\text{Area}=\frac{3\sqrt3}{2}(\text{side})^2$

Rearrange the formula to solve for the side.

$(\text{side})^2=\text{Area}(\frac{2}{3\sqrt3})$

$\text{side}=\sqrt{\frac{2(\text{Area})}{3\sqrt3}}$

Now, recall how to find the perimeter of a regular hexagon:

$\text{Perimeter}=6(\text{side})$

Substitute in for the side to solve for the perimeter.

$\text{Perimeter}=6\sqrt{\frac{2(\text{Area})}{3\sqrt3}}$

Plug in the given area and use a calculator to find the perimeter.

$\text{Perimeter}=6\sqrt{\frac{2(120)}{3\sqrt3}}=40.78$

Make sure to round to the two places after the decimal.

Report an Error

Example Question #839 : Plane Geometry

If the area of a regular hexagon is 219 , what is the perimeter of the hexagon?

Possible Answers:

81.24

55.09

61.20

56.69

Correct answer:

55.09

Explanation:

Recall the formula to find the area of a regular hexagon:

$\text{Area}=\frac{3\sqrt3}{2}(\text{side})^2$

Rearrange the formula to solve for the side.

$(\text{side})^2=\text{Area}(\frac{2}{3\sqrt3})$

$\text{side}=\sqrt{\frac{2(\text{Area})}{3\sqrt3}}$

Now, recall how to find the perimeter of a regular hexagon:

$\text{Perimeter}=6(\text{side})$

Substitute in for the side to solve for the perimeter.

$\text{Perimeter}=6\sqrt{\frac{2(\text{Area})}{3\sqrt3}}$

Plug in the given area and use a calculator to find the perimeter.

$\text{Perimeter}=6\sqrt{\frac{2(219)}{3\sqrt3}}=55.09$

Make sure to round to the two places after the decimal.

Report an Error

Example Question #840 : Plane Geometry

If the area of a regular hexagon is 456 , what is the perimeter of the hexagon?

Possible Answers:

74.13

75.39

79.49

71.21

Correct answer:

79.49

Explanation:

Recall the formula to find the area of a regular hexagon:

$\text{Area}=\frac{3\sqrt3}{2}(\text{side})^2$

Rearrange the formula to solve for the side.

$(\text{side})^2=\text{Area}(\frac{2}{3\sqrt3})$

$\text{side}=\sqrt{\frac{2(\text{Area})}{3\sqrt3}}$

Now, recall how to find the perimeter of a regular hexagon:

$\text{Perimeter}=6(\text{side})$

Substitute in for the side to solve for the perimeter.

$\text{Perimeter}=6\sqrt{\frac{2(\text{Area})}{3\sqrt3}}$

Plug in the given area and use a calculator to find the perimeter.

$\text{Perimeter}=6\sqrt{\frac{2(456)}{3\sqrt3}}=79.49$

Make sure to round to the two places after the decimal.

Report an Error

View Tutors

Ikshwaku
Certified Tutor

Rutgers University, Bachelor's (in progress), B.S Computer Science.

View Tutors

Cassandra
Certified Tutor

Eastern Michigan University, Bachelor of Education, Science Teacher Education.

View Tutors

Andrew
Certified Tutor

The University of Kansas, Bachelor of Science, Biochemistry.

All Intermediate Geometry Resources

8 Diagnostic Tests 250 Practice Tests Question of the Day Flashcards Learn by Concept

Popular Subjects

Math Tutors in Phoenix, GMAT Tutors in Denver, English Tutors in Denver, Statistics Tutors in Denver, English Tutors in Boston, Computer Science Tutors in Atlanta, Computer Science Tutors in Seattle, LSAT Tutors in Philadelphia, Chemistry Tutors in New York City, Calculus Tutors in Philadelphia

Popular Courses & Classes

Spanish Courses & Classes in San Francisco-Bay Area, LSAT Courses & Classes in Los Angeles, MCAT Courses & Classes in Washington DC, GMAT Courses & Classes in New York City, GMAT Courses & Classes in Seattle, SAT Courses & Classes in Boston, GMAT Courses & Classes in Denver, GMAT Courses & Classes in Atlanta, SAT Courses & Classes in Dallas Fort Worth, ISEE Courses & Classes in San Francisco-Bay Area

Popular Test Prep

MCAT Test Prep in Seattle, GMAT Test Prep in New York City, ISEE Test Prep in Los Angeles, ISEE Test Prep in Phoenix, GMAT Test Prep in Los Angeles, SSAT Test Prep in Boston, SSAT Test Prep in Seattle, ISEE Test Prep in Seattle, ACT Test Prep in Los Angeles, GMAT Test Prep in San Diego

DMCA Complaint

If you believe that content available by means of the Website (as defined in our Terms of Service) infringes one or more of your copyrights, please notify us by providing a written notice (“Infringement Notice”) containing the information described below to the designated agent listed below. If Varsity Tutors takes action in response to an Infringement Notice, it will make a good faith attempt to contact the party that made such content available by means of the most recent email address, if any, provided by such party to Varsity Tutors.

Your Infringement Notice may be forwarded to the party that made the content available or to third parties such as ChillingEffects.org.

Please be advised that you will be liable for damages (including costs and attorneys’ fees) if you materially misrepresent that a product or activity is infringing your copyrights. Thus, if you are not sure content located on or linked-to by the Website infringes your copyright, you should consider first contacting an attorney.

Please follow these steps to file a notice:

You must include the following:

A physical or electronic signature of the copyright owner or a person authorized to act on their behalf; An identification of the copyright claimed to have been infringed; A description of the nature and exact location of the content that you claim to infringe your copyright, in \ sufficient detail to permit Varsity Tutors to find and positively identify that content; for example we require a link to the specific question (not just the name of the question) that contains the content and a description of which specific portion of the question – an image, a link, the text, etc – your complaint refers to; Your name, address, telephone number and email address; and A statement by you: (a) that you believe in good faith that the use of the content that you claim to infringe your copyright is not authorized by law, or by the copyright owner or such owner’s agent; (b) that all of the information contained in your Infringement Notice is accurate, and (c) under penalty of perjury, that you are either the copyright owner or a person authorized to act on their behalf.

Send your complaint to our designated agent at:

Charles Cohn Varsity Tutors LLC
101 S. Hanley Rd, Suite 300
St. Louis, MO 63105

Or fill out the form below:

Do not fill in this field

Contact Information

* Full legal name

Company name

* Phone number

* Email address

Address

* Address1

Address2

* City

* State

* Zipcode

* Country

Complaint Details

* URL of copyrighted work (where your original material is located)

* Please describe the copyrighted work so that it may be easily identified

I am the owner, or an agent authorized to act on behalf of the owner of an exclusive right that is allegedly infringed.

I have a good faith belief that the use of the material in the manner complained of is not authorized by the copyright owner, its agent, or the law.

This notification is accurate.

I acknowledge that there may be adverse legal consequences for making false or bad faith allegations of copyright infringement by using this process.

* Signature (your digital signature is legally binding)

HIGH SCHOOL

GRADUATE SCHOOL

K-8

Search 50+ Tests

math tutoring

science tutoring

foreign languages

elementary tutoring

other

Search 350+ Subjects

Intermediate Geometry : Plane Geometry

Study concepts, example questions & explanations for Intermediate Geometry

All Intermediate Geometry Resources

Example Questions

Example Question #831 : Plane Geometry

Example Question #832 : Plane Geometry

Example Question #833 : Plane Geometry

Example Question #834 : Plane Geometry

Example Question #835 : Plane Geometry

Example Question #836 : Plane Geometry

Example Question #837 : Plane Geometry

Example Question #838 : Plane Geometry

Example Question #839 : Plane Geometry

Example Question #840 : Plane Geometry

All Intermediate Geometry Resources

Report an issue with this question

DMCA Complaint

Contact Information

Address

Complaint Details

Email address:
Your name:
Feedback: