The perimeter of a rectangle is equal to:

\(\displaystyle P=l+l+w+w=2l+2w\)

The only answer choice that provides dimensions for which the perimeter of a rectangle would be 54 inches is when there is a width of 10 inches a length of 17 inches.

\(\displaystyle 10+10+17+17= 54\)

Therefore, a width of 10 inches and length of 17 inches is the correct answer. 

The perimeter of a rectangle can be found by adding together all the sides. The formula is:

\(\displaystyle P=l+l+w+w=2l+2w\)

Use the given values for the length and the width to solve.

\(\displaystyle 2\text{in}+2\text{in}+6\text{in}+6\text{in}=16\text{in}\)

16 inches is the correct answer. 

The area of a rectangle is equal to the length times the width. 

\(\displaystyle A=l\times w\)

Here, we know that the area is 35, and the width is 5. We can fill in part of the equation with these values.

\(\displaystyle 35=l\times5\)

The only number that equals 35 when multiplied by 5 is 7.

\(\displaystyle 35\div5=7\)

\(\displaystyle 35=7\times5\)

7 is the correct answer. 

The perimeter of a rectangle can be found by adding together all the sides. This would give us:

\(\displaystyle 3+3+5+5=16\)

Therefore, 16 inches is the correct answer. 

\(\displaystyle \dpi{100} (30+30)+(15+15)\)

If the length of a rectangle is \(\displaystyle 2y\) and the width is \(\displaystyle x+4\), the perimeter is:

\(\displaystyle 2y+2y+x+4+x+4\)

\(\displaystyle =4y+2x+8\)

Now plug in \(\displaystyle y=7\) and \(\displaystyle x=6\):

\(\displaystyle =4\cdot7+2\cdot6+8\)

\(\displaystyle =28+12+8\)

\(\displaystyle =48\)

If the length of the rectangle is twice the value of its width, then if the width is equal to w, then the length is equal to 2w. 

Given that the perimeter of a rectangle is equal to the value of all the sides added together, the following equation would apply:

\(\displaystyle w+w+2w+2w=120\)

\(\displaystyle 6w=120\)

\(\displaystyle w=20\)

This means that the rectangle is \(\displaystyle 20\) inches wide.

Remember that the area of a rectangle is equal to its base times its height. If its area is \(\displaystyle 600\) and one side has a length of \(\displaystyle 15\), we can find the other side by dividing these:

\(\displaystyle Other Side = \frac{600}{15}=40\)

So, our rectangle looks like this:

The perimeter is easily calculated:

\(\displaystyle P = 40+40+15+15=110\)

The perimeter of a rectangle is very easy to solve.  Merely add up all the sides:

\(\displaystyle P = 128+128+71.3+71.3=398.6\)

If one side of the rectangle is \(\displaystyle 40\) and the other half of that, then the other side must be:

\(\displaystyle \frac{40}{2}=20\)

Our rectangle therefore looks like this:

The perimeter is calculated very easily.  Just sum up all the sides!

\(\displaystyle P = 40+40+20+20=120\)