ISEE Lower Level Math : ISEE Lower Level (grades 5-6) Mathematics Achievement

Study concepts, example questions & explanations for ISEE Lower Level Math

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Example Questions

Example Question #1001 : Isee Lower Level (Grades 5 6) Mathematics Achievement

A rectangle has a width of \displaystyle \frac{3}{4} foot and a length of \displaystyle \frac{1}{2} foot. Find the area of the rectangle. 

Possible Answers:

\displaystyle 5.5ft^2

\displaystyle 4ft^2

\displaystyle 127in^2

\displaystyle 27in^2

\displaystyle 54in^2

Correct answer:

\displaystyle 54in^2

Explanation:

To find the area of a rectangle apply the formula: 

\displaystyle Area= Width\times Length

This problem provides the measurements for both the width and length of the rectangle. However, to select the correct answer it's necessary to convert the width and length measurements from feet to inches. 

Since an inch is equal to \displaystyle \frac{1}{12} of \displaystyle 1 foot, the width and length conversions are: 

\displaystyle \frac{3}{4}=\frac{3}{4}\times \frac{3}{3}=\frac{9}{12}=9 in.

\displaystyle \frac{1}{2}=\frac{1}{2}\times \frac{6}{6}=\frac{6}{12}=6in. 

Thus, the solution is: 

\displaystyle Area=9\times6=54in^2

Example Question #1002 : Isee Lower Level (Grades 5 6) Mathematics Achievement

A rectangle has a width of \displaystyle 9 and a perimeter measurement of \displaystyle 34. Find the area of the rectangle.

Possible Answers:

\displaystyle 52 

\displaystyle 72 

\displaystyle 56 

\displaystyle 68 

\displaystyle 81 

Correct answer:

\displaystyle 72 

Explanation:

In this problem you are given the width and perimeter of the rectangle. However, to solve for the area of the rectangle you must first find the length of the rectangle. To do so, work backwards using the formula: 

\displaystyle Perimeter=2(W+L)

\displaystyle 34=2(9+L)

\displaystyle 34=18+2L

\displaystyle 2L=34-18=16

\displaystyle L=\frac{16}{2}=8

Now that you know the width and length of the rectangle, apply the area formula: 

\displaystyle Area=Width\times Length

\displaystyle Area=9\times 8= 72 

Example Question #1003 : Isee Lower Level (Grades 5 6) Mathematics Achievement

A rectangle has a width of \displaystyle 8 and a length of \displaystyle 25. Find the area of the rectangle.

Possible Answers:

\displaystyle 200 

\displaystyle 225 

\displaystyle 150 

\displaystyle 250 

\displaystyle 175 

Correct answer:

\displaystyle 200 

Explanation:

To find the area of a rectangle apply the formula: 

\displaystyle Area= Width\times Length

This problem provides the measurements for both the width and length of the rectangle. 

Thus, the solution is: 

\displaystyle Area=8\times25=200

Example Question #51 : Quadrilaterals

Find the area of a rectangle whose width is \displaystyle 2 and length is \displaystyle 4.

Possible Answers:

\displaystyle 8

\displaystyle 16

\displaystyle 32

\displaystyle 12

Correct answer:

\displaystyle 8

Explanation:

To solve, simply use the formula for the area of a rectangle. Thus,

\displaystyle A=w*l=2*4=8

Example Question #52 : Quadrilaterals

Find the area of a rectanlge whose length is \displaystyle 5 and width is \displaystyle 8.

Possible Answers:

\displaystyle 40

\displaystyle 20

\displaystyle 13

\displaystyle 26

Correct answer:

\displaystyle 40

Explanation:

To solve, simply use the formula for the area of a rectangle. Thus,

\displaystyle A=l*w=5*8=40

Example Question #53 : Quadrilaterals

A garden is 7 by 5 in size and you need to know how much fence is needed to surround it.  What is the perimeter?

Possible Answers:

\displaystyle 14

\displaystyle 12

\displaystyle 10

\displaystyle 24

\displaystyle 35

Correct answer:

\displaystyle 24

Explanation:

The perimeter is all four sides added together so you have two sides that are \displaystyle 7 and two that are \displaystyle 5.  So the answer would be \displaystyle 7+7+5+5=24.

Example Question #41 : Rectangles

A computer screen has a height of 9 inches and a width of 16 inches. Find its area.

Possible Answers:

\displaystyle 50in^2

\displaystyle 25in^2

\displaystyle 144in^2

\displaystyle 288in^2

Correct answer:

\displaystyle 144in^2

Explanation:

A computer screen has a height of 9 inches and a width of 16 inches. Find its area.

Area can be found by multiplying the length by the width. 

\displaystyle A=9*16=144

So our answer is 144

Example Question #55 : Quadrilaterals

A rectangle measures \displaystyle x  inches on its short side, and \displaystyle y + 1 inches on its long side.  What is its area?

Possible Answers:

\displaystyle 2xy

\displaystyle y + x

\displaystyle xy + 1

\displaystyle 2xy + 2

\displaystyle xy + x

Correct answer:

\displaystyle xy + x

Explanation:

To find the area of a rectangle, multiply the length of the long side by the length of the short side.  The best way to find the answer is:

\displaystyle x * (y + 1) = xy + x

Example Question #42 : Rectangles

A rectangle measures \displaystyle 7 inches on its short side, and \displaystyle u - 1 inches on its long side.  What is its area?

Possible Answers:

\displaystyle 7u - 1

\displaystyle 14u - 1

\displaystyle 7u - 7

\displaystyle 14u - 14

\displaystyle 7u^2 - 7

Correct answer:

\displaystyle 7u - 7

Explanation:

To find the area of a rectangle, multiply the length of the long side by the length of the short side.  The best way to find the answer is:

\displaystyle 7(u-1) = 7u - 7

Example Question #55 : Plane Geometry

A swimming pool is in the shape of a rectangle that is 20 feet wide and 30 feet long.  Find the area of the swimming pool.

Possible Answers:

\displaystyle 600\text{ft}^2

\displaystyle 50\text{ft}

\displaystyle 100\text{ft}

\displaystyle 50\text{ft}^2

\displaystyle 600\text{ft}

Correct answer:

\displaystyle 600\text{ft}^2

Explanation:

To find the area of a rectangle, we use the following formula:

\displaystyle \text{area of rectangle} = l \cdot w

where l is the length and is the width of the rectangle.  

 

In this case, we know the length of the swimming pool is 30 feet.  We also know the width of the pool is 20 feet.  So, we can substitute into the formula.  We get

\displaystyle \text{area of rectangle} = 30\text{ft} \cdot 20\text{ft}

\displaystyle \text{area of rectangle} = 600\text{ft}^2

 

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