To find the perimeter of a triangle, we add all of the side lengths together. 

\(\displaystyle 19+19+17=55\)

The area of a triangle is \(\displaystyle \frac{1}{2}*(base* height)\). We know that our base is 8 and our height is 3.

In this case, the equation is \(\displaystyle \frac{1}{2}*(8* 3)\). Now we can solve this equation.

\(\displaystyle \frac{1}{2}(24)\)

\(\displaystyle 12\)

To find the area of a triangle, we use \(\displaystyle \frac{1}{2}*(base* height)\). We know the height of the triangle is 10 and the base is 7.

\(\displaystyle \frac{1}{2}*(base*height)=\frac{1}{2}*(7*10)\)

\(\displaystyle \frac{1}{2}*(70)\)

\(\displaystyle 35\)

Use the formula for the area of a triangle

\(\displaystyle \frac{1}{2}bh\)

to solve this problem. Plug in and you get \(\displaystyle 14\ cm^{2}\).

The formula for finding the area of a triangle is \(\displaystyle \frac{1}{2}(base\times height)\). Multiply the base times the height first. \(\displaystyle 8\times6=48\). Then, either multiply  \(\displaystyle \frac{1}{2}\times\frac{48}{1}\) , or simply divide \(\displaystyle 48\div2\). Therefore the answer is \(\displaystyle 24ft^{2}\).

An area of a triangle is

\(\displaystyle \frac{1}{2}\times base\times height\)

In this case

\(\displaystyle \frac{1}{2}\times 4\times 7=14\)

First, you must remember the formula for the area of a triangle \(\displaystyle (A=\frac{1}{2}bh)\).

Plug in the given values: \(\displaystyle A=\frac{1}{2}(4)(12)\).

Multiply to get 24. Since this is area, the units must be sqaured. Therefore, your final answer is \(\displaystyle 24\ cm^2\).

There are several different ways to solve for the area of a right triangle. In this lesson, we will transform the right triangle into a rectangle, use the the simpler formula for area of a rectangle to solve for the new figure's area, and divide this area in half in order to solve for the area of the original figure.

First, let's transform the triangle into a rectangle:

Second, let's remember that the formula for area of a rectangle is  as follows:

\(\displaystyle A=l\times w\)

Substitute in our side lengths.

\(\displaystyle A=13\times 9\)

\(\displaystyle A=117\)

Last, notice that our triangle is exactly half the size of the rectangle that we made. This means that in order to solve for the area of the triangle we will need to take half of the area of the rectangle, or divide it by \(\displaystyle 2\).

\(\displaystyle 117\div 2= 58.5\textup{ in}^2\)

Thus, the area formula for a right triangle is as follows:

\(\displaystyle A=\frac{1}{2}(l\times w)\) or \(\displaystyle A=\frac{l\times w}{2}\)

There are several different ways to solve for the area of a right triangle. In this lesson, we will transform the right triangle into a rectangle, use the the simpler formula for area of a rectangle to solve for the new figure's area, and divide this area in half in order to solve for the area of the original figure.

First, let's transform the triangle into a rectangle:

Second, let's remember that the formula for area of a rectangle is  as follows:

\(\displaystyle A=l\times w\)

Substitute in our side lengths.

\(\displaystyle A=12\times 8\)

\(\displaystyle A=96\)

Last, notice that our triangle is exactly half the size of the rectangle that we made. This means that in order to solve for the area of the triangle we will need to take half of the area of the rectangle, or divide it by \(\displaystyle 2\).

\(\displaystyle 96\div 2= 48\textup{ in}^2\)

Thus, the area formula for a right triangle is as follows:

\(\displaystyle A=\frac{1}{2}(l\times w)\) or \(\displaystyle A=\frac{l\times w}{2}\)

There are several different ways to solve for the area of a right triangle. In this lesson, we will transform the right triangle into a rectangle, use the the simpler formula for area of a rectangle to solve for the new figure's area, and divide this area in half in order to solve for the area of the original figure.

First, let's transform the triangle into a rectangle:

Second, let's remember that the formula for area of a rectangle is  as follows:

\(\displaystyle A=l\times w\)

Substitute in our side lengths.

\(\displaystyle A=11\times 9\)

\(\displaystyle A=99\)

Last, notice that our triangle is exactly half the size of the rectangle that we made. This means that in order to solve for the area of the triangle we will need to take half of the area of the rectangle, or divide it by \(\displaystyle 2\).

\(\displaystyle 99\div 2= 49.5\textup{ in}^2\)

Thus, the area formula for a right triangle is as follows:

\(\displaystyle A=\frac{1}{2}(l\times w)\) or \(\displaystyle A=\frac{l\times w}{2}\)