Call Now to Set Up Tutoring:

(888) 888-0446

ISEE Middle Level Math : How to find the area of a rectangle

Study concepts, example questions & explanations for ISEE Middle Level Math

Create An Account

All ISEE Middle Level Math Resources

6 Diagnostic Tests 303 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #193 : Geometry

Use the following image to answer the question:

Rectangle3

Find the area of the rectangle.

Possible Answers:

$63\text{in}^2$ $\displaystyle 63\text{in}^2$

$54\text{in}^2$ $\displaystyle 54\text{in}^2$

$36\text{in}^2$ $\displaystyle 36\text{in}^2$

$15\text{in}^2$ $\displaystyle 15\text{in}^2$

$30\text{in}^2$ $\displaystyle 30\text{in}^2$

Correct answer:

$54\text{in}^2$ $\displaystyle 54\text{in}^2$

Explanation:

To find the area of a rectangle, we will use the following formula:

$\text{area of rectangle} = l \cdot w$ $\displaystyle \text{area of rectangle} = l \cdot w$

where l is the length and w is the width of the rectangle.

Now, let's look at the rectangle.

Rectangle3

We can see the length is 9 inches, and the width is 6 inches.

Knowing this, we can substitute into the formula. We get

$\text{area of rectangle} = 9\text{in} \cdot 6\text{in}$ $\displaystyle \text{area of rectangle} = 9\text{in} \cdot 6\text{in}$

$\text{area of rectangle} = 54\text{in}^2$ $\displaystyle \text{area of rectangle} = 54\text{in}^2$

Report an Error

Example Question #41 : How To Find The Area Of A Rectangle

Find the area of a rectangle with a width of 4in and a length that is three times the width.

Possible Answers:

$32\text{in}^2$ $\displaystyle 32\text{in}^2$

$36\text{in}^2$ $\displaystyle 36\text{in}^2$

$14\text{in}^2$ $\displaystyle 14\text{in}^2$

$48\text{in}^2$ $\displaystyle 48\text{in}^2$

$12\text{in}^2$ $\displaystyle 12\text{in}^2$

Correct answer:

$48\text{in}^2$ $\displaystyle 48\text{in}^2$

Explanation:

To find the area of a rectangle, we will use the following formula:

$\text{area of rectangle} = l \cdot w$ $\displaystyle \text{area of rectangle} = l \cdot w$

where l is the length and w is the width of the rectangle.

Now, we know the width of the rectangle is 4in. We also know the length of the rectangle is three times the width. Therefore, the length is 12in.

Knowing this, we can substitute into the formula. We get

$\text{area of rectangle} = 12\text{in} \cdot 4\text{in}$ $\displaystyle \text{area of rectangle} = 12\text{in} \cdot 4\text{in}$

$\text{area of rectangle} = 48\text{in}^2$ $\displaystyle \text{area of rectangle} = 48\text{in}^2$

Report an Error

Example Question #42 : How To Find The Area Of A Rectangle

Find the area of a rectangle with a width of 9cm and a length that is two times the width.

Possible Answers:

$162\text{cm}^2$ $\displaystyle 162\text{cm}^2$

$128\text{cm}^2$ $\displaystyle 128\text{cm}^2$

$18\text{cm}^2$ $\displaystyle 18\text{cm}^2$

$24\text{cm}^2$ $\displaystyle 24\text{cm}^2$

$32\text{cm}^2$ $\displaystyle 32\text{cm}^2$

Correct answer:

$162\text{cm}^2$ $\displaystyle 162\text{cm}^2$

Explanation:

To find the area of a rectangle, we will use the following formula:

$\text{area of rectangle} = l \cdot w$ $\displaystyle \text{area of rectangle} = l \cdot w$

where l is the length and w is the width of the rectangle.

Now, we know the width of the rectangle is 9cm. We also know the length of the rectangle is two times the width. Therefore, the length is 18cm.

Knowing this, we will substitute into the formula. We get

$\text{area of rectangle} = 18\text{cm} \cdot 9\text{cm}$ $\displaystyle \text{area of rectangle} = 18\text{cm} \cdot 9\text{cm}$

$\text{area of rectangle} = 162\text{cm}^2$ $\displaystyle \text{area of rectangle} = 162\text{cm}^2$

Report an Error

Example Question #201 : Geometry

Find the area of a rectangle with a width of 4in and a length that is three times the width.

Possible Answers:

$24\text{in}^2$ $\displaystyle 24\text{in}^2$

$32\text{in}^2$ $\displaystyle 32\text{in}^2$

$12\text{in}^2$ $\displaystyle 12\text{in}^2$

$17\text{in}^2$ $\displaystyle 17\text{in}^2$

$48\text{in}^2$ $\displaystyle 48\text{in}^2$

Correct answer:

$48\text{in}^2$ $\displaystyle 48\text{in}^2$

Explanation:

To find the area of a rectangle, we will use the following formula:

$\text{area of rectangle} = l \cdot w$ $\displaystyle \text{area of rectangle} = l \cdot w$

where l is the length and w is the width of the rectangle.

Now, we know the width of the rectangle is 4in. We also know the length is three times the width. Therefore, the length is 12in.

Knowing this, we can substitute into the formula. We get

$\text{area of rectangle} = 12\text{in} \cdot 4\text{in}$ $\displaystyle \text{area of rectangle} = 12\text{in} \cdot 4\text{in}$

$\text{area of rectangle} = 48\text{in}^2$ $\displaystyle \text{area of rectangle} = 48\text{in}^2$

Report an Error

Example Question #204 : Plane Geometry

Find the area of a rectangle with a width of 3cm and a length that is three times the width.

Possible Answers:

$9\text{cm}^2$ $\displaystyle 9\text{cm}^2$

$24\text{cm}^2$ $\displaystyle 24\text{cm}^2$

$16\text{cm}^2$ $\displaystyle 16\text{cm}^2$

$27\text{cm}^2$ $\displaystyle 27\text{cm}^2$

$12\text{cm}^2$ $\displaystyle 12\text{cm}^2$

Correct answer:

$27\text{cm}^2$ $\displaystyle 27\text{cm}^2$

Explanation:

To find the area of a rectangle, we will use the following formula:

$\text{area of rectangle} = l \cdot w$ $\displaystyle \text{area of rectangle} = l \cdot w$

where l is the length and w is the width of the rectangle.

So, we know the width of the rectangle is 3cm. We also know the length is three times the width. Therefore, the length is 9cm.

Knowing this, we can substitute into the formula. We get

$\text{area of rectangle} = 9\text{cm} \cdot 3\text{cm}$ $\displaystyle \text{area of rectangle} = 9\text{cm} \cdot 3\text{cm}$

$\text{area of rectangle} = 27\text{cm}^2$ $\displaystyle \text{area of rectangle} = 27\text{cm}^2$

Report an Error

Example Question #41 : Rectangles

Find the area of a rectangle with a length of 12cm and a width that is a quarter of the length.

Possible Answers:

$48\text{cm}^2$ $\displaystyle 48\text{cm}^2$

$36\text{cm}^2$ $\displaystyle 36\text{cm}^2$

$30\text{cm}^2$ $\displaystyle 30\text{cm}^2$

$16\text{cm}^2$ $\displaystyle 16\text{cm}^2$

$25\text{cm}^2$ $\displaystyle 25\text{cm}^2$

Correct answer:

$36\text{cm}^2$ $\displaystyle 36\text{cm}^2$

Explanation:

To find the area of a rectangle, we will use the following formula:

$\text{area of rectangle} = l \cdot w$ $\displaystyle \text{area of rectangle} = l \cdot w$

where l is the length and w is the width of the rectangle.

Now, we know the length of the rectangle is 12cm. We also know the width of the rectangle is a quarter of the length. To find the width, we will divide 12 by 4. Therefore, the width the 3cm.

Knowing this, we will substitute into the formula. We get

$\text{area of rectangle} = 12\text{cm} \cdot 3\text{cm}$ $\displaystyle \text{area of rectangle} = 12\text{cm} \cdot 3\text{cm}$

$\text{area of rectangle} = 36\text{cm}^2$ $\displaystyle \text{area of rectangle} = 36\text{cm}^2$

Report an Error

Example Question #206 : Plane Geometry

Find the area of a rectangle with a width of 8in and a length that is two times the width.

Possible Answers:

$20\text{in}^2$ $\displaystyle 20\text{in}^2$

$114\text{in}^2$ $\displaystyle 114\text{in}^2$

$48\text{in}^2$ $\displaystyle 48\text{in}^2$

$16\text{in}^2$ $\displaystyle 16\text{in}^2$

$128\text{in}^2$ $\displaystyle 128\text{in}^2$

Correct answer:

$128\text{in}^2$ $\displaystyle 128\text{in}^2$

Explanation:

To find the area of a rectangle, we will use the following formula:

$\text{area of rectangle} = l \cdot w$ $\displaystyle \text{area of rectangle} = l \cdot w$

where l is the length and w is the width of the rectangle.

Now, we know the width of the rectangle is 8in. We also know the length is two times the width. Therefore, the length is 16in.

Knowing this, we can substitute into the formula. We get

$\text{area of rectangle} = 16\text{in} \cdot 8\text{in}$ $\displaystyle \text{area of rectangle} = 16\text{in} \cdot 8\text{in}$

$\text{area of rectangle} = 128\text{in}^2$ $\displaystyle \text{area of rectangle} = 128\text{in}^2$

Report an Error

Example Question #207 : Plane Geometry

Find the area of a rectangle with a length of 24in and a width that is a third of the length.

Possible Answers:

$192\text{in}^2$ $\displaystyle 192\text{in}^2$

$72\text{in}^2$ $\displaystyle 72\text{in}^2$

$212\text{in}^2$ $\displaystyle 212\text{in}^2$

$156\text{in}^2$ $\displaystyle 156\text{in}^2$

$96\text{in}^2$ $\displaystyle 96\text{in}^2$

Correct answer:

$192\text{in}^2$ $\displaystyle 192\text{in}^2$

Explanation:

To find the area of a rectangle, we will use the following formula:

$A = l \cdot w$ $\displaystyle A = l \cdot w$

where l is the length and w is the width of the rectangle.

Now, we know the length of the rectangle is 24in. We also know the width is a third of the length. Therefore, the width is 8in.

Knowing this, we can substitute into the formula. We get

$A = 24\text{in} \cdot 8\text{in}$ $\displaystyle A = 24\text{in} \cdot 8\text{in}$

$A = 196\text{in}^2$ $\displaystyle A = 196\text{in}^2$

Report an Error

Example Question #43 : How To Find The Area Of A Rectangle

Find the area of a rectangle with a width of 6in and a length that is four times the width.

Possible Answers:

$96\text{in}^2$ $\displaystyle 96\text{in}^2$

$144\text{in}^2$ $\displaystyle 144\text{in}^2$

$121\text{in}^2$ $\displaystyle 121\text{in}^2$

$136\text{in}^2$ $\displaystyle 136\text{in}^2$

$48\text{in}^2$ $\displaystyle 48\text{in}^2$

Correct answer:

$144\text{in}^2$ $\displaystyle 144\text{in}^2$

Explanation:

To find the area of a rectangle, we will use the following formula:

$A = l \cdot w$ $\displaystyle A = l \cdot w$

where l is the length and w is the width of the rectangle.

Now, we know the width of the rectangle is 6in. We also know the length is four times the width. Therefore, the length is 24in.

Knowing this, we can substitute into the formula. We get

$A = 24\text{in} \cdot 6\text{in}$ $\displaystyle A = 24\text{in} \cdot 6\text{in}$

$A = 144\text{in}^2$ $\displaystyle A = 144\text{in}^2$

Report an Error

Example Question #44 : How To Find The Area Of A Rectangle

Find the area of a rectangle with a length of 21in and a width that is a third of the length.

Possible Answers:

$147\text{in}^2$ $\displaystyle 147\text{in}^2$

$49\text{in}^2$ $\displaystyle 49\text{in}^2$

$84\text{in}^2$ $\displaystyle 84\text{in}^2$

$63\text{in}^2$ $\displaystyle 63\text{in}^2$

$126\text{in}^2$ $\displaystyle 126\text{in}^2$

Correct answer:

$147\text{in}^2$ $\displaystyle 147\text{in}^2$

Explanation:

To find the area of a rectangle, we will use the following formula:

$A = l \cdot w$ $\displaystyle A = l \cdot w$

where l is the length and w is the width of the rectangle.

We know the length of the rectangle is 21in. We also know the width of the rectangle is a third of the length. Therefore, the width is 7in.

Knowing this, we can substitute into the formula. We get

$A = 21\text{in} \cdot 7\text{in}$ $\displaystyle A = 21\text{in} \cdot 7\text{in}$

$A = 147\text{in}^2$ $\displaystyle A = 147\text{in}^2$

Report an Error

View Tutors

Marie
Certified Tutor

Silliman University, Master of Science, Mathematics.

View Tutors

Srishaan
Certified Tutor

The University of Texas at Austin, Electrical Engineer, Electrical Engineering.

View Tutors

Jacqueline
Certified Tutor

Yale University, Bachelor of Science, German Studies. Cornell University, Master of Science, German Studies.

All ISEE Middle Level Math Resources

6 Diagnostic Tests 303 Practice Tests Question of the Day Flashcards Learn by Concept

Popular Subjects

Algebra Tutors in Seattle, LSAT Tutors in Houston, ACT Tutors in Seattle, Computer Science Tutors in Philadelphia, Biology Tutors in Denver, Calculus Tutors in Seattle, Physics Tutors in Philadelphia, ACT Tutors in Miami, Computer Science Tutors in Phoenix, Computer Science Tutors in New York City

Popular Courses & Classes

MCAT Courses & Classes in Washington DC, LSAT Courses & Classes in Washington DC, SSAT Courses & Classes in Denver, Spanish Courses & Classes in Miami, MCAT Courses & Classes in Chicago, MCAT Courses & Classes in Los Angeles, SSAT Courses & Classes in Phoenix, SAT Courses & Classes in San Diego, GMAT Courses & Classes in Dallas Fort Worth, Spanish Courses & Classes in New York City

Popular Test Prep

SAT Test Prep in Los Angeles, MCAT Test Prep in Boston, SSAT Test Prep in San Diego, MCAT Test Prep in Phoenix, GRE Test Prep in Philadelphia, SSAT Test Prep in Denver, SAT Test Prep in San Diego, LSAT Test Prep in San Diego, SAT Test Prep in Boston, LSAT Test Prep in Atlanta

DMCA Complaint

If you believe that content available by means of the Website (as defined in our Terms of Service) infringes one or more of your copyrights, please notify us by providing a written notice (“Infringement Notice”) containing the information described below to the designated agent listed below. If Varsity Tutors takes action in response to an Infringement Notice, it will make a good faith attempt to contact the party that made such content available by means of the most recent email address, if any, provided by such party to Varsity Tutors.

Your Infringement Notice may be forwarded to the party that made the content available or to third parties such as ChillingEffects.org.

Please be advised that you will be liable for damages (including costs and attorneys’ fees) if you materially misrepresent that a product or activity is infringing your copyrights. Thus, if you are not sure content located on or linked-to by the Website infringes your copyright, you should consider first contacting an attorney.

Please follow these steps to file a notice:

You must include the following:

A physical or electronic signature of the copyright owner or a person authorized to act on their behalf; An identification of the copyright claimed to have been infringed; A description of the nature and exact location of the content that you claim to infringe your copyright, in \ sufficient detail to permit Varsity Tutors to find and positively identify that content; for example we require a link to the specific question (not just the name of the question) that contains the content and a description of which specific portion of the question – an image, a link, the text, etc – your complaint refers to; Your name, address, telephone number and email address; and A statement by you: (a) that you believe in good faith that the use of the content that you claim to infringe your copyright is not authorized by law, or by the copyright owner or such owner’s agent; (b) that all of the information contained in your Infringement Notice is accurate, and (c) under penalty of perjury, that you are either the copyright owner or a person authorized to act on their behalf.

Send your complaint to our designated agent at:

Charles Cohn Varsity Tutors LLC
101 S. Hanley Rd, Suite 300
St. Louis, MO 63105

Or fill out the form below:

Do not fill in this field

Contact Information

* Full legal name

Company name

* Phone number

* Email address

Address

* Address1

Address2

* City

* State

* Zipcode

* Country

Complaint Details

* URL of copyrighted work (where your original material is located)

* Please describe the copyrighted work so that it may be easily identified

I am the owner, or an agent authorized to act on behalf of the owner of an exclusive right that is allegedly infringed.

I have a good faith belief that the use of the material in the manner complained of is not authorized by the copyright owner, its agent, or the law.

This notification is accurate.

I acknowledge that there may be adverse legal consequences for making false or bad faith allegations of copyright infringement by using this process.

* Signature (your digital signature is legally binding)

HIGH SCHOOL

GRADUATE SCHOOL

K-8

Search 50+ Tests

math tutoring

science tutoring

foreign languages

elementary tutoring

other

Search 350+ Subjects

ISEE Middle Level Math : How to find the area of a rectangle

Study concepts, example questions & explanations for ISEE Middle Level Math

All ISEE Middle Level Math Resources

Example Questions

Example Question #193 : Geometry

Example Question #41 : How To Find The Area Of A Rectangle

Example Question #42 : How To Find The Area Of A Rectangle

Example Question #201 : Geometry

Example Question #204 : Plane Geometry

Example Question #41 : Rectangles

Example Question #206 : Plane Geometry

Example Question #207 : Plane Geometry

Example Question #43 : How To Find The Area Of A Rectangle

Example Question #44 : How To Find The Area Of A Rectangle

All ISEE Middle Level Math Resources

Report an issue with this question

DMCA Complaint

Contact Information

Address

Complaint Details

Email address:
Your name:
Feedback: