In modulo 13 arithmetic, a number is congruent to the remainder of the divison of that number by 13. Since 

and 

,

, 

making the correct response 0.

By the order of operations, the operation within parentheses, which is addition, is carried out first; of the remaining two, multiplication precedes subtraction.

By the order of operations, in the absence of grouping symbols, exponentiation (squaring here) takes precedence, followed by, in order, multiplication and addition.

The algebraic way to solve this problem is to set up an equation, however, students can also solve using guess-and-check from the answer options.

When setting up an equation, sequential numbers are equal to , , , and . We know the sum of these sequential numbers to be 62, allowing us to set up the following equation:

Combine like-terms by reordering.

Subtract 6 from each side of the equation, then divide each side by 4 in order to isolate the variable.

In base five, each place value is a power of five, starting with 1 at the right, then, going to the left, 

To convert a base ten number to base five, divide the number by the next lowest power of five, then divide each remainder by progressively lower powers.

Since , we start by dividing 387 by 125, and continue accordingly:

The base five equivalent of 387 is 

If there are 3 students in each of Marie's art classes, and each student pays $15, this means that students are paying Marie $45 in total per class.

We can find the expense of the supplies by subtracting the amount Maria makes from the amount that the students pay her. The students pay her $45, but she only makes $35 per class.

The supplies must cost her $10.

Given that Joey's essay was 3 days late, he lost 15 points. This is because he loses 5 points for each day that it is late, and having turned it in 3 days late, lost 15 points. 

Joey's final score (68) will be equal to his original grade, minus the penalty.

If we add 15 to the score that ultimately received, the sum is 83.

If Joey had turned his essay in on time, he would have earned a score of 83. 

In base five, each place value is a power of five, starting with 1 at the right, then, going to the left, 

 can be calculated in base ten as

.

On Wednesday, Annie ran  miles.

She ran  more miles on Thursday than she did on Wednesday. Therefore, she ran  miles on Thursday.

On Friday, she ran a distance in miles that was  longer than the distance she ran on Wednesday.  of  miles is  mile. (You can figure this out by realizing that since  of  is  and  is half of ,  of  must be half of , which is .) , so Annie ran  miles on Friday.

On Saturday, she ran a distance in miles that was  longer than the distance she ran on Thursday. of  is . , so Annie ran  miles on Saturday. 

The sum of these distances is equal to

Annie ran  miles in total Wednesday through Saturday.

If Bob drove  miles, and Anita drove twice as many miles as Bob, then Anita drove  miles; therefore, the sum of the miles that they drove together would be 3J. 

Thus, the correct answer is .