Recall that the mean is the same as the average.

Let \(\displaystyle x\) be the smallest number in this set. Since these are consecutive even numbers, the other numbers can be represented as \(\displaystyle x+2, x+4, x+6, \text{ and }x+8\).

Now, find the average of these numbers, and solve for \(\displaystyle x\).

\(\displaystyle \text{Mean}=\frac{x+x+2+x+4+x+6+x+8}{5}=58\)

\(\displaystyle 5x+20=290\)

\(\displaystyle 5x=270\)

\(\displaystyle x=54\)

The smallest number is \(\displaystyle 54\).

To find the mean of a data set, we will use the following formula:

\(\displaystyle \text{mean} = \frac{\text{sum of numbers within set}}{\text{number of numbers within set}}\)

Now, given the following set of Math test scores

\(\displaystyle 90, 81, 98, 85,83, 92, 95, 77,82\)

we can calculate the following:

\(\displaystyle \text{sum of numbers within set} = 90+81+98+85+83+92+95+77+82\)

\(\displaystyle \text{sum of numbers within set} = 783\)

Now, we will calculate the following:

\(\displaystyle \text{number of numbers within set} = 9\)

because there are 9 numbers in the set.

Knowing all of this, we can substitute into the formula.  We get

\(\displaystyle \text{mean} = \frac{783}{9}\)

\(\displaystyle \text{mean} = 87\)

Therefore, the mean score of the Math exams is 87.

Find the mean of the following data set:

\(\displaystyle 44,65,12,33,99,12,55,44,65,12,79\)

Find the mean by first summing up our terms, then dividing by the number of terms we have.

In this case, we have 11 terms, so our denominator is 11

\(\displaystyle \frac{44+65+12+33+99+12+55+44+65+12+79}{11}=\frac{521}{11}\approx47\)

So, our mean is 47

Recall that the mean is the same as the average.

To find the average, add up all the terms that are given and divide by the number of terms there are.

\(\displaystyle \text{Mean}=\frac{\text{Sum of all terms}}{\text{Number of all terms}}\)

\(\displaystyle \text{Mean}=\frac{92+80+88+94+95+97}{6}=91\)

His mean score is a \(\displaystyle 91\).

Recall that the mean is another way of saying "average."

To find the average, we will need to find the total number of siblings the class has, then divide by the number of students in the class.

\(\displaystyle \\ \text{Mean}=\frac{0+0+0+0+0+1+1+1+1+1+1+1+1+1+2+2+2+2+3+3}{20} \\\text{Mean}=\frac{23}{20}=1.15\)

Thus, the mean number of siblings the class has is \(\displaystyle 1.15\)

Remember that the mean is the same as the average.

Let \(\displaystyle x\) be the score he needs on his fifth test. Since we already know what his average needs to be, we can set up the following equation:

\(\displaystyle \frac{65+58+69+58+x}{5}=70\)

Solve for \(\displaystyle x\).

\(\displaystyle 250+x=350\)

\(\displaystyle x=100\)

Michael must score \(\displaystyle 100\) on his next test to pass.

Recall that the mean is just the same as the average. Let \(\displaystyle x\) be the number of points she must score in the last game. We can then write the following equation:

\(\displaystyle \text{Mean}=\frac{14+20+12+9+10+8+12+x}{8}=15\)

Now, solve for \(\displaystyle x\).

\(\displaystyle 85+x=120\)

\(\displaystyle x=35\)

Joanna must score \(\displaystyle 35\) points in the next game to make the all-star team.

To find the mean of a data set, we will use the following formula:

\(\displaystyle \text{mean} = \frac{\text{sum of numbers within set}}{\text{number of numbers within set}}\)

Now, given the set of test scores, we can calculate the following:

\(\displaystyle \text{sum of numbers within set} = 99+95+84+99+81+97+79+86\)

\(\displaystyle \text{sum of numbers within set} = 720\)

Now, we will calculate the following:

\(\displaystyle \text{number of numbers within set} = 8\)

because there are 8 numbers in the set.

Knowing all of this, we can substitute into the formula.  We get

\(\displaystyle \text{mean} = \frac{720}{8}\)

\(\displaystyle \text{mean} = 90\)

Therefore, the mean score of the tests is 90.