Arrange the eight known values from least to greatest.

$\displaystyle \left \{ 24, 27, 34, 37, 50, 57,61, 63\right \}$

For $\displaystyle 50$ to be the median of the nine elements, it muct be the fifth-greatest, This happens if $\displaystyle N \geq 50$.

The median of this nine-element set is its fifth-highest element. Of the eight known elements, the fourth-highest and fifth-highest elements are both 20. Regardless of the value of $\displaystyle N$, 20 is the fifth-highest element of the nine.

The "stem" of this data set represents the tens digits of the data values; the "leaves" represent the units digits. 

There are 22 elements, so the median is the arithmetic mean of the eleventh- and twelfth-highest elements, which are 64 and 65, the middle two "leaves". Their mean is $\displaystyle \left (64 + 65 \right )\div 2 = 64.5$.

To determine the median of a set of numbers, you first need to order them from least to greatest:

$\displaystyle 79, 80, 81, 88, 93, 93, 95$

Since there is an odd number of scores, the median is the score that falls exactly in the middle of the new list. Thus, the median is 88.

To determine the median of a set of numbers, you first need to order them from least to greatest:

$\displaystyle 27, 34, 36, 44, 51, 55$

Since there is an even amount of numbers, the median is determined by finding the average of the two numbers in the middle - 36 and 44.

$\displaystyle 36+44 = 80 \div 2 = 40$

Thus, the median is 40.

The median is the center number when the data points are listed in ascending or descending order. To find the median, reorder the values in numerical order:

$\displaystyle 2,3,4,7,14$

In this problem, the middle number, or median, is the third number, which is $\displaystyle 4.$

The first step towards solving for the set, $\displaystyle \left ( 5.45, 3.12, 5.7,9.86, 14.78, 3.35\right )$ is to reorder the numbers from smallest to largest. 

This gives us:

$\displaystyle \left ( 3.12,3.35, 5.45, 5.7,9.86, 14.78\right )$

The median is equal to middle number in s a set. In since this set has 6 numbers, which is even, the average of the middle two numbers is the mean. The average can be found using the equation below:

$\displaystyle \frac{5.45+5.7}{2}$

$\displaystyle \frac{11.15}{2}$

$\displaystyle 5.575$

Find the median of the following data set:

$\displaystyle 45,67,12,34,55,88,67,343,49$

Begin by putting your numbers in increasing order:

$\displaystyle 12,34,45,49,55,67,67,88,343$

Next, identify the median by choosing the middle value:

$\displaystyle 12,34,45,49,{\color{Green} 55},67,67,88,343$

So, our answer is 55

Find the median of the following data set:

$\displaystyle 5,76,12,34,55,89,76,109,67,33,9$

Let's begin by rearranging our terms from least to greatest:

$\displaystyle 5,9,12,33,34,55,67,76,76,89,109$

Now, the median will be the middle term:

$\displaystyle 5,9,12,33,34,{\color{DarkOrange} 55},67,76,76,89,109$

Find the median of the following data set:

$\displaystyle 34,56,76,12,33,43,98,99,77,93,33$

First, let's put our terms in increasing order:

$\displaystyle 12,33,33,34,43,56,76,77,93,98,99$

Now, we can find our median simply by choosing the middle term.

$\displaystyle 12,33,33,34,43,{\color{Blue} 56},76,77,93,98,99$

So, 56 is our median.