All MCAT Physical Resources
Example Questions
Example Question #12 : Forces
A body with mass is situated meters from a second body with a mass of . What will be the effect on gravitational attraction of moving one body so that it is only meters from the other body?
It will increase by a factor of
It will decrease by a factor of
It will increase by a factor of
It will decrease by a factor of
It will increase by a factor of
It will increase by a factor of
Gravity is essentially a property of mass, and the force of gravitational attraction between two bodies is given by the formula:
In our scenario, the masses remain the same, and of course is a constant, so the only thing that changes is the denominator.
Example Question #12 : Gre Subject Test: Physics
Using Newton's Law of Universal Gravitation equation, which of the following expressions is equal to the local gravitational acceleration on Earth?
On earth, .
The law of universal gravitation is equal to .
We can set these equations equal to one another and isolate by dividing both sides by , the mass of an object on Earth.
Using the mass of the Earth, the radius of the Earth, and the gravitational constant, , we get a value of approximately if we solve for .
Example Question #21 : Forces
Which of the following must be true for a block to be considered weightless?
The block is being constantly accelerated downward at
The block is being constantly accelerated downward at
The block is being constantly accelerated downward at
The object can never be considered weightless
The block is being constantly accelerated upward at
The block is being constantly accelerated downward at
One way an object can be considered "weightless," is if it is accelerating downward at the same rate that it would be if it were free falling. This is why objects in an elevator whose cable had been cut would be "weightless." Therefore the answer is just for the block to be accelerating in the same magnitude and direction as the acceleration due to gravity, which is
Example Question #381 : Mcat Physical Sciences
Which of the following changes would increase a satellite's orbital speed?
Decrease orbital radius
Increase the mass of the satellite
Decrease the mass of the satellite
Decrease the mass of the Earth
Increase orbital radius
Decrease orbital radius
We know , and the force of gravity is:
Also, the equation for uniform circular motion, such as a satellite in orbit is:
Set and substitute the acceleration due to circular motion into the equation. Solve for velocity.
This indicates that the only variables that affect the orbital speed are orbital radius and the mass of the Earth.
Example Question #383 : Mcat Physical Sciences
A block lies upon a frictionless surface. A string is attached to the right side of the block, passed over a pulley, and then attached to a mass suspended by the string. When the block is held still, what is the tension in the string?
The block cannot provide any frictional force to the left because it is resting on a frictionless table. Whether the block is allowed to move or not, the tension force in the string is all generated by the suspended mass. The force in the string is equal and opposite to the gravitational force acting on the suspended mass.
The system is in equilibrium when no parts are in motion. Alternatively stated, the upward tension in the string is equal and opposite to the downwards force on the mass. If the block is not allowed to move as more mass is added, at some point the tensile force in the string will exceed its mechanical limits, and the string will break.
Example Question #203 : Newtonian Mechanics And Motion
What is the tension in a rope that is used to pull a box straight upwards with an acceleration of ?
For the problem we need to understand Newton's second law: . The net upward forces and net downward forces must equal the product of mass and acceleration. Since the box is traveling upwards with an acceleration of 1m/s2 we can indicate upward forces as positive and downward forces as negative. Indicating T as tension and Fg as the weight of the box, we can find the value of tension with the equation .
Example Question #3 : Gravity And Weight
Planet X has mass and radius , and the gravitational acceleration on its surface is . What is the gravitational acceleration at the location of a satellite orbiting at a distance from the surface of planet X?
Gravitational acceleration is related to distance via the equation:
is the gravitational constant, is the mass of the attracting object, and is the distance from its center.
In this case, the initial distance (on the surface) is from the center of planet X, and the distance of the satellite is from the center. We know that gravitational acceleration is proportional to the distance squared, and we know the acceleration at the surface. Using these values, we can solve for the acceleration on the satellite.
By expanding the equation for the acceleration on the satellite, we can see that it is equal to one-sixteenth the acceleration at the surface, based on our original equation. Substitute the value of the surface acceleration to get the final answer.
Example Question #1 : Gravity And Weight
A ball is thrown vertically with an initial velocity, , and returns to its original position after time . How would the value of be affected if the ball were thrown in the same manner on the moon, where gravitational acceleration is one-sixth the gravitational acceleration on Earth?
Increase by a factor of
Increase by a factor of six
Decrease by a factor of
Decrease by a factor of six
Increase by a factor of six
To solve this question, we will need to use the equation for acceleration:
In this case, the initial velocity will be equal to the final velocity, but opposite in magnitude. The initial velocity is in the upward direction, while the final velocity is downward.
Plug this value into the equation for acceleration.
The velocity value is constant, regardless of the planet. Substitute the acceleration for each planet to determine the change in the time variable.
We can see that the time of flight on the moon is equal to six times the time of flight on Earth.
Example Question #21 : Forces
A hypothetical planet has a radius equal to twice that of Earth, with the same mass as Earth. How much would a person weigh on the surface of this hypothetical planet if they weighed 1000N on earth?
The force due to gravity on any object can be given by the equation below.
is the gravitational constant, is the mass of the earth, is the mass of the object, and is the distance between the center of each object.
In our question, the only value to change is the radius of the new planet; both masses and remain constant. The effect of doubling the radius on the force is given below.
The person's weight on the new planet would be one-fourth their weight on Earth.
Example Question #381 : Mcat Physical Sciences
An astronaut standing on a scale on the moon observes that he weighs . If the acceleration due to gravity on the moon's is one-sixth of its value on Earth's surface, what is the astronaut's mass on the earth?
To relate force and mass, we use Newton's second law:
We are given his weight (force) on the moon, and we are told the relative gravitational acceleration on the moon. Using these values, we can find the astronaut's mass.
Since mass is the same regardless of gravitational acceleration, this is the same as the astronaut's mass on the earth.
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